Aptitude - Clock - Discussion

Discussion Forum : Clock - General Questions (Q.No. 5)
5.
How much does a watch lose per day, if its hands coincide every 64 minutes?
32 8 min.
11
36 5 min.
11
90 min.
96 min.
Answer: Option
Explanation:

55 min. spaces are covered in 60 min.

60 min. spaces are covered in 60 x 60 min. = 65 5 min.
55 11

Loss in 64 min. = 65 5 - 64 = 16 min.
11 11

Loss in 24 hrs = 16 x 1 x 24 x 60 min. = 32 8 min.
11 64 11

Discussion:
119 comments Page 10 of 12.

Anonymous said:   7 years ago
@Jay.

What is the value for M in this question.

Rithun said:   7 years ago
Well said, Thank you @Konxie.

Tiwari said:   7 years ago
Use this formula for solving this.

(720/11-M)(60*24/M).
(1)

Jamal said:   7 years ago
I am not understanding the concept, can anyone explain it?

Kalyani said:   7 years ago
I am not understanding this problem. Please explain me.
(1)

CERS said:   7 years ago
Soln;

1 min = 60/55 same as 12/11.

We have now:
(12/11)(60)
= 720/11.
(720/11) " every 64 min.
= 16/11,
(16/11)(1/every 64 min).

1/44 min using conversion for in 1day
= (1/44 min)(60 min/1hr.)(24hr/1 day)
32.272 in the 1-day loss,
Using fraction.
32.272= 32(8/11).
(1)

Shahaji said:   6 years ago
Actual time of overtake/coincide = 65 5/11 min.

False clock overtakes/ coincide = 64 min.

For every 65 5/11 min of actual time false watch gains 1 5/11 min= 16/11 min time.
therefore in a day that is 24 hrs time gained will be;

65 (5/11)/24 = 1 (5/11)/x.

x = 32 minutes gain in 1 day.

Gagan said:   6 years ago
The hands coincide 22 times a day soo instead of 24.

22 should be used as ( (720/11) -64) *24*60. The answer would be 32 mins.
(1)

Soni said:   6 years ago
Is there any formula to solve this?

Sangeetha said:   6 years ago
Use this formula,
((720/11)-M) x 24 x 60/M.
Here M is 64.
(2)


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