Aptitude - Clock - Discussion
Discussion Forum : Clock - General Questions (Q.No. 16)
16.
At what time, in minutes, between 3 o'clock and 4 o'clock, both the needles will coincide each other?
Answer: Option
Explanation:
At 3 o'clock, the minute hand is 15 min. spaces apart from the hour hand.
To be coincident, it must gain 15 min. spaces.
55 min. are gained in 60 min.
| 15 min. are gained in |  |
60 | x 15 |  min |
= | 16 | 4 | min. |
| 55 | 11 |
 The hands are coincident at 16 |
4 | min. past 3. |
| 11 |
Discussion:
34 comments Page 1 of 4.
Akshita said:
1 year ago
Thanks @Sai.
For giving formula for coincide (5 (H) +0) * (12/11) h =3.
For giving formula for coincide (5 (H) +0) * (12/11) h =3.
(4)
Penjor said:
5 years ago
How 15 min spaces at 3 o clock? Anyone explain it for me.
(3)
Josava said:
9 years ago
In that formula,
M=2/11*(30*H +- degree) 2/11(3*30) =180/11 = 16 4/11 ans.
Note coincide means 0 degree.
M=2/11*(30*H +- degree) 2/11(3*30) =180/11 = 16 4/11 ans.
Note coincide means 0 degree.
(2)
Bharat balasaheb jadhav said:
2 years ago
12 to 1 = 5.
1 to 2 = 5.
2 to 3 = 5.
= 15.
=15/(11/12).
= 15 * 12/11 = 180/11,
=11 4/11 ans.
1 to 2 = 5.
2 to 3 = 5.
= 15.
=15/(11/12).
= 15 * 12/11 = 180/11,
=11 4/11 ans.
(1)
OVI said:
5 years ago
Can anyone explain briefly?
(1)
Grump said:
6 years ago
Here, min space refers to the displacement of the minute hand, w.r.t y o' clock, in forms of mins(minute hand mins) where y = 3.
So min space = 15(5, 10, 15 - 1, 2, 3)
Visualize relative speed. There are two trains. One is goods train 15 km away travelling at 5/60 km per min.
And there is another train which is travelling at 1 km per minute.
Relative speed = (1-5/60)kmph.
= 55/60 = 11/12.
time = distance/speed = 15/(11/12)min = 180/11 min = 16 + 4/11 min.
So min space = 15(5, 10, 15 - 1, 2, 3)
Visualize relative speed. There are two trains. One is goods train 15 km away travelling at 5/60 km per min.
And there is another train which is travelling at 1 km per minute.
Relative speed = (1-5/60)kmph.
= 55/60 = 11/12.
time = distance/speed = 15/(11/12)min = 180/11 min = 16 + 4/11 min.
(1)
Nancy said:
6 years ago
How to find 15min space?
Vinodh said:
8 years ago
Its very easy I am n. Vinodh kumar the formulae is x (x/11). So here x=3. We have to multiply with 5.
So 3*5=15.
Now x is 15 so as per formulae 15 (15/11) =16 (4/11).
So 3*5=15.
Now x is 15 so as per formulae 15 (15/11) =16 (4/11).
Peaceful said:
8 years ago
No, The needles only move after every second. With time unit smaller than one second, all needles stay where they are. Since 16 (4/11) minutes = 16*60 (4/11) (in second) is not a natural number, So, it cannot be the answer.
Prawesh Pradhan said:
8 years ago
m= 60/11 * t,
m= 60/11 * 3.
m= 16 4/11.
m= 60/11 * 3.
m= 16 4/11.
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