Aptitude - Compound Interest - Discussion

Discussion Forum : Compound Interest - General Questions (Q.No. 7)
7.
At what rate of compound interest per annum will a sum of Rs. 1200 become Rs. 1348.32 in 2 years?
6%
6.5%
7%
7.5%
Answer: Option
Explanation:

Let the rate be R% p.a.

Then, 1200 x 1 + R 2 = 1348.32
100

1 + R 2 = 134832 = 11236
100 120000 10000

1 + R 2 = 106 2
100 100

1 + R = 106
100 100

R = 6%

Discussion:
41 comments Page 3 of 5.

Suraj said:   7 years ago
What is the answer, if 9 months is given here instead of 2 years?

Harika said:   1 decade ago
To find cp=p(1+R/100)^n-p but only amount is taken

Shikhar shukla said:   1 decade ago
After the last step how 6% comes please explain?

Jasika said:   1 decade ago
1348.32 is CI, but here they have taken. Directly at the place of amount. ?

Vinoth said:   1 decade ago
Divide numerator and denominater by 100 to take out point. Tahts why 1200 as 120000.

Pawan said:   1 decade ago
Shakti borrows an amount of Rs 28000 for 2 years from a bank at a subsidised rate. At the end of 2 years he pays a sum of Rs 30870. How much was the rate of interest? What is the amount that should be paid if Shakti pays it after 3 years?

Solve it please?

G NARESH said:   1 decade ago
How you got 11236/10000?

Pinky said:   1 decade ago
By dividing numerator and denominator by 12 we got 11236/10000.

Praveen said:   1 decade ago
Let subtract sum from total amount 1348.32 - 1200 is 148.32.

148.32 is two years interest amt (profit) we get. Ten one year interest amount is 148.30/2 = 74 per annum.

Lets find the 74 amount interest rate of 1200 >>> 10% is 120 and then 6% is 74 Rs that all. 6% is right answer. Hope you understand this.

Rosy said:   1 decade ago
1348.32 = 1200(1+R/100)^2.

1.1236 = (1+R/100)^2.

(1.1236)^(1/2) = (1+R/100).

Since, divided half both sides,

1.06 = (1+R/100).

r = 6%.


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