Aptitude - Compound Interest - Discussion
Discussion Forum : Compound Interest - General Questions (Q.No. 9)
9.
Albert invested an amount of Rs. 8000 in a fixed deposit scheme for 2 years at compound interest rate 5 p.c.p.a. How much amount will Albert get on maturity of the fixed deposit?
Answer: Option
Explanation:
Amount |
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= Rs. 8820. |
Discussion:
23 comments Page 2 of 3.
Tamsa said:
6 years ago
A=P(1+R/100)^n.
8000(1+5/100)^2,
80(105)^2.
= 105 * 105 = 11025 * 80 = 882000.
8000(1+5/100)^2,
80(105)^2.
= 105 * 105 = 11025 * 80 = 882000.
(1)
Ankit said:
9 years ago
I can solve this question by P(1+r/100)n.
Use this formula, you will get the solution.
Use this formula, you will get the solution.
Senthilprakash said:
1 decade ago
Why we are putting (1+5/100) 2,
I need why 1 is there and why we are squaring them.
I need why 1 is there and why we are squaring them.
Shubakar ps said:
9 years ago
Given: r = 5, n = 2, p = 8000.
Amount = P[1+r/100]^n;
CI = Amount + principal;
Amount = P[1+r/100]^n;
CI = Amount + principal;
Nishant said:
1 decade ago
@Shivani.
C.I = P(1 +R/100)^n.
Use this formula you will get answer.
C.I = P(1 +R/100)^n.
Use this formula you will get answer.
Daryl said:
9 years ago
Formula:
CI = A - P.
A = P ( 1 + R/100 )^N.
N= no of years.
CI = A - P.
A = P ( 1 + R/100 )^N.
N= no of years.
Ritha said:
1 decade ago
How this 21/20 is come? please can someone explain this.
Varshink said:
9 years ago
Can anyone tell why are we using amount formulae for CI?
Thinesh said:
8 years ago
Why are we not using CI = [ PX(1+R/100)^n]-P formula?
Sweta said:
9 years ago
Can I solve this question by any short trick?
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