Aptitude - Clock - Discussion
Discussion Forum : Clock - General Questions (Q.No. 16)
16.
At what time, in minutes, between 3 o'clock and 4 o'clock, both the needles will coincide each other?
Answer: Option
Explanation:
At 3 o'clock, the minute hand is 15 min. spaces apart from the hour hand.
To be coincident, it must gain 15 min. spaces.
55 min. are gained in 60 min.
| 15 min. are gained in |  |
60 | x 15 |  min |
= | 16 | 4 | min. |
| 55 | 11 |
 The hands are coincident at 16 |
4 | min. past 3. |
| 11 |
Discussion:
33 comments Page 1 of 4.
Akshita said:
9 months ago
Thanks @Sai.
For giving formula for coincide (5 (H) +0) * (12/11) h =3.
For giving formula for coincide (5 (H) +0) * (12/11) h =3.
(4)
Josava said:
8 years ago
In that formula,
M=2/11*(30*H +- degree) 2/11(3*30) =180/11 = 16 4/11 ans.
Note coincide means 0 degree.
M=2/11*(30*H +- degree) 2/11(3*30) =180/11 = 16 4/11 ans.
Note coincide means 0 degree.
(2)
Penjor said:
5 years ago
How 15 min spaces at 3 o clock? Anyone explain it for me.
(2)
Bharat balasaheb jadhav said:
2 years ago
12 to 1 = 5.
1 to 2 = 5.
2 to 3 = 5.
= 15.
=15/(11/12).
= 15 * 12/11 = 180/11,
=11 4/11 ans.
1 to 2 = 5.
2 to 3 = 5.
= 15.
=15/(11/12).
= 15 * 12/11 = 180/11,
=11 4/11 ans.
(1)
OVI said:
5 years ago
Can anyone explain briefly?
(1)
Grump said:
6 years ago
Here, min space refers to the displacement of the minute hand, w.r.t y o' clock, in forms of mins(minute hand mins) where y = 3.
So min space = 15(5, 10, 15 - 1, 2, 3)
Visualize relative speed. There are two trains. One is goods train 15 km away travelling at 5/60 km per min.
And there is another train which is travelling at 1 km per minute.
Relative speed = (1-5/60)kmph.
= 55/60 = 11/12.
time = distance/speed = 15/(11/12)min = 180/11 min = 16 + 4/11 min.
So min space = 15(5, 10, 15 - 1, 2, 3)
Visualize relative speed. There are two trains. One is goods train 15 km away travelling at 5/60 km per min.
And there is another train which is travelling at 1 km per minute.
Relative speed = (1-5/60)kmph.
= 55/60 = 11/12.
time = distance/speed = 15/(11/12)min = 180/11 min = 16 + 4/11 min.
(1)
Vinodh said:
8 years ago
Its very easy I am n. Vinodh kumar the formulae is x (x/11). So here x=3. We have to multiply with 5.
So 3*5=15.
Now x is 15 so as per formulae 15 (15/11) =16 (4/11).
So 3*5=15.
Now x is 15 so as per formulae 15 (15/11) =16 (4/11).
Sharanya said:
1 decade ago
In 60 minutes, the minute hand gains 55 minutes on the hour hand.
M.S.N Prasad Reddy said:
1 decade ago
@Sharanya
Can you explain this briefly please ?
Can you explain this briefly please ?
Shruti said:
5 years ago
55 min is there because.
In one hour (60 min), the minute hand is 55 min ahead of the hour hand.
In one hour (60 min), the minute hand is 55 min ahead of the hour hand.
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