Aptitude - Clock - Discussion

Discussion Forum : Clock - General Questions (Q.No. 2)
2.
The reflex angle between the hands of a clock at 10.25 is:
180°
192 1 °
2
195°
197 1 °
2
Answer: Option
Explanation:

Angle traced by hour hand in 125 hrs = 360 x 125 ° = 312 1 ° .
12 12 12 2

Angle traced by minute hand in 25 min = 360 x 25 ° = 150°.
60

Reflex angle = 360° - 312 1 - 150 ° = 360° - 162 1 ° = 197 .
2 2 2

Discussion:
269 comments Page 17 of 27.

Anomie said:   6 years ago
(11/2) * minute - 30 * hour = A (angle between hour hand and minute hand).

360- A = reflex angle.

Uzzwal said:   4 years ago
(11M-60H)/2.
= (11*25-60 * 10)/2,
= (325/2) = 162.5.

The reflex Angle is 360-162.5 = 197.5 degree.
(19)

Vasim said:   7 years ago
Simply use formula:

Angle = 30*H - (11*M) / 2 ---> (1).
Reflex Angle= 360 - Angle ---> From (1).

Sweta said:   1 decade ago
Hi everyone, Please help me to solve clock problems because I am unable to understand the concept.

Karthik said:   1 decade ago
Follow this:

Min hand 1 min movement swipes 6 deg.

Min hand 1 min movement = hour hand 0.5 deg.

Haimanti said:   1 decade ago
Can you please clear if this is correct calculatioon for 10 hr 25 min i.e.:

(10*60 + 25)/60??

Prashanth varma said:   1 decade ago
I didn't get simplified formula to understand this problem so please help me by simple method.

Sundar said:   2 decades ago
Hi Ramya and Pallavi,

We can write 10.25 (10 hrs 25 mins) as 125/12 hrs.

Have a nice day.!

Pallavi said:   2 decades ago
Please let me know why "Angle traced by hour hand" is calculated for 125 /12 hrs
(1)

Lipu said:   1 decade ago
Please let me know why "Angle traced by hour hand" is calculated for 125 /12 hrs


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