Aptitude - Compound Interest - Discussion
Discussion Forum : Compound Interest - General Questions (Q.No. 3)
3.
There is 60% increase in an amount in 6 years at simple interest. What will be the compound interest of Rs. 12,000 after 3 years at the same rate?
Answer: Option
Explanation:
Let P = Rs. 100. Then, S.I. Rs. 60 and T = 6 years.
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100 x 60 | ![]() |
= 10% p.a. |
100 x 6 |
Now, P = Rs. 12000. T = 3 years and R = 10% p.a.
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= 3972. |
Discussion:
94 comments Page 5 of 10.
Aashi said:
7 years ago
Please tell me how 331 is coming? Please explain me.
Rajeev rathor said:
7 years ago
Using pascal traingle.
= 3*10%of12000+3*10%of1200+1*10%of120,
= 3600+360+12,
= 3972.
= 3*10%of12000+3*10%of1200+1*10%of120,
= 3600+360+12,
= 3972.
Shub said:
7 years ago
Amount after 1st year =1200.
After 2nd year=1200 + 120.
After 3rd year= 1200 + 120+120+12.
Total = 3972.
After 2nd year=1200 + 120.
After 3rd year= 1200 + 120+120+12.
Total = 3972.
Ronald said:
5 years ago
12000 in 10% is 1200 then,
12000+1200=13200 is 1st year.
And 13200 in 10% so 13200+3200= 16400.
Same next year we get 16400+6400=18040.
Then, 18040-12000=6040.
Why not like this? Anyone explain to me.
12000+1200=13200 is 1st year.
And 13200 in 10% so 13200+3200= 16400.
Same next year we get 16400+6400=18040.
Then, 18040-12000=6040.
Why not like this? Anyone explain to me.
Shri said:
5 years ago
Thanks for explaining @Anmol.
Sangavi said:
7 years ago
When will we use -P in the compound interest formula?
Rahul krishna said:
6 years ago
Let p=100 and si=60(as amount increase to 60%).
Si=(p*r*t)/100.
Find r=?.
Then, with the help of r find ci.
Si=(p*r*t)/100.
Find r=?.
Then, with the help of r find ci.
Rahul krishna said:
6 years ago
@Sangavi we use - p because.
CI = Amount - principal.
So, CI=p(1+r/100)^n-p.
CI = Amount - principal.
So, CI=p(1+r/100)^n-p.
Poorvajain said:
1 decade ago
CI=AMT-PRINCIPLE
So in this question princple is 100 and u hve taken principle 1 why so is it wrong.
So in this question princple is 100 and u hve taken principle 1 why so is it wrong.
Sarojkumarnaik786@gmail.com said:
1 decade ago
Generally we know the formula of amount not C.I.
Amount = P(1+ R\100)^t.
If we find C.I then we should subtract the principal, then the formula changes to C.I = P((1 + R/100)^t -- 1).
Amount = P(1+ R\100)^t.
If we find C.I then we should subtract the principal, then the formula changes to C.I = P((1 + R/100)^t -- 1).
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