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Aptitude - Numbers

Exercise : Numbers - General Questions
116.
The sum of first 45 natural numbers is:
1035
1280
2070
2140
Answer: Option
Explanation:

Let Sn = (1 + 2 + 3 + ... + 45)

This is an A.P. in which a = 1, d = 1, n = 45 and l = 45

Sn = n (a + l) = 45 x (1 + 45)   = (45 x 23)   = 1035
2 2

Required sum = 1035.

117.
666 ÷ 6 ÷ 3 = ?
37
333
111
84
None of these
Answer: Option
Explanation:
Given Exp. = 666 x 1 x 1 = 37.
6 3
118.
The sum of all two digit numbers divisible by 5 is:
1035
1245
1230
945
None of these
Answer: Option
Explanation:

Required numbers are 10, 15, 20, 25, ..., 95

This is an A.P. in which a = 10, d = 5 and l = 95.

tn = 95       a + (n - 1)d = 95

10 + (n - 1) x 5 = 95

(n - 1) x 5 = 85

(n - 1) = 17

n = 18

Requuired Sum = n (a + l) = 18 x (10 + 95)   = (9 x 105)   = 945.
2 2

119.
The difference between the place values of two sevens in the numeral 69758472 is
0
6993
699930
None of these
Answer: Option
Explanation:
Required difference = (700000 - 70) = 699930
120.
On dividing a number by 68, we get 269 as quotient and 0 as remainder. On dividing the same number by 67, what will the remainder ?
0
1
2
3
Answer: Option
Explanation:
Number = 269 x 68 + 0 = 18292

 67) 18292 (273
     134
     ----
      489
      469
      ----
       202
       201
       ---
         1
       ---
       
Therefore, Required remainder = 1
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