Aptitude - Decimal Fraction - Discussion
Discussion Forum : Decimal Fraction - General Questions (Q.No. 14)
14.
The price of commodity X increases by 40 paise every year, while the price of commodity Y increases by 15 paise every year. If in 2001, the price of commodity X was Rs. 4.20 and that of Y was Rs. 6.30, in which year commodity X will cost 40 paise more than the commodity Y ?
Answer: Option
Explanation:
Suppose commodity X will cost 40 paise more than Y after z years.
Then, (4.20 + 0.40z) - (6.30 + 0.15z) = 0.40
0.25z = 0.40 + 2.10
| z = |
2.50 | = | 250 | = 10. |
| 0.25 | 25 |
X will cost 40 paise more than Y 10 years after 2001 i.e., 2011.
Discussion:
18 comments Page 2 of 2.
Minar said:
8 years ago
4.20 + (.4*10) = 8.2.
6.30 + (.15*10) = 7.8.
How could it be 10 yrs?
6.30 + (.15*10) = 7.8.
How could it be 10 yrs?
(1)
Renuka Prasad said:
1 decade ago
= {(6.30-4.20)+0.40}/0.40-0.15.
= 2.50/0.25.
= 10 year.
= 2.50/0.25.
= 10 year.
Shailu said:
5 years ago
@Monisa.
Thank you for the clear explanation.
Thank you for the clear explanation.
(2)
Himanshi sethi said:
10 years ago
@Moses.
They just convert paise into rupees.
They just convert paise into rupees.
Om singh said:
8 years ago
4.20+.40z=6.30+.15z+.40,
.25z=2.10+.40,
Z=10.
.25z=2.10+.40,
Z=10.
(1)
Bittu Rana said:
2 months ago
Very clear explanation. Thanks all.
Sankara Gomathi said:
9 years ago
Very clear this answer.
Thank you.
Thank you.
Jyothi said:
7 years ago
Very clear answer, Thanks all.
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