Aptitude - Clock - Discussion
Discussion Forum : Clock - General Questions (Q.No. 2)
2.
The reflex angle between the hands of a clock at 10.25 is:
Answer: Option
Explanation:
Angle traced by hour hand in | 125 | hrs = | ![]() |
360 | x | 125 | ![]() |
° | = 312 | 1 | ° | . |
12 | 12 | 12 | 2 |
Angle traced by minute hand in 25 min = | ![]() |
360 | x 25 | ![]() |
° | = 150°. |
60 |
![]() |
![]() |
312 | 1 | - 150 | ![]() |
° | = 360° - 162 | 1 | ° | = 197 | 1° | . |
2 | 2 | 2 |
Discussion:
269 comments Page 22 of 27.
Balaji said:
1 decade ago
Prassaa is correct. First use the formula 30h-(11/2)m. if the answer comes 180 below. I think all of you got the answer is 137.5
Then simply subtract it from 360. Then we get the 197.5 like that.
Otherwise I mean if the answer comes 180+ then that is the answer no need subtract it from 360.
Then simply subtract it from 360. Then we get the 197.5 like that.
Otherwise I mean if the answer comes 180+ then that is the answer no need subtract it from 360.
Jyothipriya said:
1 decade ago
Please explain the concept clearly how to find the exact reflex angle.
Gouthamprasanna said:
1 decade ago
To calculate the reflex angle formula is
= 360-(30*H-11/2*M)
Where His hours hand and M is minute hand.
= 360-(30*H-11/2*M)
Where His hours hand and M is minute hand.
Wasim said:
1 decade ago
Reflex angle is defined as the angle obtained when the angle between hour and minute hand is subtracted from 360 degree.
Jitendra chauhan said:
1 decade ago
It is very easy. We can solve it like
10.25 hr=10hr+25 min
=(10+25/60)hr
=10+5/12
=(120+5)/12
=125/12 hr
10.25 hr=10hr+25 min
=(10+25/60)hr
=10+5/12
=(120+5)/12
=125/12 hr
Ravi said:
1 decade ago
Angle traced in 1 hour=360/12=30 angle
Angle traced in 10 hours=30*10=300 angle
Angle traced in 25min=25/60hour=30*25/60 angle=25/2=12.5 angle=12(1/2)
total Angle traced in 10hour25min=300+12.5 angle =312(1/2)
Angle traced by minute hand in 25 min =(360/60)*25=150 angle
hence 312(1/2)-150=197.5=197(1/2)
Angle traced in 10 hours=30*10=300 angle
Angle traced in 25min=25/60hour=30*25/60 angle=25/2=12.5 angle=12(1/2)
total Angle traced in 10hour25min=300+12.5 angle =312(1/2)
Angle traced by minute hand in 25 min =(360/60)*25=150 angle
hence 312(1/2)-150=197.5=197(1/2)
Mayur said:
1 decade ago
Simple solution.
At 10 o'clock angle between them = 300
for 25min displacement between them = 25*5.5 = 137.5
so, angle between them = 300-137.5 = 162.5
for reflex angle = 300-162.5 = 197.5
At 10 o'clock angle between them = 300
for 25min displacement between them = 25*5.5 = 137.5
so, angle between them = 300-137.5 = 162.5
for reflex angle = 300-162.5 = 197.5
Nandhini said:
1 decade ago
This is the formula to calculate the angle.
Angle = min*(11/2)-30*hour.
Angle = min*(11/2)-30*hour.
B.Vamsi Srinivas said:
1 decade ago
Have a look at my solution once...
Time 10:25
Reflex Time...
11:60
-10:25
~~~~~~~
1:35
formulae to find angle
Angle = 11*(m)
---- - 30(h)
2
m = minutes
h = hours
so
now
11*35
= ----- - 30* 1
2
385 - 60
= --------
2
325
=---
2
1
=167 ---
2
Correct me if I'm wrong.
Time 10:25
Reflex Time...
11:60
-10:25
~~~~~~~
1:35
formulae to find angle
Angle = 11*(m)
---- - 30(h)
2
m = minutes
h = hours
so
now
11*35
= ----- - 30* 1
2
385 - 60
= --------
2
325
=---
2
1
=167 ---
2
Correct me if I'm wrong.
Gopal said:
1 decade ago
Thank you Venu. Lekkala.
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