Aptitude - Compound Interest - Discussion

Discussion Forum : Compound Interest - General Questions (Q.No. 3)
3.
There is 60% increase in an amount in 6 years at simple interest. What will be the compound interest of Rs. 12,000 after 3 years at the same rate?
Rs. 2160
Rs. 3120
Rs. 3972
Rs. 6240
None of these
Answer: Option
Explanation:

Let P = Rs. 100. Then, S.I. Rs. 60 and T = 6 years.

R = 100 x 60 = 10% p.a.
100 x 6

Now, P = Rs. 12000. T = 3 years and R = 10% p.a.

C.I.
= Rs. 12000 x 1 + 10 3 - 1
100
= Rs. 12000 x 331
1000
= 3972.

Discussion:
94 comments Page 5 of 10.

Aashi said:   7 years ago
Please tell me how 331 is coming? Please explain me.

Rajeev rathor said:   7 years ago
Using pascal traingle.

= 3*10%of12000+3*10%of1200+1*10%of120,
= 3600+360+12,
= 3972.

Shub said:   7 years ago
Amount after 1st year =1200.
After 2nd year=1200 + 120.
After 3rd year= 1200 + 120+120+12.
Total = 3972.

Ronald said:   5 years ago
12000 in 10% is 1200 then,
12000+1200=13200 is 1st year.
And 13200 in 10% so 13200+3200= 16400.
Same next year we get 16400+6400=18040.
Then, 18040-12000=6040.

Why not like this? Anyone explain to me.

Shri said:   5 years ago
Thanks for explaining @Anmol.

Sangavi said:   7 years ago
When will we use -P in the compound interest formula?

Rahul krishna said:   6 years ago
Let p=100 and si=60(as amount increase to 60%).
Si=(p*r*t)/100.
Find r=?.

Then, with the help of r find ci.

Rahul krishna said:   6 years ago
@Sangavi we use - p because.
CI = Amount - principal.
So, CI=p(1+r/100)^n-p.

Poorvajain said:   1 decade ago
CI=AMT-PRINCIPLE

So in this question princple is 100 and u hve taken principle 1 why so is it wrong.

Sarojkumarnaik786@gmail.com said:   1 decade ago
Generally we know the formula of amount not C.I.

Amount = P(1+ R\100)^t.

If we find C.I then we should subtract the principal, then the formula changes to C.I = P((1 + R/100)^t -- 1).


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