Aptitude - Clock - Discussion
Discussion Forum : Clock - General Questions (Q.No. 6)
6.
At what time between 7 and 8 o'clock will the hands of a clock be in the same straight line but, not together?
Answer: Option
Explanation:
When the hands of the clock are in the same straight line but not together, they are 30 minute spaces apart.
At 7 o'clock, they are 25 min. spaces apart.
Minute hand will have to gain only 5 min. spaces.
55 min. spaces are gained in 60 min.
| 5 min. spaces are gained in | ![]() |
60 | x 5 | min |
= 5 | 5 | min. |
| 55 | 11 |
Required time = 5 |
5 | min. past 7. |
| 11 |
Discussion:
70 comments Page 2 of 7.
Joshua Thangliana said:
7 years ago
Degree= 30H - 5.5M.
straight line= 180 °
=> 180= 30*7 - 5.5M.
=> M= 60/11.
So, Answer= 7 hours 60/11 min.
straight line= 180 °
=> 180= 30*7 - 5.5M.
=> M= 60/11.
So, Answer= 7 hours 60/11 min.
(1)
Bombiyah said:
7 years ago
The angle formed from 12 o'clock to 7 o'clock is 210°.
Use this formula:
2/11 (angle formed (+) or (-) 180°)
Add 180 when the clock hands coincide, subtract when they are not.
Since, not coincide subtract it,
=2/11(210 * 180°)
= 60/11 or 5 5/11.
Use this formula:
2/11 (angle formed (+) or (-) 180°)
Add 180 when the clock hands coincide, subtract when they are not.
Since, not coincide subtract it,
=2/11(210 * 180°)
= 60/11 or 5 5/11.
(1)
Dara. Sai Madhukar said:
6 years ago
This question is solved by using formula.
A=30*HOUR -5.5*MINUTES.
Here we aer going to take A =180 degrees (straight line).
180=30*7-5.5*M.
M is minutes.
A=30*HOUR -5.5*MINUTES.
Here we aer going to take A =180 degrees (straight line).
180=30*7-5.5*M.
M is minutes.
(1)
Bangya said:
5 years ago
Assume that the time is 1 O'clock. If we look in a clockwise direction, it's 55 min space but if we look in the anticlockwise direction, it's 5-minute space. Can somebody explain which direction should we look to know the correct minute space?
If both directions are correct, then 5-minute space will be equal to 55-minute space.
If both directions are correct, then 5-minute space will be equal to 55-minute space.
(1)
Bhargav Bhatti said:
1 year ago
@All.
As we know that;
1hr i.e. 60 min the the minute hand gains 55 minute spaces over the hour hand.
So in the minute formula just replace 60 by 55 to get the answer
Given:-
The min and hour hand are in a straight line so the angle between them is 180 degrees
So angle = 180 degree.
Formula :
= |55x7-360/11|,
= 385 - 360/11 = 25/11.
Hence, the answer = 5 5/11.
As we know that;
1hr i.e. 60 min the the minute hand gains 55 minute spaces over the hour hand.
So in the minute formula just replace 60 by 55 to get the answer
Given:-
The min and hour hand are in a straight line so the angle between them is 180 degrees
So angle = 180 degree.
Formula :
= |55x7-360/11|,
= 385 - 360/11 = 25/11.
Hence, the answer = 5 5/11.
(1)
Harish udupa s said:
10 years ago
At 7o clock hour, the hand will be 210 degrees, at 5min minute hand will be 30 degrees, (same line).
So consider 5min 5/11 for hour hand and just 5/11min for minute hand.
For every 1min hour hand rotates by 0.5 degrees so for 60/11 min it rotates by 30/11 degree.
For every min minute hand rotates by 6 degrees for 5/11 min it rotates by 30/11 degree hence equal.
So at 7 past 5min 5/11 it will be 210+30/11 degree in hour hand and 30+30/11 for minute hand difference is 180 degree thus they are in same line.
So consider 5min 5/11 for hour hand and just 5/11min for minute hand.
For every 1min hour hand rotates by 0.5 degrees so for 60/11 min it rotates by 30/11 degree.
For every min minute hand rotates by 6 degrees for 5/11 min it rotates by 30/11 degree hence equal.
So at 7 past 5min 5/11 it will be 210+30/11 degree in hour hand and 30+30/11 for minute hand difference is 180 degree thus they are in same line.
Sonia said:
6 years ago
At 7:05 both hands of the clock make a straight line.
So by taking 5 minutes use formula (5*12/11), that's it.
So by taking 5 minutes use formula (5*12/11), that's it.
Vikram kumar said:
9 years ago
Use formula.
(5A + or - 30) * 12/11min past A.
Where A = + whan A < 6 and - when a > 6.
According to the question A = 5.
(5A + or - 30) * 12/11min past A.
Where A = + whan A < 6 and - when a > 6.
According to the question A = 5.
Sandun said:
9 years ago
Another way to do this.
The angle created when the time is 7 o' clock is 150*. So we have to add the extra gained by minute hand and to subtract the angle lost by hour hand.
If we put this in to an equation and we get x = 5 5\11.
The angle created when the time is 7 o' clock is 150*. So we have to add the extra gained by minute hand and to subtract the angle lost by hour hand.
If we put this in to an equation and we get x = 5 5\11.
Prasanna said:
9 years ago
Here, is some Equation:
Angle between hands = [(Hour Hand * 30) + (Minute hand * 1/2)] - Minute hand * 6.
(Hour Hand * 30) -> Because At 1 o'clock it will be 30 deg so at 7 it will be 150 deg.
Minute hand * 1/2 -> Hour hand moves 1/2 deg per min.
Minute hand * 6 -> Minute hand moves 6 deg per min.
180 = [7 * 30 + x/2] - 6x.
So, the answer is 5 5/1.
Angle between hands = [(Hour Hand * 30) + (Minute hand * 1/2)] - Minute hand * 6.
(Hour Hand * 30) -> Because At 1 o'clock it will be 30 deg so at 7 it will be 150 deg.
Minute hand * 1/2 -> Hour hand moves 1/2 deg per min.
Minute hand * 6 -> Minute hand moves 6 deg per min.
180 = [7 * 30 + x/2] - 6x.
So, the answer is 5 5/1.
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