Aptitude - Decimal Fraction - Discussion

Discussion Forum : Decimal Fraction - General Questions (Q.No. 17)
17.
The rational number for recurring decimal 0.125125.... is:
63
487
119
993
125
999
None of these
Answer: Option
Explanation:
0.125125... = 0.125 = 125
999
Discussion:
8 comments Page 1 of 1.

FAHIM said:   2 decades ago
PLZ TELL ME THE METHOD USING WHICH THIS RESULT IS FORMED.
PLZ REPLY SOON

Priyanka P. said:   1 decade ago
In this method the recurring number after decimal are show by 9's in denominator and non-recurring are represented by 0's.

As 0.125125 in it 125 these 3 digits are recurring so we represent it by 9, 125/999

if it is 0.123535 then it will be 1235/9900

hope it helps u.

Richa said:   1 decade ago
thank u priyanka...

Manoj said:   1 decade ago
Can some body tell me about non-recurring please I am not able to understand it : (.

RamJISharda said:   1 decade ago
Hey friends as we have studied in formulas that when we solve or covert a pure decimal into vulgar fraction then we divide that with 9 instead of 10 as in this case the .125125 is a pure decimal 0.125 so instead of 1000 we will use 999

n / n-1 = .n

Anonymous said:   9 years ago
Let x= 0.125125.

Now here we can see that 3 digits are recurring so what we do is multiply x by 1000.

That is if k digits are recurring then we will multiply the number by 10^k.

Now subtract the x from the number that is formed by multiplication.

In our case 1000 * x = 125.125125.

1000 * x - x = 125.

999x = 125.

X = 125/999.

Hope it helps!
(1)

Roselin said:   9 years ago
Thank you all. It's very useful.
(1)

Karan Kumar said:   5 years ago
x = 0.125125
10x = 1.25125.
100x = 12.5125.
1000x = 125.125.

Therefore,
1000x - x = 125.125 - 0.125.
999x = 125,
x =125/999.
(6)

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