Aptitude - Clock - Discussion

Discussion Forum : Clock - General Questions (Q.No. 16)
16.
At what time, in minutes, between 3 o'clock and 4 o'clock, both the needles will coincide each other?
5 1 "
11
12 4 "
11
13 4 "
11
16 4 "
11
Answer: Option
Explanation:

At 3 o'clock, the minute hand is 15 min. spaces apart from the hour hand.

To be coincident, it must gain 15 min. spaces.

55 min. are gained in 60 min.

15 min. are gained in 60 x 15 min = 16 4 min.
55 11

The hands are coincident at 16 4 min. past 3.
11

Discussion:
33 comments Page 3 of 4.

Deepak said:   1 decade ago
I can't get that 55 min. are gained in 60 min

Subodh said:   9 years ago
@Kajal.

When minute hand covers 60 minutes that is passed by hour hand only 5 minutes space which alternatively we can say 1 hour for hour hand. But here among space covered by minute hand i.e. 60 minutes. Hour hand expenses only 5 minute equals i.e. 1 hour. So gained by minute hand is 55 minutes.

Kajal said:   9 years ago
I also confused with 55 m. Please explain it.

Fiza khan said:   9 years ago
I was also confused about 55 m but now I got it with the help of the explanation.

Thanks to all.

Sai said:   9 years ago
55 min are gained in 60 min means;

Take an example minute hand and hour hand at 12 o clock i.e. both coincide.

Now when hour hand moves by 1 hour it has covered only 5 degrees from the start i.e.12 o clock.

However, the minute hand covers 60 degrees from the start i.e. 12o clock.

So in 60 minutes minute hand gains 55 minutes on hour hand (i.e. 60 - 5 = 55).

Chandra prakash verma said:   10 years ago
As it is between 3 to 4 o'clock. So hour (H=3).

Arun said:   1 decade ago
@Sai.

How H=3?

Sai said:   1 decade ago
I have formula for clocks coincide.

= (5(H)+0)*(12/11) where H = 3.

Xyz said:   1 decade ago
Both the needles coincide after 3 O' clock. Number 3 is on clock is situated after 15 minutes. So answer must have 15 minutes or more in options, We have only one option that is D 16(4/11).

James said:   1 decade ago
Does this take into account that the hour hand moves while the minute hand moves? So, that after 15 minutes, the minute hand has moved 15/60 (=1/4) of the way around, and similarly, the hour hand has moved proportionally the same. In other words, it has moved 1/4 of the way to the next hour (4 o'clock).

So, the minute hand is moving 12 times as fast as the hour hand. Conversely, the hour hand is moving 1/12 the speed of the minute hand. I have only had a moment to think about this, but if you consider both hands to be moving, but at different rates, it would seem that the minute hand would pass the hour hand (between the 1 o'clock and 2 o'clock hours) , between and 1:05 and 25 seconds and 1:05 and 50 seconds. From 2 to 3, it would pass over the hour hand somewhere between 2:11 and 15 seconds and 2:11 and 40 seconds. Roughly.

However, I haven't given thought to how to relate the two positions of the two hands via a single relationship for the precise points of intersection.


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