### Discussion :: Clock - General Questions (Q.No.5)

K.Kiran Kumar said: (Aug 4, 2010) | |

I cant get the question what it means. Please someone try to explain it. |

Ravi said: (Aug 24, 2010) | |

I can't understand this: (60/55*60) why this step is used. Please someone explain me? |

Tarak B Patel said: (Aug 25, 2010) | |

Solution: In 1 hour both the hands cover 55 min space. => 60/55 = 12/11 min space covered in 1min of the actual time. for the hand to coincide hands have to cover 60 min space => 12/11 * 60 = 720/11 = 65.5/11 min in actual clock. But the clock coincides every 64 min. =>65.5/11 - 64 = 1.5/11 = 16/11 min loss in 64min. =>16/11 * 1/64 = 1/44 min loss in 1min. Loss In 24 Hrs => 1/44 * (24 *60) = 360/11 = 32.8/11 min the clock looses in a day. |

Soumya said: (Jan 12, 2011) | |

Why we multiply 1/64 ? |

Priya said: (Jun 24, 2011) | |

How 55 spaces in 60 mins? couldnt get that. |

Sharat said: (Dec 14, 2011) | |

What is this min. space? Does it mean the min. hand lags the hour by 5 min. space ? |

Maddy said: (Jan 13, 2012) | |

To coincide with each other space(ticks) between them should be ZERO(no space). Consider starting from 12 noon. in 1 hr--> min hand covers spaces(ticks) =60 in 1 hr--> hour hand covers spaces(ticks) = 5 so in 1 min --> hour hand covers 5/60=1/12 space(tick) so after 1 hr=60 mins (1.00) spaces between them will be equal to 5 so have to cover 5 places for minute hand to meet hour hand total time = 60+5 ... but in 5 mins hour hand will further go ahead by 5*1/12 ticks so have to cover 5/12 ticks for minute hand to meet total time = 60+5+5/12 ... but agin in 5/12 mins hour hand will go ahead buy 5/12*1/12= 5/12^2... and so on So total time will be = 60+5+(5/12+5/12^2+5/12^3+.........) this GP total time to meet = 720/11 i.e., 65.(5/11). This time required to coincide hands in correct clock... solve accordingly. |

Karthik said: (Mar 21, 2012) | |

How can the watch lose time if it is covering earlier than what is expected? |

Himanshu Dewangan said: (Mar 26, 2012) | |

It is universal truth that watch does not lose any time.Every day start from 12:00 am in night, hr. and min hand positioned at 0 degree,than how lose? no lose is there.. But suppose hands coincide every 64 min. (In really it is not possible..eg if ones they coincide it take 65+5/11 min always for next) there will be lose of 65+5/11 - 64= 16/11 from actual or real time in 65+5/11 min. So calculate lose in 1 day= 24*60 min |

Vallaban said: (Apr 4, 2012) | |

55 min. Spaces are gained by minute hand in 60 min period. To find how many spaces it has actually gained, we need to fix a standard point first. ! With respect to it, we need to see the difference by how much is it actually varying. ! So let us assume the standard point to be the place where the minutes hand and hours hand has been coincided. ! I may be 12:00, 1.06, 2.11, 3.17. etc. from there. 60 minutes implies the minute hand must come back to the same point where it has started. ! Is it not. ? Now, 60 minute passed and so minute hand covers 60 minute spaces. And the hour hand advances by 5 minute spaces. ! So from the standard point fixed initially (we assumed the standard point is where the minute point and hours hand were coinciding. Also. 60 minutes will be passed when the minute hand comes back to the same position from where it started). Now, there is. An absolute 60 min spaces covered by minute hand in 60 min and then there is 5 min spaces advanced by hour hand in 60 min period. ! So on total. Total advancement is 60-5 = 55 minute spaces. ! |

Prasant said: (Apr 13, 2012) | |

Pleaes clarify, whether the clock looses or gain in this question? |

Naresh said: (May 30, 2012) | |

A watch which gains uniformly, is 5 minutes slow at 8 o' clock in the morning on Sunday and it is 5 min. 48 sec fast at 8 p. M. On following Sunday. When was it correct? |

Konxie said: (Jun 7, 2012) | |

Say its 12 o' clock: The minute hand and the hour hand points towards 12 After an hour i.e at 1 o' clock: The minute hand points at 12 and the hour hand points 1 The difference between the two hands after 60 min (1 hr) is 55 spaces but the hands did not coincide! They will coincide when 60 spaces are covered And to cover 60 spaces it takes = (60/55*60) = 65.4545 min (in a normal clock) Now given in question is that the hands coincide at 64 min (defective clock) So loss in time when the hands coincide is 65.4545 - 64 = 1.4545 min (this loss happens for every 64 min in our defective clock) So for 1 min our loss is = 1.4545/64 min For a day 1.4545/64*(24*60) = 32.7 min @Naresh : just remember this If coinciding time > 65(5/11) then our clock is going slow than normal (our watch is loosing time) and if coinciding time < 65(5/11) then its going fast than normal (or gaining time). By 65(5/11) i mean 65.4545 and not (65*5)11 And we say loosing time in questions just to state the irregularity in time. HOPE THIS CLEARS IT ALL |

Dinesh said: (Jul 29, 2012) | |

Well said Konxie. |

Priya said: (Aug 31, 2012) | |

I can't understand this problem 65*5/11-64 |

Sachin said: (Jan 1, 2013) | |

First consider in how many minutes, hands should coincide. 55 min. spaces are covered in 60 min. 60 min. spaces will be covered in, 65 (5/11) i.e. 65.45 minutes. But this clock is taking 64 minutes to coincide hence it is 1.45 min slow to actual time (65.45-64=1.45). In 64 min of journey clock is 1.45 min slow, then in 24*60 min it will 32.62 min slow. =(24*60*1.45*1)/64= 32.62 or 32(8/11). |

Koti said: (Feb 24, 2013) | |

I am not able to understand how 55 min. Spaces are gained by minute hand in 60 min period. Can anybody explain? |

Amit said: (May 16, 2013) | |

Just imagine hour hand and minute hand starting at 12 O'clock. After 1 hour, the minute hand will be at 12 whereas the hour hand will be at 1. So what is the difference between them? it's 55 "Minute Space". So, it takes 1 hour to cover 55 minute spaces, for overlapping they should cover total 60 minute space. Thus, here is the calculation: 1 hr --> 55 minute space. ? hr --> 60 minute space. (1*60) /55 hour = 60/55 * 60 minute // converting hr to mins. = 65 5/11 minute. |

Yuriy said: (Jul 15, 2013) | |

Why does everybody say that the minute hand does a complete circle in exactly 1 hour, when it is evidently not so (since the clock is losing time)? The solution should be like this: Let Wm be the angular speed of the minute hand, in radians per astronomical minute, and Wh be the angular speed of the hour hand. The constraint of the clock mechanism requires that Wh=Wm/12 (per each full revolution of the hour hand, the minute hand makes 12 full revolutions). The requirement that the hands meet every 64 minutes is: Wm*t = Wh*t + 2*pi, where t=64 astronomical minutes (astronomical minutes = actual minutes!). Hence we have Wm*(11/12) = 2*pi/64, or Wm = 2*pi*(12/11/64) rad/ast. minute, giving a period of revolution of (11/12)*64 = 58.6(6) astronomical minutes per revolution. In 1 astronomical hour the minute hand covers Wm*60 = 2*pi*(60/64)*(12/11) radians, or simply 90/88=1+1/44 of a full revolution. Thus after each astronomical hour the minute hand shows 1/44*60 "clock minutes" more than the number of astronomical minutes passed. In other words, each astronomical hour the clock GAINS 15/11 of a minute. Thus it GAINS (15/11)*24 = 32+8/11 clock minutes per astronomical day (i.e., each astronomical day it shows time which is 32+8/11 minutes more than the actual astronomical time). |

Surya said: (Aug 6, 2013) | |

Walking at 4/5 of his usual speed a man is 10 min too late. Find his usual time? |

Abhilash said: (Dec 5, 2013) | |

My 2 cents: So far we know that it takes 60 min for the minute hand to gain a 55 min space lead over the hour hand. We assume that a 60 min space lead actually means that the two hands coincide. The time required for a 60 min space lead would be 60*60/55 min for a normal clock. Instead of this, the error clock has a time requirement of 64 min for the min hand to gain a 60 min space lead over the hour hand. With this new value we now try to calculate how many minutes the error clock would take for it's min hand to gain a 55 min space lead. Basically- "how many minutes of the error clock would signify i hour for the normal clock?" This works out to be 64*55/60 min..which is 58.6666 min. So for a normal clock which counts 60 minutes (1 hour), the error clock has clocked up 60/58.6666 min(1.022 hours). Over a period of 24 hours, the error clock has would gain 24*1.022 hours=24.4545 hours. The difference being 24.4545-24 hr Which is equal to .4545 hr = .4545*60 min = 32.72 min ~32 8/11 . |

Nauman said: (Dec 6, 2013) | |

Simple solution. Don't get confused. Just remember that in normal clocks the minute hand and the hour hand universally takes. (6.5/11) minutes to coincide. But in error clock it takes only 64 mins. Hence the time lost is 6.5/11-64 = 16/11. Now the total mins in a day are 24*60 = 1440. Now divide 1440 in equal parts of 64. i.e 1440/64 = 22.5. Therefore. The error in 64 mins was 16/11. Hence the error in 1440 mins is = 22. 5*16/11 = 32.8/11. Simple. |

Moksha Shridhar said: (Mar 17, 2014) | |

I am unable to understand this question what is it? |

Raman said: (May 17, 2014) | |

I can't understand this question please explain in easy language. |

Manpreet Kaur said: (Jun 3, 2014) | |

@Raman, We know that the two hands (hour hand and min hand) of a clock coincide after 60 mins. The question here is if the hands of the clock coincide after every 64 mins instead of 60 mins, how much time the clock/watch will lose in a day. From the above comments, I can see many people are confused that if the hands coincide after every 64 mins instead of 60mins, then how come the clock/watch is losing time! If the hands are coinciding after 64 mins instead of 60 mins, it means they are taking more time to coincide. The longer the hands take to coincide, the more time they lose. Say for example, the time is 12 pm. In normal clock it will take 60 mins for the hands to coincide, that is to strike 1 pm. Now, as given in the example, if the hands coincide after 64 mins, it means the clock/watch will strike 1 pm after 64 mins instead of 60 mins. So it means where it took 60 mins to complete one hour, it is taking 64 mins. So here it is losing time. Hope, this helps! :). |

Ayesha said: (Jul 5, 2014) | |

Why multiplied with 1/64 in last step? |

Manmohan Mahapatra said: (Jul 24, 2014) | |

This is gaining clock because it moves faster than original clock. Explain me. |

Harish said: (Aug 29, 2014) | |

How to find the mirror image when the time is 8:40? |

Sapy said: (Sep 2, 2014) | |

Imagine the hour and minute hand in case of 8:40, and divide the clock into 4 quarters (Each quarter defined from 12 to 3, 3 to 6, 6 to 9 and 9 to 12). When u are seeing the clock, the time 8:40 is basically at the one to the left hand, bottom quarter(ie. in between 6 to 9) while its mirror image should be at the right hand bottom quarter(ie. between 3 to 6). Since in a mirror image the one's in the left side take the position to your right, while those in the right side shifts to the left, hence 8:40 will correspond to 3:20 in the mirror image. |

Gurunadam said: (Sep 25, 2014) | |

Generally hands will coincide every 1 hour:5min:(5/11)th of a minute. According to the problem hands will coincide every 1hour:4min. So the lose per 1 coincidence 1 min:(5/11)th of a minute. Number of coincidences per day is 22. So the lose per 1 day is 22min:(110/11) or is 32min. |

Shivangi said: (Oct 4, 2014) | |

The universal rule is , hands of any accurate clock meets after 65 5/11 [=(11*65+5)/11] minutes. But here the clock is taking 64 minutes to meet ! Hence , the error is [65 5/11]-[64] mints -> 16/11 minutes . Now , total minutes in a day is = 24 hrs* 60 minutes= 1440 minutes. Now, we know , the error in 64 mins was --> 16/11. Means in 1 min ---> 16/11*1/64. So in 11440 mins---> (16/11*1/64)*11440. Which equals to ---> 360/11 Answer. |

Apurba said: (Dec 16, 2014) | |

How can coincide 24 times in a day, any one can explain? I think it may coincide 23 times in a day, but only meet 24 times in a day. |

Prasanth said: (Jan 8, 2015) | |

What does "55 min spaces" mean? I can't get it. I understand the clock concept like this. -->Hour hand covers 0.5 degree in 1 min. -->Min hand covers 6 degrees in 1 min. -->Sec hand covers 360 degrees in 1 min. And I used to solve all problems using this theory. But I can't get this min spaces concept. Some one help me. |

Vivek G Shivhare said: (Jan 24, 2015) | |

This some's difficulty is bit high, that's why here we have to consider relative speeds of hands of clock. Not separate got it? |

Vijender said: (May 21, 2015) | |

@Harish. To find mirror image of a given time, there are two approaches, one is to draw the clock on paper indicating the time given and then find the mirror image of the hour hand and minute hand. This is time consuming. The other method requires you only to subtract the given time from 12:00, and result will be your answer. For the example you've given 8:40. Subtract it from 12:00, we'll have 3:20 which is the right answer. |

Vijender said: (May 21, 2015) | |

This question is wrong. If the hands coincide every 64 minutes, then it should be a gaining clock. So how could a gaining clock lose time? |

Debdeep said: (May 29, 2015) | |

Exactly @Vijendar. I doubt in that point too. But it take me quite time. Also the statement would be I think: "Gain in 65*5/11 is 16/11 min". |

Sagnik Chatterjee said: (Jun 12, 2015) | |

Can anyone make me understand this? |

Aum Jena said: (Aug 8, 2015) | |

Can anyone make me explain the last step? |

Girish said: (Aug 25, 2015) | |

I can't understand 65 5/11 how 5/11 is anybody explain? |

Sonam said: (Aug 29, 2015) | |

Gain or loss per day = (720/11-m) (60*24/m). M: Interval at which minute hand overtake the hour hand. If result positive indicate positive otherwise negative. = (720/11-64) (60*24/64). = (16/11) (60*24/64). = 32 (8/11). |

Indra said: (Sep 3, 2015) | |

@ Shivangi is absolutely right. Check her explanation. Its easily explained. Even now if you don't understand how 55 min are covered in 60 min then here is simple explanation. Take it as a metaphor. Assume hour hand to be tortoise and minute hand to be hare. Now after 60 seconds you will see that hare had traveled 60 minute distance while tortoise had traveled only 5 minute distance. So you can say hare gained 55 minute or 55 spaces to tortoise. So finally you can say minute hand gained 55 spaces to hour hand. |

Naresh said: (Sep 28, 2015) | |

How much can a watch gain or loss per day if its hand coincide every 65 minutes? Can anyone explain this please? Thanks in advance. |

Twinkle said: (Oct 12, 2015) | |

Using unitary method: 720/11 minutes of correct clock = 64 mins of incorrect clock. Therefore 24*60 mins of correct clock = (64*24*60*11)/720 which gives 32 minutes exactly. Where is discrepancy in this method? |

Dharmendra Nath said: (Dec 11, 2015) | |

Why it is not correct 24*4=96? |

Moredhvaj said: (Dec 30, 2015) | |

In 720/11 minutes.....incorrect clock gain (720/11-64) = 16/11. In 1 minutes.....incorrect clock gain= (16/11)*(11/720). In 24 hour.....incorrect clock gain = (16/11)*(11/720)*24*60. = 32 min exactly. |

Manab said: (Jan 14, 2016) | |

Direct formula: Gain or loss = (720/11-m) (60*24/m). Here m = 64, Hence (720/11-64) (60*24/64) = (65.45-64) (45/2) = 1.45*22.5 = 32.625. |

Manab said: (Jan 14, 2016) | |

Formula for (720/11-m) (60*24/m)? |

Suma said: (Jan 23, 2016) | |

Well Said @Manpreet, @Twinkle, @Abhilash. But @Abhilash can you please elaborate how the step 64*55/60 came? |

Kanishk said: (Feb 17, 2016) | |

I think question should be "How much does a watch gain per day". Because lose means it loses 16/11 min from 65 (5/11). |

Tilak Dewangan said: (Mar 23, 2016) | |

If hands coincide earlier than expected time, how I'd losing time? |

Deepa said: (Mar 30, 2016) | |

How fast or slow is the hand moving? like this problems I need to know please help me. |

Gowtham said: (May 18, 2016) | |

Please help me to know the completion of the problem within 1 minute. |

Harish Udupa S said: (Jul 7, 2016) | |

Hands coincide every 65 min 27 secs (google it for proof) but here it happens every 64 min. So it runs behind by 1 min 27s so for every 65 min 27 secs (3927s) there's delay of 1 min 27s (87). Hence, for 24 hrs (86400s) there will be 87 * 86400/3927 = 1914.1329s = 31.90221 min, that's roughly 31 9/10min. These type of questions won't be asked anyway. |

Sanjeev said: (Jul 13, 2016) | |

Say its 12 o' clock: The minute hand and the hour hand points towards 12. After an hour i.e at 1 o' clock: The minute hand points at 12 and the hour hand points 1. The difference between the two hands after 60 min (1 hr) is 55 spaces but the hands did not coincide. They will coincide when 60 spaces are covered. And to cover 60 spaces it takes = (60/55 * 60) = 65.4545 min (in a normal clock). Now given in question is that the hands coincide at 64 min (defective clock). So, loss in a time when the hands coincide is 65.4545 - 64 = 1.4545 min (this loss happens for every 64 min in our defective clock). So for 1 min our loss is = 1.4545/64 min. For a day 1.4545/64 * (24*60) = 32.7. If coinciding time > 65(5/11) then our clock is going fast than normal (our watch is losing time) and if coinciding time < 65(5/11) then it's going slow than normal (or gaining time). By 65(5/11) I mean 65.4545 and not (65*5)11. And we say losing time in questions just to state the irregularity in time. |

Ankit said: (Jul 19, 2016) | |

Why we multiply it by 1/64? |

Aks said: (Jul 21, 2016) | |

WHETHER THE CLOCK HAS GAINED OR LOST TIME? We know from the calculation above that the two hands of the clock coincide every 65.45 mins. But here it is mentioned that they meet every 64mins in the defective clock. => the clock is going fast. => in 24 hours it would be actually showing more than 24hours. => the clock has gained time! |

Raju said: (Aug 7, 2016) | |

I guess it is the wrong question because when hands coincide after 64 min I, e < 64 5/11 then clock will gain. |

Shivanand said: (Aug 20, 2016) | |

@Harish. To find mirror time jus subtract given time as ==>hour time by 11 and min time by 60. You'll get the answer for ex 10.25.11- 10 = 1 & 60 - 25 = 35 so the time will be 1.35. |

Rohitha said: (Aug 29, 2016) | |

I can't get the question what it means? Please someone try to explain it. |

Karan Singh Saud said: (Sep 11, 2016) | |

Very simple question. A clock coincides 11 times in 12 hrs (720 min). So, per meeting =720/11 (65.45). i.e hands coincide after every 65.45 min. But according to the question. Hands coincide every 64 min. So clock losses 1.45 min for every meeting. And we know that hands coincide 22 times a day. So. Answer = 22 * 1.45. (I guess this is correct). |

Shiva said: (Sep 29, 2016) | |

Use this you will get any problem solved from clock M * 6° ~ (h + m/60) * 30°= Angle. |

Sapnaa said: (Sep 29, 2016) | |

It actually does not cover 55 min space in 1 hr it covers 56.25 min space in 1 hr. |

Krishna said: (Oct 6, 2016) | |

How could you all get 720/11 - 64 = 16/11? Please explain. |

Vijeshri said: (Oct 9, 2016) | |

@Krishna 64 * 11= 704. 720 - 704/11 = 16/11. |

Anonymous said: (Oct 12, 2016) | |

I didn't understand. Please clarify me. |

Rohit Dubey said: (Oct 22, 2016) | |

Please solve it by the tricky method. |

Vishal said: (Oct 23, 2016) | |

Well done @Konxie. |

Akgarhwal said: (Dec 6, 2016) | |

Watch coincide every 65 5/11 min Loss in 64 minutes= (65 5/11- 64)= 16/11 Loss in 1 minute= (16/11) * (1/64) Loss in 60 minute or 1 hr = (16/11) * (1/64) * 60, Loss in a day or 24 hours = (16/11) * (1/64) * 60 * 24 = 32 8/11 min. |

Chetan Minajigi said: (Jan 13, 2017) | |

Thanks @Maddy. |

Ramu said: (Jan 26, 2017) | |

Thanks for explaining the answer. |

Anand Moghe said: (Feb 13, 2017) | |

I think the question is incorrect. It is like this: A correct clock will have a time gap of (720/11 = 65 and 5/11) minutes between two successive overlaps of the hours hand and the minute hand. IF this time is being covered by the incorrect clock in 64 minutes (64 < 65 5/11), then the incorrect clock is gaining time, not losing time. What should have been covered in 65 5/11 mins is now being covered in 64 mins. Thus the time gained in 65 5/11 minutes is 1 5/11 minutes (=16/11). So the time gained in 24 hrs (1440 minutes) is (1440 * (16/11) * (11/720) = 32 mins. I believe when the incorrect clock covers a specified (correct) time in lesser (incorrect) time, then the incorrect clock is gaining time. The answer must be : clock gains time of 32 mins per day. |

Anand S Moghe said: (Feb 13, 2017) | |

I have a small correction to offer to my previous explanation. In 64 mins of correct time, the watch shows to have covered 65.5/11 mins. So the watch runs faster. Hence the time is gained. In 64 mins the time gained is 1.5/11 min. So in 24 hrs (1440 mins) the time gained is 1440*(16/11)*(1/64) = 32.8/11 mins. So the time is GAINED, not lost, as per my understanding. |

Amit Kumar said: (Feb 14, 2017) | |

I think the clock is gaining time. Because, instead of meeting after 65 5/11, it is meeting in 64 minutes only. Hence the question, "what time it looses is wrong". |

Sushma said: (Mar 29, 2017) | |

I am not understanding this question. Please, anybody explain me. |

Surjeet Murmu said: (May 8, 2017) | |

Here, I think there will be gain in time. Not a loss in time. |

Pooja Armo said: (Jun 22, 2017) | |

Please explain that 55 min space concept. I am not getting it properly. |

Bajpai said: (Jul 16, 2017) | |

I am unable to get the concept of -55 min space covered in 60 min. As well as the question about hands coincide every 64 min refers to? |

Arana said: (Jul 17, 2017) | |

Please explain me why in last step it is multiplied with 1/64? |

Mukul said: (Aug 13, 2017) | |

The minute hand of a clock overtakes the hour hand at intervals of M minutes of correct time. The clock gains or loses in a day by=(72011/M)(60 * 24M) minutes. |

Rsatish1110 said: (Sep 13, 2017) | |

It should be gain,not lose. |

Manoj Kumar said: (Nov 18, 2017) | |

Why do we multiply by 1/64? |

Dasun Umayanga said: (Dec 10, 2017) | |

2 hands coincide after 65+5/11 minutes in real but here it is 64 minutes. (Coincident. Two lines or shapes that lie exactly on top of each other) which means 1+5/11 lose per hour. this coincides happen 22 times in a day. which means total lost per day (1+5/11)*22=32 min. |

Smz said: (Jan 7, 2018) | |

As per the given question the clock is not losing the time, where as it is gaining the time. Actual clock coincide for every 65 5/11min where as this faulty clock coinciding for every 64th min. That means this clock is running faster than the actual clock so the answer comes exactly 32min not 32 8/11min. |

Pooja Tiwari said: (Feb 26, 2018) | |

I am not understanding it. Will anyone explain me? |

Saviour24 said: (May 11, 2018) | |

Why we multiply 1/64 at the end? Please explain. |

Rohit said: (May 20, 2018) | |

The clock gains. Agree with you @Rsatish1110. |

Rashmika said: (Jun 8, 2018) | |

@Harish. Subtract 8:40 from 11:60. |

Jay said: (Jun 29, 2018) | |

2 hands coincide after 65+5/11 minutes in real but here it is 64 minutes. (Coincident. Two lines or shapes that lie exactly on top of each other) which means 1+5/11 lose per hour. this coincides happen 22 times in a day. which means total lost per day (1+5/11)*22=32 min. |

Jay said: (Jun 30, 2018) | |

Use the formula. Clock gain or loss: 720/(11-M)*(24*60)/M. |

Anonymous said: (Aug 22, 2018) | |

@Jay. What is the value for M in this question. |

Rithun said: (Sep 13, 2018) | |

Well said, Thank you @Konxie. |

Tiwari said: (Sep 19, 2018) | |

Use this formula for solving this. (720/11-M)(60*24/M). |

Jamal said: (Sep 28, 2018) | |

I am not understanding the concept, can anyone explain it? |

Kalyani said: (Dec 13, 2018) | |

I am not understanding this problem. Please explain me. |

Cers said: (Jan 16, 2019) | |

Soln; 1 min = 60/55 same as 12/11. We have now: (12/11)(60) = 720/11. (720/11) " every 64 min. = 16/11, (16/11)(1/every 64 min). 1/44 min using conversion for in 1day = (1/44 min)(60 min/1hr.)(24hr/1 day) 32.272 in the 1-day loss, Using fraction. 32.272= 32(8/11). |

Shahaji said: (Apr 30, 2019) | |

Actual time of overtake/coincide = 65 5/11 min. False clock overtakes/ coincide = 64 min. For every 65 5/11 min of actual time false watch gains 1 5/11 min= 16/11 min time. therefore in a day that is 24 hrs time gained will be; 65 (5/11)/24 = 1 (5/11)/x. x = 32 minutes gain in 1 day. |

Gagan said: (May 25, 2019) | |

The hands coincide 22 times a day soo instead of 24. 22 should be used as ( (720/11) -64) *24*60. The answer would be 32 mins. |

Soni said: (Dec 13, 2019) | |

Is there any formula to solve this? |

Sangeetha said: (Dec 31, 2019) | |

Use this formula, ((720/11)-M) x 24 x 60/M. Here M is 64. |

Ram Gopal Nadakuditi said: (Jan 24, 2020) | |

The two hands of a clock coincide after a gap of every 65 5/11 minutes. For example, if we consider the starting time at 12 . the two hands coincide exactly at 12. Again after 65 5/11 minutes both coincide. Means exactly at 1 5/11 minutes. In the problem, the two hands of a clock coincide after 64 minutes give. It means the clock is faster than usual. It means it is gaining time. For Every 64 minutes the clock gains 65 5/11- 64 = 1 5/11 = 16/11 minutes. It GAINS not Loses. So in the problem, for 64 mints clock gains ( faster) 16/11 minutes. Then it gains how much per day? ( for 24*60 hrs) Answer = {24*60 *16/11 }/64. = 32 8/11 mints. |

Mari said: (Apr 27, 2020) | |

You explanation is nice. Thank you @Konxie. |

Katherin said: (Sep 22, 2020) | |

As per the formula, it is; ((720/11) -64) * ( (60*24) /64). |

Sonu said: (Jan 24, 2021) | |

How to get 1.5/11 from 16/11? Please explain. |

Abdeali Chitalwala said: (Feb 3, 2021) | |

The clock is GAINING 1 and 5/11 mins every hour and not losing. There's an error in the question. Hence, the clock will GAIN 32 and 8/11 mins in one day. |

Sheetanshu said: (Mar 19, 2021) | |

Thanks for explaining @Maddy. |

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