Aptitude - Clock - Discussion
Discussion Forum : Clock - General Questions (Q.No. 6)
6.
At what time between 7 and 8 o'clock will the hands of a clock be in the same straight line but, not together?
Answer: Option
Explanation:
When the hands of the clock are in the same straight line but not together, they are 30 minute spaces apart.
At 7 o'clock, they are 25 min. spaces apart.
Minute hand will have to gain only 5 min. spaces.
55 min. spaces are gained in 60 min.
| 5 min. spaces are gained in |  |
60 | x 5 |  min |
= 5 | 5 | min. |
| 55 | 11 |
| Required time = 5 |
5 | min. past 7. |
| 11 |
Discussion:
71 comments Page 2 of 8.
Joshua Thangliana said:
8 years ago
Degree= 30H - 5.5M.
straight line= 180 °
=> 180= 30*7 - 5.5M.
=> M= 60/11.
So, Answer= 7 hours 60/11 min.
straight line= 180 °
=> 180= 30*7 - 5.5M.
=> M= 60/11.
So, Answer= 7 hours 60/11 min.
(1)
Bombiyah said:
7 years ago
The angle formed from 12 o'clock to 7 o'clock is 210°.
Use this formula:
2/11 (angle formed (+) or (-) 180°)
Add 180 when the clock hands coincide, subtract when they are not.
Since, not coincide subtract it,
=2/11(210 * 180°)
= 60/11 or 5 5/11.
Use this formula:
2/11 (angle formed (+) or (-) 180°)
Add 180 when the clock hands coincide, subtract when they are not.
Since, not coincide subtract it,
=2/11(210 * 180°)
= 60/11 or 5 5/11.
(1)
Tehsin said:
8 years ago
I couldn't get it how 55 min required to gain 60 min spaces. I mean they are min spaces so why not 60 min spaces be in 60 min? please someone explain!
(1)
Dara. Sai Madhukar said:
6 years ago
This question is solved by using formula.
A=30*HOUR -5.5*MINUTES.
Here we aer going to take A =180 degrees (straight line).
180=30*7-5.5*M.
M is minutes.
A=30*HOUR -5.5*MINUTES.
Here we aer going to take A =180 degrees (straight line).
180=30*7-5.5*M.
M is minutes.
(1)
Bhargav Bhatti said:
2 years ago
@All.
As we know that;
1hr i.e. 60 min the the minute hand gains 55 minute spaces over the hour hand.
So in the minute formula just replace 60 by 55 to get the answer
Given:-
The min and hour hand are in a straight line so the angle between them is 180 degrees
So angle = 180 degree.
Formula :
= |55x7-360/11|,
= 385 - 360/11 = 25/11.
Hence, the answer = 5 5/11.
As we know that;
1hr i.e. 60 min the the minute hand gains 55 minute spaces over the hour hand.
So in the minute formula just replace 60 by 55 to get the answer
Given:-
The min and hour hand are in a straight line so the angle between them is 180 degrees
So angle = 180 degree.
Formula :
= |55x7-360/11|,
= 385 - 360/11 = 25/11.
Hence, the answer = 5 5/11.
(1)
NAVI said:
9 years ago
I didn't understand the question. Can anyone help me?
Sandun said:
10 years ago
Another way to do this.
The angle created when the time is 7 o' clock is 150*. So we have to add the extra gained by minute hand and to subtract the angle lost by hour hand.
If we put this in to an equation and we get x = 5 5\11.
The angle created when the time is 7 o' clock is 150*. So we have to add the extra gained by minute hand and to subtract the angle lost by hour hand.
If we put this in to an equation and we get x = 5 5\11.
Rintu said:
10 years ago
To from 180d between 7:0 to 8:0, the minute hand has to gain (35 - 30) = 5 min space.
As in 1 min =12/11 min gain.
Therfore in 5 min=12/11 * 5 = 5 * 5/11 min.
As in 1 min =12/11 min gain.
Therfore in 5 min=12/11 * 5 = 5 * 5/11 min.
Hrushi said:
9 years ago
How 5*5/11 come?
Please explain.
Please explain.
Shanur Rahman said:
9 years ago
@Sharmistha.
Minute hand gains 55 minutes on the hour hand.
Minute hand gains 55 minutes on the hour hand.
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