Aptitude - Clock - Discussion
Discussion Forum : Clock - General Questions (Q.No. 2)
2.
The reflex angle between the hands of a clock at 10.25 is:
Answer: Option
Explanation:
Angle traced by hour hand in | 125 | hrs = | ![]() |
360 | x | 125 | ![]() |
° | = 312 | 1 | ° | . |
12 | 12 | 12 | 2 |
Angle traced by minute hand in 25 min = | ![]() |
360 | x 25 | ![]() |
° | = 150°. |
60 |
![]() |
![]() |
312 | 1 | - 150 | ![]() |
° | = 360° - 162 | 1 | ° | = 197 | 1° | . |
2 | 2 | 2 |
Discussion:
269 comments Page 7 of 27.
Vasuroshan said:
1 decade ago
Nice expalnation guys. I have a known formula.
30H-(11/2)M where H----Hours
M----Minutes
So, sub.. 30(10)-(11/2)(25)
(600-275)/2=162.5
If the angle is <180 sub from 360 viceversa...
360-162.5=197.5
I Hope You guys can understand.
30H-(11/2)M where H----Hours
M----Minutes
So, sub.. 30(10)-(11/2)(25)
(600-275)/2=162.5
If the angle is <180 sub from 360 viceversa...
360-162.5=197.5
I Hope You guys can understand.
Sarah said:
1 decade ago
The formula is 6m-(30h+m/2) m=minutes h=hour.
For example 11:26.
6(26)-(30(11)+(26)/2).
156-(330+13).
156-343.
-187.
If you get a result that is negative, all it means is that the hour hand is ahead of the minute hand, simply multiply the answer by -1 and then subtract that from 360.
For example 11:26.
6(26)-(30(11)+(26)/2).
156-(330+13).
156-343.
-187.
If you get a result that is negative, all it means is that the hour hand is ahead of the minute hand, simply multiply the answer by -1 and then subtract that from 360.
Reshma john said:
1 decade ago
THERE IS A READY MADE FORMULA FOR THIS KIND OF PROBLEM:
1/2(60H-11M).
WHERE ,
H = HOUR
M = MINUTE.
Eg:10.30 can be written as
1/2(60*10-11*30).
As per problem.
1/2(60*10-11*25)
= 1/2(600-375)
= 1/2(325)
= 162.5.
In question it is asked reflex angle so,
= 360 - 162.5.
= 197.5.
1/2(60H-11M).
WHERE ,
H = HOUR
M = MINUTE.
Eg:10.30 can be written as
1/2(60*10-11*30).
As per problem.
1/2(60*10-11*25)
= 1/2(600-375)
= 1/2(325)
= 162.5.
In question it is asked reflex angle so,
= 360 - 162.5.
= 197.5.
Dhruba said:
9 years ago
The hour hand moves 1/2 degree every minute and 30 degrees each hour so after 10.25 the hour hand moves (10 * 30) + (25 * .5) = 312.5 degree.
Now the minute hand moves 6 degrees each minute so (6 * 25) = 150 degrees the reflex angle will be 360 - (312.5 - 150) = 197.5 degrees.
Now the minute hand moves 6 degrees each minute so (6 * 25) = 150 degrees the reflex angle will be 360 - (312.5 - 150) = 197.5 degrees.
ANAND MAURYA said:
8 years ago
Hour Hand: 10:25
1 Hour=30° 10*30=300°
1 Minute=1/2° 25*1/2=25/2°
(300+25/2)°;
Minute Hand: 25
1 Minute=6° 25*6=150°;
Angle b/w HH & MH = (300+25/2-150)°,
Reflexive Angle = [360-(300+25/2-150)]°,
Reflexive Angle = 197.5°.
1 Hour=30° 10*30=300°
1 Minute=1/2° 25*1/2=25/2°
(300+25/2)°;
Minute Hand: 25
1 Minute=6° 25*6=150°;
Angle b/w HH & MH = (300+25/2-150)°,
Reflexive Angle = [360-(300+25/2-150)]°,
Reflexive Angle = 197.5°.
Peeyush Kumar said:
2 months ago
To calculate angle : (60h - 11M)/2.
This formula is used to calculate the angle between the hour hand and minute hand.
For 10 : 25;
Using formula : ( 60 x 10 - 11 x 25 )/2,
= 325/2.
Reflex angle = 360 - 325/2 = 197.5.
So, the answer is 197.5.
This formula is used to calculate the angle between the hour hand and minute hand.
For 10 : 25;
Using formula : ( 60 x 10 - 11 x 25 )/2,
= 325/2.
Reflex angle = 360 - 325/2 = 197.5.
So, the answer is 197.5.
(16)
Avinash said:
7 years ago
We can find the angle between two hands with the help of bellow formula ( x*30) - (y*11)/2.
Here x is 10 and y is 25.
So by applying bellow formula, the angle between two hands is 162.5,
Now, angle at 10 'o clock is 300,
So, the reflex angle is 300- 162.5 = 197.5.
Here x is 10 and y is 25.
So by applying bellow formula, the angle between two hands is 162.5,
Now, angle at 10 'o clock is 300,
So, the reflex angle is 300- 162.5 = 197.5.
Fawad said:
8 years ago
BEST ANSWER:
Short hand or hour hand = 360/12 = 30,
Long hand or minute hand= 360/60 = 6,
When 10.25 is the short hand in the clock then 10x30=300 and 25x30/60=12.5,
Adding this 300+12.5=312.5,
When 25 minute long hand is 25x6=150,
=360-[312.5-150]=197.5.
Short hand or hour hand = 360/12 = 30,
Long hand or minute hand= 360/60 = 6,
When 10.25 is the short hand in the clock then 10x30=300 and 25x30/60=12.5,
Adding this 300+12.5=312.5,
When 25 minute long hand is 25x6=150,
=360-[312.5-150]=197.5.
Varun said:
4 years ago
Angle needed:
1} Hour hand to go from 10.25 to 12 i.e. (35+60) = 95min = 47.5° (speed of hour hand is 0.5° per minute)
2} Minute hand to go from 0 to 25 = 150°(speed of minute hand is 6° per minute).
Ans: 47.5 + 150 = 197.5°.
1} Hour hand to go from 10.25 to 12 i.e. (35+60) = 95min = 47.5° (speed of hour hand is 0.5° per minute)
2} Minute hand to go from 0 to 25 = 150°(speed of minute hand is 6° per minute).
Ans: 47.5 + 150 = 197.5°.
(1)
Jithin said:
1 decade ago
The equation for calculating the angle b/w the hands was given as (11/2)m-30h.
For eg: We clearly know that in case of 9.00 am/pm, that the angle is 90 degree, using this formula I got as 60 degree is it correct? please explain me with example.
For eg: We clearly know that in case of 9.00 am/pm, that the angle is 90 degree, using this formula I got as 60 degree is it correct? please explain me with example.
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