Aptitude - Compound Interest - Discussion

Discussion Forum : Compound Interest - General Questions (Q.No. 7)
7.
At what rate of compound interest per annum will a sum of Rs. 1200 become Rs. 1348.32 in 2 years?
6%
6.5%
7%
7.5%
Answer: Option
Explanation:

Let the rate be R% p.a.

Then, 1200 x 1 + R 2 = 1348.32
100

1 + R 2 = 134832 = 11236
100 120000 10000

1 + R 2 = 106 2
100 100

1 + R = 106
100 100

R = 6%

Discussion:
41 comments Page 2 of 5.

Vijay said:   9 years ago
1348.32 is not the C.I.
It is the amount so obviously 1348.32 =1200(1 + r/100)^2,the formula for the amount,I got confused at this. Please help me.
(3)

Rosy said:   1 decade ago
1348.32 = 1200(1+R/100)^2.

1.1236 = (1+R/100)^2.

(1.1236)^(1/2) = (1+R/100).

Since, divided half both sides,

1.06 = (1+R/100).

r = 6%.

Rakesh sharma said:   9 years ago
(100 + R) x 1200/100 = 1348.32,
100 + R = 1348.32 x 100/1200,
100 + R = 112.36,
R =12.36 * 6 + 6 + (6x6/100) = 12.36 so ans is 6.

Srivardhani said:   4 weeks ago
1200:
For 1st year: 6% of 1200 = 72 => 1200 + 72 = 1272.
2nd year : 6% of 1272 = 76.32 => 1272 + 76.32 = 1348.32.

Mounica said:   1 decade ago
Can any one explain this?

1348.32 is CI, but here they have taken directly at the place of amount?

Vinoth said:   1 decade ago
Divide numerator and denominater by 100 to take out point. Tahts why 1200 as 120000.

Praveena said:   7 years ago
1+R/100=106/100.
R/100=106/100-1,
R/100=106-100/100,
R/100=6/100,
100R=600,
R=6.
(10)

Saumitr K said:   8 years ago
Can any one explain me how to solve it by percentage change?

I am getting 6.3.

TKB said:   10 years ago
Can't we just apply the formula P = R/T using 1200 as the principal amount?

Jasika said:   1 decade ago
1348.32 is CI, but here they have taken. Directly at the place of amount. ?


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