Aptitude - Compound Interest - Discussion

Discussion Forum : Compound Interest - General Questions (Q.No. 10)
10.
The effective annual rate of interest corresponding to a nominal rate of 6% per annum payable half-yearly is:
6.06%
6.07%
6.08%
6.09%
Answer: Option
Explanation:

Amount of Rs. 100 for 1 year
when compounded half-yearly
= Rs. 100 x 1 + 3 2 = Rs. 106.09
100

Effective rate = (106.09 - 100)% = 6.09%

Discussion:
43 comments Page 3 of 5.

XYZ said:   9 years ago
Why n is taken as n=2?

For half yearly formula is:
amt= P+ (1+r/2/100)^ 2N

Considering half yearly, N=1/2 then value of 2N = 2* 1/2=1.

Syamu said:   6 years ago
The given interest is 6%.

According to formulae of compound interest for half-yearly [p (1 + (R/2) /100) ^2].

Harsh Chandel said:   1 month ago
Apply AB theoram: a+b + ab/100.

When it's given half-yearly, we can split the rate by 3+3, which is equal to 6.
a + b + ab/100.
= 3 + 3+(3*3)/100.
= 6 + 9/100.
= 609/100.
= 6.09%.

Parvathy said:   1 decade ago
Still got no clue. Somebody please explain in simple context. What this effective rate and annual rate anyway?

Jasika said:   1 decade ago
Yeah. How we can find rate by subtracting principal from amount in the form of %?

Sathya said:   1 decade ago
The effective rate is the actual rate that you earn on an investment or pay on a loan after the effects of compounding frequency are considered.

Formula for Effective Rate = (1 + (i / n))^n -1


i = Nominal or stated interest rate
n = Number of compounding periods per year

Chadrashekhar said:   1 decade ago
Let p=rs 100

As we know that

for yearly:

A=P(1+R/100)^n
=100(1+6/100)
=Rs.106
for half yearly:

A=p(1+R/2*100)^2n
=100(1+6/2*100)^2*1
=100(103/100*103/100)
=Rs.106.09

Effective rate=(106.09-106)=6.09%

Vimal said:   1 decade ago
Thanks chandrashekhar.

Shyamlata said:   1 decade ago
@Chandrashekhar Ji, How could u solve the Effective rate?

= 106.09-106 = 6.09%.

Please explain it.

Arun said:   1 decade ago
Effective rate of Interest means,
the simple interest rate that produces the same amount of interest as the compound interest rate.

i.e assume the principal amount be 'x'
Then according to definition,

p*r*t = (p(1+r/100)^n - p),

For S.I., as per question, t= 1 year;
For C.I., as per question, we use formula C.I= (P(1+(r/2)/100)^2 - P);
Therefore,
x*r*1 = ( x(1+(6/2)/100)^2 - x),

r = 0.0609;
or, rate percent = 6.09.


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