Aptitude - Decimal Fraction - Discussion
Discussion Forum : Decimal Fraction - General Questions (Q.No. 4)
4.
| The value of | 0.1 x 0.1 x 0.1 + 0.02 x 0.02 x 0.02 | is: |
| 0.2 x 0.2 x 0.2 + 0.04 x 0.04 x 0.04 |
Answer: Option
Explanation:
| Given expression = | (0.1)3 + (0.02)3 | = | 1 | = 0.125 |
| 23 [(0.1)3 + (0.02)3] | 8 |
Discussion:
34 comments Page 4 of 4.
Bangaru Sathish said:
1 decade ago
Given problem = [(0.1)^3+(0.02)^3]/[(0.2)^3+(0.04)^3].
Then [(0.1)^3+(0.02)^3]/[(2(0.1))^3+(2(0.02))^3.
Then [(0.1)^3+(0.02)^3]/2^3[(0.1)^3+(0.02)^3].
Then 1/2^3.
Finally 1/8.
Then [(0.1)^3+(0.02)^3]/[(2(0.1))^3+(2(0.02))^3.
Then [(0.1)^3+(0.02)^3]/2^3[(0.1)^3+(0.02)^3].
Then 1/2^3.
Finally 1/8.
SIDHARTHAN M said:
9 years ago
How to convert .008 to 1 and .000064 to 8?
Hema said:
9 years ago
Here
2 * (0.1) = 0.2
2 * (0.02) = 0.04
Then the question we get;
(0.1)^3 + (0.02)^3 / (2(0.1))^3 + (2(0.02))^3.
Then the denominator we can take 2 in common,
(0.1)^3 + (0.02)^3 / 2^3[(0.1)^3 + (0.02)^3].
Then, we can get 1/2^3.
We know 1/8, So we get the answer is 0.125.
2 * (0.1) = 0.2
2 * (0.02) = 0.04
Then the question we get;
(0.1)^3 + (0.02)^3 / (2(0.1))^3 + (2(0.02))^3.
Then the denominator we can take 2 in common,
(0.1)^3 + (0.02)^3 / 2^3[(0.1)^3 + (0.02)^3].
Then, we can get 1/2^3.
We know 1/8, So we get the answer is 0.125.
Ezra mike said:
9 years ago
Simple to learn with the given explanations. Thanks.
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