Aptitude - Decimal Fraction - Discussion
Discussion Forum : Decimal Fraction - General Questions (Q.No. 4)
4.
| The value of | 0.1 x 0.1 x 0.1 + 0.02 x 0.02 x 0.02 | is: |
| 0.2 x 0.2 x 0.2 + 0.04 x 0.04 x 0.04 |
Answer: Option
Explanation:
| Given expression = | (0.1)3 + (0.02)3 | = | 1 | = 0.125 |
| 23 [(0.1)3 + (0.02)3] | 8 |
Discussion:
36 comments Page 3 of 4.
Sarada said:
1 decade ago
How can you common 2^3 from denominator?
Sukeshani Kadam said:
1 decade ago
I don't understand this proble. Please explain
Vikram grandhi143 said:
1 decade ago
It is just take the common of 0.2 on denominator.
Prasanna said:
1 decade ago
It simple guys.
Just divide (0.1) hole power 3 and (0.02) hole power 3 and take cube of 2 so we get the answer 1/8.
Just divide (0.1) hole power 3 and (0.02) hole power 3 and take cube of 2 so we get the answer 1/8.
Manjula said:
1 decade ago
Hai friends,
They just take 2 common in denominator. (0.2)^3+(0.4)^3 they take 2^3 common. So, 2^3(0.1)^3+(0.2)^3.It is cancelled. 1/8 = 0.125.
They just take 2 common in denominator. (0.2)^3+(0.4)^3 they take 2^3 common. So, 2^3(0.1)^3+(0.2)^3.It is cancelled. 1/8 = 0.125.
Maulik said:
1 decade ago
If you calculate with calculator than is the answer is same ?
Can anybody explain it in simple way.
Can anybody explain it in simple way.
Chandu said:
1 decade ago
First answer is good one we must take the common 2 so we can get the answer essay.
Manuj said:
1 decade ago
Can anyone explain the numerator?
Acharya said:
1 decade ago
How is it explain please.
Sankar said:
1 decade ago
We know the formula, (a^m x b^m) = (ab)^m. In the denominator, take 2^3 common & apply above formula.
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers