Aptitude - Clock - Discussion

Discussion Forum : Clock - General Questions (Q.No. 2)
2.
The reflex angle between the hands of a clock at 10.25 is:
180°
192 1 °
2
195°
197 1 °
2
Answer: Option
Explanation:

Angle traced by hour hand in 125 hrs = 360 x 125 ° = 312 1 ° .
12 12 12 2

Angle traced by minute hand in 25 min = 360 x 25 ° = 150°.
60

Reflex angle = 360° - 312 1 - 150 ° = 360° - 162 1 ° = 197 .
2 2 2

Discussion:
269 comments Page 16 of 27.

Alok said:   1 decade ago
I think 125/12 is wrong.

10.25 hrs = 10h+0.25 hrs = (10*60+0.25*60) mins = 615 mins = 615/60 mins = 123/12 hrs.

Divya said:   1 decade ago
What's the formula to calculate reflex angle if it is greater than 180 degrees? Anyone who know please tell me.

Teja Saga said:   1 year ago
Angle between hrs and min formula is 30H-11/2 M, we get 263 1/2.

Now reflex formula is 360-263 1/2 = 197 1/2.
(57)

Chikkuangel said:   7 years ago
How to calculate the angle between 2 hands of the clock when the time is 9.00 and 12.00 noon. Please explain.

Manish said:   6 years ago
(11/2)*25 = 30*10(+-)θ.
11*25-600/2 = (+-)θ.
162.5.

Reflex angle = 360- 162.5.
192.5 (option D).

Gouthamprasanna said:   1 decade ago
To calculate the reflex angle formula is

= 360-(30*H-11/2*M)

Where His hours hand and M is minute hand.

Shivam said:   2 years ago
Formula:
The angle between minute & hour hand (Ans) = (11/2)minute - 30*hour.
Reflex angle = 360 - ans.
(14)

Ajay Kumar said:   1 decade ago
The formula is wrong. The correct formula is:

The angle between the hands of the clock = (60xH - 11xM)/2.

Akhilrajpandey said:   1 decade ago
Calculation

(10*60)+25/60

where 10 is hour converted into min and add 25 min which is equal to
125/12

Raambharath said:   1 decade ago
Finding the angle= (11/2) M - (30) H.

M is the minutes.

H is the hours.

10:25.

(11/2) 25 - 30*10.


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