Aptitude - Clock - Discussion
Discussion Forum : Clock - General Questions (Q.No. 5)
5.
How much does a watch lose per day, if its hands coincide every 64 minutes?
Answer: Option
Explanation:
55 min. spaces are covered in 60 min.
60 min. spaces are covered in | ![]() |
60 | x 60 | ![]() |
= 65 | 5 | min. |
55 | 11 |
Loss in 64 min. = | ![]() |
65 | 5 | - 64 | ![]() |
= | 16 | min. |
11 | 11 |
Loss in 24 hrs = | ![]() |
16 | x | 1 | x 24 x 60 | ![]() |
= | 32 | 8 | min. |
11 | 64 | 11 |
Discussion:
119 comments Page 4 of 12.
Aloo bonda said:
9 months ago
The speed is inversely proportional to time, if clock hands are fast they lose time and when clock hands are slow they gain time.
If the clock covers 60-minute spaces in 64 minutes instead of 65+ (5/11) then the clock is faster, hence losing time. (taking less time than actual time).
If the clock covers 60-minute spaces in 64 minutes instead of 65+ (5/11) then the clock is faster, hence losing time. (taking less time than actual time).
(3)
Gurunadam said:
1 decade ago
Generally hands will coincide every 1 hour:5min:(5/11)th of a minute.
According to the problem hands will coincide every 1hour:4min.
So the lose per 1 coincidence 1 min:(5/11)th of a minute.
Number of coincidences per day is 22.
So the lose per 1 day is 22min:(110/11) or is 32min.
According to the problem hands will coincide every 1hour:4min.
So the lose per 1 coincidence 1 min:(5/11)th of a minute.
Number of coincidences per day is 22.
So the lose per 1 day is 22min:(110/11) or is 32min.
Dasun Umayanga said:
8 years ago
2 hands coincide after 65+5/11 minutes in real but here it is 64 minutes.
(Coincident. Two lines or shapes that lie exactly on top of each other)
which means 1+5/11 lose per hour.
this coincides happen 22 times in a day.
which means total lost per day (1+5/11)*22=32 min.
(Coincident. Two lines or shapes that lie exactly on top of each other)
which means 1+5/11 lose per hour.
this coincides happen 22 times in a day.
which means total lost per day (1+5/11)*22=32 min.
Jay said:
7 years ago
2 hands coincide after 65+5/11 minutes in real but here it is 64 minutes.
(Coincident. Two lines or shapes that lie exactly on top of each other)
which means 1+5/11 lose per hour.
this coincides happen 22 times in a day.
which means total lost per day (1+5/11)*22=32 min.
(Coincident. Two lines or shapes that lie exactly on top of each other)
which means 1+5/11 lose per hour.
this coincides happen 22 times in a day.
which means total lost per day (1+5/11)*22=32 min.
(1)
CERS said:
7 years ago
Soln;
1 min = 60/55 same as 12/11.
We have now:
(12/11)(60)
= 720/11.
(720/11) " every 64 min.
= 16/11,
(16/11)(1/every 64 min).
1/44 min using conversion for in 1day
= (1/44 min)(60 min/1hr.)(24hr/1 day)
32.272 in the 1-day loss,
Using fraction.
32.272= 32(8/11).
1 min = 60/55 same as 12/11.
We have now:
(12/11)(60)
= 720/11.
(720/11) " every 64 min.
= 16/11,
(16/11)(1/every 64 min).
1/44 min using conversion for in 1day
= (1/44 min)(60 min/1hr.)(24hr/1 day)
32.272 in the 1-day loss,
Using fraction.
32.272= 32(8/11).
(1)
Sugavasan said:
2 years ago
The difference between time is 4min here.
Between 60 and 64 min, and I'd we take;
4min × 24 = 96, 96 is now common between.
60 and 64 min like 4 min, we need to find the difference for 64 min, so;
(64/24) × 96 = 256 =>32/11×8.
Between 60 and 64 min, and I'd we take;
4min × 24 = 96, 96 is now common between.
60 and 64 min like 4 min, we need to find the difference for 64 min, so;
(64/24) × 96 = 256 =>32/11×8.
(20)
Akgarhwal said:
9 years ago
Watch coincide every 65 5/11 min
Loss in 64 minutes= (65 5/11- 64)= 16/11
Loss in 1 minute= (16/11) * (1/64)
Loss in 60 minute or 1 hr = (16/11) * (1/64) * 60,
Loss in a day or 24 hours = (16/11) * (1/64) * 60 * 24 = 32 8/11 min.
Loss in 64 minutes= (65 5/11- 64)= 16/11
Loss in 1 minute= (16/11) * (1/64)
Loss in 60 minute or 1 hr = (16/11) * (1/64) * 60,
Loss in a day or 24 hours = (16/11) * (1/64) * 60 * 24 = 32 8/11 min.
(1)
Sonam said:
1 decade ago
Gain or loss per day = (720/11-m) (60*24/m).
M: Interval at which minute hand overtake the hour hand.
If result positive indicate positive otherwise negative.
= (720/11-64) (60*24/64).
= (16/11) (60*24/64).
= 32 (8/11).
M: Interval at which minute hand overtake the hour hand.
If result positive indicate positive otherwise negative.
= (720/11-64) (60*24/64).
= (16/11) (60*24/64).
= 32 (8/11).
(1)
Twinkle said:
10 years ago
Using unitary method:
720/11 minutes of correct clock = 64 mins of incorrect clock.
Therefore 24*60 mins of correct clock = (64*24*60*11)/720 which gives 32 minutes exactly.
Where is discrepancy in this method?
720/11 minutes of correct clock = 64 mins of incorrect clock.
Therefore 24*60 mins of correct clock = (64*24*60*11)/720 which gives 32 minutes exactly.
Where is discrepancy in this method?
Moredhvaj said:
10 years ago
In 720/11 minutes.....incorrect clock gain (720/11-64) = 16/11.
In 1 minutes.....incorrect clock gain= (16/11)*(11/720).
In 24 hour.....incorrect clock gain = (16/11)*(11/720)*24*60.
= 32 min exactly.
In 1 minutes.....incorrect clock gain= (16/11)*(11/720).
In 24 hour.....incorrect clock gain = (16/11)*(11/720)*24*60.
= 32 min exactly.
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