Aptitude - Compound Interest - Discussion

Discussion Forum : Compound Interest - General Questions (Q.No. 4)
4.
What is the difference between the compound interests on Rs. 5000 for 1 years at 4% per annum compounded yearly and half-yearly?
Rs. 2.04
Rs. 3.06
Rs. 4.80
Rs. 8.30
Answer: Option
Explanation:

C.I. when interest
compounded yearly    
= Rs. 5000 x 1 + 4 x 1 + x 4
100 100
= Rs. 5000 x 26 x 51
25 50
= Rs. 5304.

C.I. when interest is
compounded half-yearly
= Rs. 5000 x 1 + 2 3
100
= Rs. 5000 x 51 x 51 x 51
50 50 50
= Rs. 5306.04

Difference = Rs. (5306.04 - 5304) = Rs. 2.04

Discussion:
85 comments Page 6 of 9.

Keya said:   10 years ago
If the year was 5 and 1/2 years instead of 3/2 years for annual compound interest then what should be the equation?

A = P[(1+R/100)^5*{1+ (R/2) /100). Is it correct?

Ayan Guchhait said:   1 decade ago
If the calculator is not provided.

Then short cut (same as Given Solution).

For yearly (Amount+compound interest) = A (1 + [r/100]) ^ 3/2 A = 5000; are = 4.

= A (1 + [r/100]) ^ (1+1/2).

= A (1 + [r/100]) * (1 +[r/100] ^ (1/2)).

= A (1 + [r/100]) * (1 + 1/2[r/100]).

For half yearly (Amount +compound interest) =A (1 +[(r/2) /100]) ^ (3/2*2).

Manohar said:   1 decade ago
Hello friends.

Thank you for sharing your views about that problem.

Sangeet said:   1 decade ago
Not understand this question. Why we multiply (1+(((1/2)*4)/100)?

Even I am not able understand the further steps.

Kajal said:   1 decade ago
Why are you using the formula of amount instead of C.I that means question is demanding for the difference of C.I rather the difference of amount.

Prach said:   1 decade ago
How 51 come?

Sowmya` said:   1 decade ago
When time is in fraction formula changes as:

For ex time is: 1 1/2 years.

= p(1+r/100)^1*(1+(r/2)/100).

Ranjeeta said:   1 decade ago
When the interest is compounded yearly, for that A = P(1+r/100)^t.

= 5000(1+4/100)^1.5 = 5302.98.

But here's what they have done I am not getting it for yearly compounding?

Stephen hawking said:   1 decade ago
Correct answer is 3.06.

CI 1 = 302.98 (not 304) and CI 2 = 306.04.

Gurpreet said:   1 decade ago
For yearly A = P[(1+R/100)*{1+(R/2)/100).
Then CI =A-P =304.

For half-yearly A = P(1+(R/2)/100)^3.
Then CI =A-P =306.04.

After that difference = CI(half yearly)-CI(yearly) = [(306.04)-304] = 2.04.


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