# Aptitude - Clock - Discussion

Discussion Forum : Clock - General Questions (Q.No. 5)
5.
How much does a watch lose per day, if its hands coincide every 64 minutes?
 32 8 min. 11
 36 5 min. 11
90 min.
96 min.
Explanation:

55 min. spaces are covered in 60 min.

 60 min. spaces are covered in 60 x 60 min. = 65 5 min. 55 11

 Loss in 64 min. = 65 5 - 64 = 16 min. 11 11

 Loss in 24 hrs = 16 x 1 x 24 x 60 min. = 32 8 min. 11 64 11

Discussion:
115 comments Page 1 of 12.

AMAN said:   3 months ago
Agree @Abdeali Chitalwala.

You are absolutely right.
(2)

Rishi KSM said:   5 months ago
@Dawa Tshering.

Total minutes per day: 24 x 60 = 1440.

Minute and hour hands coincide 22 times per day so, 1440/22.
= 720/11,
= 65 5/11.

Here in question, it coincides every 64 mins.
So, loss in every coincide is;
65 5/11 - 64 = 16/11 or 1 5/11.

Till this you are correct!

However the no of coincidence per day is 22 for a normal clock.
In this peculiar clock, the coincidence happens every 64 mins.
Therefore, in 24 hours the no of coincidence is ( 24*60)/64 which is 22.5.
That means in 24 hours, this peculiar clock coincides 22.5 times.

Loss per every coincide x number of coincide per day = total loss.
So, 16/11 x 22.5 = 32 8/11 mins per day.
(16)

Sugavasan said:   9 months ago
The difference between time is 4min here.
Between 60 and 64 min, and I'd we take;
4min × 24 = 96, 96 is now common between.
60 and 64 min like 4 min, we need to find the difference for 64 min, so;
(64/24) × 96 = 256 =>32/11×8.
(12)

Dawa Tshering said:   10 months ago
Total minutes per day: 24 x 60 = 1440.

Minute and hour hands coincide 22 times per day so, 1440/22 = 720/11 = 65 5/11.

Here in question, it coincides every 64 mins.
So, loss in every coincide is;
65 5/11 - 64 = 16/11 or 1 5/11.

Therefore,
Loss per every coincide x number of coincide per day = total loss per day.
So, 16/11 x 22 = 32 mins per day.

@All
Please, anyone, explain me why divided by 64 and multiply by 24 and 60.
(23)

Sri iyer said:   2 years ago
@Jess.

See for an hour the min hand has to travel 60 spaces(ticks) right?

And for the same hour, the hour hand travels only 5 spaces(ticks).
So the actual displacement by both in the same direction is = the difference between the spaces travelled.

then, the time spaces travelled is 60-5=55 min(representing each tick, not the actual minute) spaces.

And the total minute spaces travelled for a minute is 60/55 right?

then, for an hour it is (60/55)*60 which is equal to 720/11 = 65.4545 giving the time for each coincidence of the min and hour hand.

If the given value(coincidence time) is >65.4545 means your watch is losing time i.e. clock is slower.

If the given value is <65.4545 means your watch is gaining time i.e. clock is faster
Here the coincidence time is 64 hence, 65.4545 - 64 = 1.4545 this is for 64 mins.
Then for a minute, the time variation is 1.4545/64.
And to get the same for a day we multiply by 60 and 24.

Hence,
Time lost is (1.4545/64)*60*24 = 32.7272=32(8/11) min.
(36)

Jess said:   2 years ago
(6)

Raghu said:   2 years ago
Well explained & very simple. Thanks @Shivangi.
(1)

Arjun Mandavkar said:   2 years ago
It's a proven fact that for a normal clock after every 720/11 = 65.4545 minutes both minute and hour hand meet.

In this case, the hour and minute hands are meeting after every 64 minutes which is less than 65.4545.

This clearly indicates the clock is going faster.

For every hour the clock is gaining 720/11 - 64 = 16/11 = 1.4545 minutes.

Hence, for 24 hours it will gain 24 * 16/11 = 34.909 = 34 10/11.
(12)

Vedant S. Koladiya said:   3 years ago
Hello @Konxie,

Why to find loss per minute? Can't we just multiply with 24?
Like, 1.45* 24...