Aptitude - Decimal Fraction - Discussion
Discussion Forum : Decimal Fraction - General Questions (Q.No. 3)
3.
| The value of | (0.96)3 - (0.1)3 | is: |
| (0.96)2 + 0.096 + (0.1)2 |
Answer: Option
Explanation:
| Given expression |
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Discussion:
22 comments Page 2 of 3.
Sachin pal said:
9 years ago
As we have formula a3-b3 = (a-b)(a2+ab+b2).
Now,
(a2+ab+b2) is cancel out and we have (a-b)only.
So, .96 -.1 = .86.
Now,
(a2+ab+b2) is cancel out and we have (a-b)only.
So, .96 -.1 = .86.
(2)
Anandhan said:
9 years ago
But (a + b)3 is = (a - b) (a2 + ab + b2). Here a3 + b3 so how it can be possible? Both are different, Right?
Nathi said:
1 decade ago
Hi Friends,
Formula
(a^3-b^3) = (a-b)(a^2+ab+b^2)/a^2+ab+b^2
So cancel thes and we get (a-b).
Formula
(a^3-b^3) = (a-b)(a^2+ab+b^2)/a^2+ab+b^2
So cancel thes and we get (a-b).
M.azam said:
1 decade ago
@Vineash.
The formula of a^3-b^3 = (a-b)(a^2+ab+b^2).
Hence a^3-b^3/a^2+ab+b^2 = a-b.
The formula of a^3-b^3 = (a-b)(a^2+ab+b^2).
Hence a^3-b^3/a^2+ab+b^2 = a-b.
Sadhuru said:
8 years ago
How to solve ab? Please explain it for me.
Akshu said:
1 decade ago
Can tell me clearly please I didn't get.
Vignesh said:
1 decade ago
Please tell how (a-b) is possible
Gokil said:
1 decade ago
How (a-b) possible? please tell.
Jagga said:
4 years ago
a^3-b^3 = (a-b)(a^2+2ab+b^2).
(2)
Bhumi said:
1 decade ago
How is it possible a-b?
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