Aptitude - Clock - Discussion
Discussion Forum : Clock - General Questions (Q.No. 6)
6.
At what time between 7 and 8 o'clock will the hands of a clock be in the same straight line but, not together?
Answer: Option
Explanation:
When the hands of the clock are in the same straight line but not together, they are 30 minute spaces apart.
At 7 o'clock, they are 25 min. spaces apart.
Minute hand will have to gain only 5 min. spaces.
55 min. spaces are gained in 60 min.
| 5 min. spaces are gained in |  |
60 | x 5 |  min |
= 5 | 5 | min. |
| 55 | 11 |
| Required time = 5 |
5 | min. past 7. |
| 11 |
Discussion:
70 comments Page 2 of 7.
Joshua Thangliana said:
7 years ago
Degree= 30H - 5.5M.
straight line= 180 °
=> 180= 30*7 - 5.5M.
=> M= 60/11.
So, Answer= 7 hours 60/11 min.
straight line= 180 °
=> 180= 30*7 - 5.5M.
=> M= 60/11.
So, Answer= 7 hours 60/11 min.
(1)
Bombiyah said:
6 years ago
The angle formed from 12 o'clock to 7 o'clock is 210°.
Use this formula:
2/11 (angle formed (+) or (-) 180°)
Add 180 when the clock hands coincide, subtract when they are not.
Since, not coincide subtract it,
=2/11(210 * 180°)
= 60/11 or 5 5/11.
Use this formula:
2/11 (angle formed (+) or (-) 180°)
Add 180 when the clock hands coincide, subtract when they are not.
Since, not coincide subtract it,
=2/11(210 * 180°)
= 60/11 or 5 5/11.
(1)
Dara. Sai Madhukar said:
5 years ago
This question is solved by using formula.
A=30*HOUR -5.5*MINUTES.
Here we aer going to take A =180 degrees (straight line).
180=30*7-5.5*M.
M is minutes.
A=30*HOUR -5.5*MINUTES.
Here we aer going to take A =180 degrees (straight line).
180=30*7-5.5*M.
M is minutes.
(1)
Bangya said:
5 years ago
Assume that the time is 1 O'clock. If we look in a clockwise direction, it's 55 min space but if we look in the anticlockwise direction, it's 5-minute space. Can somebody explain which direction should we look to know the correct minute space?
If both directions are correct, then 5-minute space will be equal to 55-minute space.
If both directions are correct, then 5-minute space will be equal to 55-minute space.
(1)
Harish udupa s said:
9 years ago
At 7o clock hour, the hand will be 210 degrees, at 5min minute hand will be 30 degrees, (same line).
So consider 5min 5/11 for hour hand and just 5/11min for minute hand.
For every 1min hour hand rotates by 0.5 degrees so for 60/11 min it rotates by 30/11 degree.
For every min minute hand rotates by 6 degrees for 5/11 min it rotates by 30/11 degree hence equal.
So at 7 past 5min 5/11 it will be 210+30/11 degree in hour hand and 30+30/11 for minute hand difference is 180 degree thus they are in same line.
So consider 5min 5/11 for hour hand and just 5/11min for minute hand.
For every 1min hour hand rotates by 0.5 degrees so for 60/11 min it rotates by 30/11 degree.
For every min minute hand rotates by 6 degrees for 5/11 min it rotates by 30/11 degree hence equal.
So at 7 past 5min 5/11 it will be 210+30/11 degree in hour hand and 30+30/11 for minute hand difference is 180 degree thus they are in same line.
Sonia said:
6 years ago
At 7:05 both hands of the clock make a straight line.
So by taking 5 minutes use formula (5*12/11), that's it.
So by taking 5 minutes use formula (5*12/11), that's it.
Vikram kumar said:
9 years ago
Use formula.
(5A + or - 30) * 12/11min past A.
Where A = + whan A < 6 and - when a > 6.
According to the question A = 5.
(5A + or - 30) * 12/11min past A.
Where A = + whan A < 6 and - when a > 6.
According to the question A = 5.
Sandun said:
9 years ago
Another way to do this.
The angle created when the time is 7 o' clock is 150*. So we have to add the extra gained by minute hand and to subtract the angle lost by hour hand.
If we put this in to an equation and we get x = 5 5\11.
The angle created when the time is 7 o' clock is 150*. So we have to add the extra gained by minute hand and to subtract the angle lost by hour hand.
If we put this in to an equation and we get x = 5 5\11.
Prasanna said:
9 years ago
Here, is some Equation:
Angle between hands = [(Hour Hand * 30) + (Minute hand * 1/2)] - Minute hand * 6.
(Hour Hand * 30) -> Because At 1 o'clock it will be 30 deg so at 7 it will be 150 deg.
Minute hand * 1/2 -> Hour hand moves 1/2 deg per min.
Minute hand * 6 -> Minute hand moves 6 deg per min.
180 = [7 * 30 + x/2] - 6x.
So, the answer is 5 5/1.
Angle between hands = [(Hour Hand * 30) + (Minute hand * 1/2)] - Minute hand * 6.
(Hour Hand * 30) -> Because At 1 o'clock it will be 30 deg so at 7 it will be 150 deg.
Minute hand * 1/2 -> Hour hand moves 1/2 deg per min.
Minute hand * 6 -> Minute hand moves 6 deg per min.
180 = [7 * 30 + x/2] - 6x.
So, the answer is 5 5/1.
Shiv said:
9 years ago
Thanks for your solution @Shekhar.
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers