Aptitude - Clock - Discussion
Discussion Forum : Clock - General Questions (Q.No. 5)
5.
How much does a watch lose per day, if its hands coincide every 64 minutes?
Answer: Option
Explanation:
55 min. spaces are covered in 60 min.
| 60 min. spaces are covered in |  |
60 | x 60 |  min. |
= 65 | 5 | min. |
| 55 | 11 |
| Loss in 64 min. = | |
65 | 5 | - 64 | |
= | 16 | min. |
| 11 | 11 |
| Loss in 24 hrs = | |
16 | x | 1 | x 24 x 60 | min. |
= | 32 | 8 | min. |
| 11 | 64 | 11 |
Discussion:
119 comments Page 12 of 12.
Jay said:
7 years ago
Use the formula.
Clock gain or loss:
720/(11-M)*(24*60)/M.
Clock gain or loss:
720/(11-M)*(24*60)/M.
Anonymous said:
7 years ago
@Jay.
What is the value for M in this question.
What is the value for M in this question.
Rithun said:
7 years ago
Well said, Thank you @Konxie.
Jamal said:
7 years ago
I am not understanding the concept, can anyone explain it?
Shahaji said:
6 years ago
Actual time of overtake/coincide = 65 5/11 min.
False clock overtakes/ coincide = 64 min.
For every 65 5/11 min of actual time false watch gains 1 5/11 min= 16/11 min time.
therefore in a day that is 24 hrs time gained will be;
65 (5/11)/24 = 1 (5/11)/x.
x = 32 minutes gain in 1 day.
False clock overtakes/ coincide = 64 min.
For every 65 5/11 min of actual time false watch gains 1 5/11 min= 16/11 min time.
therefore in a day that is 24 hrs time gained will be;
65 (5/11)/24 = 1 (5/11)/x.
x = 32 minutes gain in 1 day.
Soni said:
6 years ago
Is there any formula to solve this?
Mari said:
5 years ago
You explanation is nice. Thank you @Konxie.
Sonu said:
5 years ago
How to get 1.5/11 from 16/11? Please explain.
Sheetanshu said:
4 years ago
Thanks for explaining @Maddy.
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