Aptitude - Clock - Discussion
Discussion Forum : Clock - General Questions (Q.No. 2)
2.
The reflex angle between the hands of a clock at 10.25 is:
Answer: Option
Explanation:
| Angle traced by hour hand in | 125 | hrs = |  |
360 | x | 125 |  |
° | = 312 | 1 | ° | . |
| 12 | 12 | 12 | 2 |
| Angle traced by minute hand in 25 min = | |
360 | x 25 | |
° | = 150°. |
| 60 |
 Reflex angle = 360° - |
|
312 | 1 | - 150 | |
° | = 360° - 162 | 1 | ° | = 197 | 1° | . |
| 2 | 2 | 2 |
Discussion:
269 comments Page 6 of 27.
Ajay said:
1 decade ago
Equation for the angle of the hour hand,
(Hour Angle) = (60H+M)/2.
Where, H= Hour.
M is the minutes past the hour.
And, Equation for the angle of the minute hand, (minute Angle) = 6M.
For Example:
10.25.
(Hour Angle) = (60*10+25)/2 = 312.5.
(Minute Angle) = 6*25 = 150.
Reflex angle = 360-(312.5-150) = 197.5.
(Hour Angle) = (60H+M)/2.
Where, H= Hour.
M is the minutes past the hour.
And, Equation for the angle of the minute hand, (minute Angle) = 6M.
For Example:
10.25.
(Hour Angle) = (60*10+25)/2 = 312.5.
(Minute Angle) = 6*25 = 150.
Reflex angle = 360-(312.5-150) = 197.5.
Raghavendra said:
1 decade ago
This table show the movement angle of each hand in each time in a clock.
TIME Hour Min Sec
1 hour 30° 360° 21600°
1 Minute 0.5° 6° 360°
1 Second 1/120° 0.1° 6°
TIME Hour Min Sec
1 hour 30° 360° 21600°
1 Minute 0.5° 6° 360°
1 Second 1/120° 0.1° 6°
Kunal Rai said:
2 years ago
To find the angle use this formula:
Θ=|5.5*(min) - 30*(hour)|
here in this example;
θ = |5.5*25 - 30*10|
= |137.5 - 300|
= |-162.5|
= 162.5 for an obtuse angle.
Now for reflex angle 360-162.5 = 197.5.
Using this formula u can find min and hours using theta or angle.
Θ=|5.5*(min) - 30*(hour)|
here in this example;
θ = |5.5*25 - 30*10|
= |137.5 - 300|
= |-162.5|
= 162.5 for an obtuse angle.
Now for reflex angle 360-162.5 = 197.5.
Using this formula u can find min and hours using theta or angle.
(107)
Ravi said:
1 decade ago
Angle traced in 1 hour=360/12=30 angle
Angle traced in 10 hours=30*10=300 angle
Angle traced in 25min=25/60hour=30*25/60 angle=25/2=12.5 angle=12(1/2)
total Angle traced in 10hour25min=300+12.5 angle =312(1/2)
Angle traced by minute hand in 25 min =(360/60)*25=150 angle
hence 312(1/2)-150=197.5=197(1/2)
Angle traced in 10 hours=30*10=300 angle
Angle traced in 25min=25/60hour=30*25/60 angle=25/2=12.5 angle=12(1/2)
total Angle traced in 10hour25min=300+12.5 angle =312(1/2)
Angle traced by minute hand in 25 min =(360/60)*25=150 angle
hence 312(1/2)-150=197.5=197(1/2)
Ravi singh said:
7 years ago
Reflex angle- the angle is more than 180 and less than 360 ° is called reflex angle-
The formula for this question-
M=2/11(t1*30+-∠),
∠= angle,
Form this question.
25=2/11(10*30+-∠),
25*11/2=300+-∠,
Mode
|275/2-300|=∠,
162.5=∠,
∠=360-162.5,
∠=197.5.
The formula for this question-
M=2/11(t1*30+-∠),
∠= angle,
Form this question.
25=2/11(10*30+-∠),
25*11/2=300+-∠,
Mode
|275/2-300|=∠,
162.5=∠,
∠=360-162.5,
∠=197.5.
Rinky poptani said:
7 years ago
The angle between an hour =30°.
Between 10 and 25(5) there are 7 hour.
Therefore 30° * 7 = 210°.
As at 10:25 the hour needle is 25 more than a perfect hour,
Therefore we have to minus 25/2 by 210° (as the angle between a minute is 1/2,
=> 210°- 25/2,
=> 210° -17.5 =192.5.
Between 10 and 25(5) there are 7 hour.
Therefore 30° * 7 = 210°.
As at 10:25 the hour needle is 25 more than a perfect hour,
Therefore we have to minus 25/2 by 210° (as the angle between a minute is 1/2,
=> 210°- 25/2,
=> 210° -17.5 =192.5.
(1)
Chetan said:
1 decade ago
Take simple solution,
After every 12 minutes, Hour clock will move 1 step.
=25 minutes = almost 2 steps moved hour sign from 10 to 10.02.
Now difference between hour & minute clock is 25+8=33 step
1 step = 6 degree than 33 x 6 = 198, answer option near to 198 is given 197 1/2 which is correct.
After every 12 minutes, Hour clock will move 1 step.
=25 minutes = almost 2 steps moved hour sign from 10 to 10.02.
Now difference between hour & minute clock is 25+8=33 step
1 step = 6 degree than 33 x 6 = 198, answer option near to 198 is given 197 1/2 which is correct.
Soujanya said:
8 years ago
The correct method is;
1 hour = 30 degree,
1 min = 5.5 degree.
At 10 o'clock angle between them = 30*10=300
For 25min displacement between them = 25*5.5 = 137.5
So, angle between them = 300-137.5 = 162.5, for reflex angle = 360 (total angle is 360 degree) -162.5 (so, angle between them)= 197.5.
1 hour = 30 degree,
1 min = 5.5 degree.
At 10 o'clock angle between them = 30*10=300
For 25min displacement between them = 25*5.5 = 137.5
So, angle between them = 300-137.5 = 162.5, for reflex angle = 360 (total angle is 360 degree) -162.5 (so, angle between them)= 197.5.
Balaji said:
1 decade ago
Prassaa is correct. First use the formula 30h-(11/2)m. if the answer comes 180 below. I think all of you got the answer is 137.5
Then simply subtract it from 360. Then we get the 197.5 like that.
Otherwise I mean if the answer comes 180+ then that is the answer no need subtract it from 360.
Then simply subtract it from 360. Then we get the 197.5 like that.
Otherwise I mean if the answer comes 180+ then that is the answer no need subtract it from 360.
SAI CHAKRADHAR said:
9 years ago
Write 10:25 as.
10*25/60 = 10*5/12 = (10*12 = 120 + 5 = 125/12).
Therefore, now we should multiply with 30.
(125*30/12 = 625/2 = 312.5).
Now 25 minutes should be multiply with 6.
(25*6 = 150).
And then subtract 150 from 312.5.
(312.5 - 150 = 162.5).
Reflex angle = (360 - 162.5 = 197.5).
10*25/60 = 10*5/12 = (10*12 = 120 + 5 = 125/12).
Therefore, now we should multiply with 30.
(125*30/12 = 625/2 = 312.5).
Now 25 minutes should be multiply with 6.
(25*6 = 150).
And then subtract 150 from 312.5.
(312.5 - 150 = 162.5).
Reflex angle = (360 - 162.5 = 197.5).
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