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Aptitude - Logarithm - Discussion

Discussion Forum : Logarithm - General Questions (Q.No. 2)
Logarithm
2.
If log 2 = 0.3010 and log 3 = 0.4771, the value of log5 512 is:
2.870
2.967
3.876
3.912
Answer: Option
Explanation:
log5 512
= log 512
log 5
= log 29
log (10/2)
= 9 log 2
log 10 - log 2
= (9 x 0.3010)
1 - 0.3010
= 2.709
0.699
= 2709
699
= 3.876
Discussion:
71 comments Page 5 of 8.
Sukh Singh said:   9 years ago
How to use Log3?

Please explain me.
ArBan said:   9 years ago
How can log 10 be 1? It can only be 1 if the base is 10. If I remember the formula correctly then the base can be anything and is generally a random constant term (a, b etc. ). If we follow the same logic then the answer is most definitely wrong as per my calculations.

CAN ANYONE EXPLAIN THE CORRECT PROCESS?
Michael Essandoh said:   9 years ago
Please solve this, given that log 9 = 0.9542 and log 6 = 0.7781, find the value of log base 10 of 225.
Saffee2 said:   9 years ago
@Michael Essandoh.

Is it 2.5104?
Anu said:   9 years ago
How to subtract 1 - 0.3010 =? Explain.
Shreyash said:   9 years ago
@Arban.

Whenever base is not mentioned, it is taken as 10.
So, log 10 =1 (as the base here is 10).
Mansi said:   9 years ago
Here Log2 =0.3010.
Then, Find log 5.
Mushariq said:   9 years ago
Nice explanation, thank you for all your solution.
Ayesha said:   8 years ago
If log2=0.3010 then find the value of log32. Can someone solve this?
Siddharth said:   8 years ago
@Ayesha.

log32 = log(2^5)= 5log2=5*0.3010= 1.505.
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