Aptitude - Clock - Discussion

Discussion Forum : Clock - General Questions (Q.No. 2)
2.
The reflex angle between the hands of a clock at 10.25 is:
180°
192 1 °
2
195°
197 1 °
2
Answer: Option
Explanation:

Angle traced by hour hand in 125 hrs = 360 x 125 ° = 312 1 ° .
12 12 12 2

Angle traced by minute hand in 25 min = 360 x 25 ° = 150°.
60

Reflex angle = 360° - 312 1 - 150 ° = 360° - 162 1 ° = 197 .
2 2 2

Discussion:
269 comments Page 27 of 27.

Shreekanth said:   1 decade ago
Hello friend... time into fraction

10hrs 25 min should be taken as

10+25/60 = 10+5/12 =(120+5)/12 = 125/12

Thats all.
(4)

Shalini said:   1 decade ago
Why multiplied by 12 and not 60?

Bret said:   2 decades ago
@manoj how 10.5/12

Ankit said:   2 decades ago
How to calculate reflex angle?

Manoj said:   2 decades ago
10 hrs 25 min= 10.25/60. = 10.5/12 =(12*10+5)/12 =125/12

Sundar said:   2 decades ago
Hi Ramya and Pallavi,

We can write 10.25 (10 hrs 25 mins) as 125/12 hrs.

Have a nice day.!

Ramya said:   2 decades ago
How did you get 125/12?

Pallavi said:   2 decades ago
I got the answer for my previous question. But one more thing I want to now is how reflex angle calculated . and why?
(1)

Pallavi said:   2 decades ago
Please let me know why "Angle traced by hour hand" is calculated for 125 /12 hrs
(1)


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