Aptitude - Logarithm - Discussion
Discussion Forum : Logarithm - General Questions (Q.No. 2)
2.
If log 2 = 0.3010 and log 3 = 0.4771, the value of log5 512 is:
Answer: Option
Explanation:
log5 512 |
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= 3.876 |
Discussion:
71 comments Page 2 of 8.
Vigneshraj said:
1 decade ago
@jeromy.
Click the impotant formulas link there you can see 7th formula using that formula we divide log512 by log5.
Click the impotant formulas link there you can see 7th formula using that formula we divide log512 by log5.
Lekan said:
1 decade ago
Please who can solve this log10 2 = 0.3010?
K.rajeshreddy said:
1 decade ago
log5512 = log512/log5 = 9log2/log5.
= 9log2/log3+log2.
= 9*0.3010/0.4771+0.3010.
I think this is this the correct procedure as log 2 and log3 values are given. Why we need to go for log 10/2?
= 9log2/log3+log2.
= 9*0.3010/0.4771+0.3010.
I think this is this the correct procedure as log 2 and log3 values are given. Why we need to go for log 10/2?
Apoorva said:
1 decade ago
Why is it only 2?
Nirav said:
1 decade ago
Why are they dividing log 512 by log 5?
Is this a formula?
Is this a formula?
Nagdish kewat said:
1 decade ago
What is the answer of log3(log2(log3t)) =1 t=?
Raj kumar said:
1 decade ago
@Nirav.
log512/log5 = 9log2/log(2+3) = 9log2/(log2*log3).
= 9*.3010/(.3010*.4771).
= 9/.4771 >18.
log512/log5 = 9log2/log(2+3) = 9log2/(log2*log3).
= 9*.3010/(.3010*.4771).
= 9/.4771 >18.
Saurabh said:
1 decade ago
Why are they dividing log 512 by log 5?
Vipin Mishra said:
1 decade ago
Formula:
log a x = log x/log a.
log 5 512 = log 512/log 5.
log a x = log x/log a.
log 5 512 = log 512/log 5.
Goose said:
1 decade ago
log(75) = log(70+5).
= log(7*10)+(2+3).
= [log(7)+log(10)]*log(2)*log(3).
= [0.8541+1]*0.3010*0.4771.
= 1.8451*0.3010*0.4771.
= 0.1557.
= log(7*10)+(2+3).
= [log(7)+log(10)]*log(2)*log(3).
= [0.8541+1]*0.3010*0.4771.
= 1.8451*0.3010*0.4771.
= 0.1557.
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