Aptitude - Clock - Discussion
Discussion Forum : Clock - General Questions (Q.No. 8)
8.
The angle between the minute hand and the hour hand of a clock when the time is 4.20, is:
Answer: Option
Explanation:
| Angle traced by hour hand in | 13 | hrs = |  |
360 | x | 13 |  |
° | = 130°. |
| 3 | 12 | 3 |
| Angle traced by min. hand in 20 min. = | |
360 | x 20 | |
° | = 120°. |
| 60 |
Required angle = (130 - 120)° = 10°.
Discussion:
79 comments Page 7 of 8.
Mohan said:
1 decade ago
To find angle take this formula.
Angle= ( (11/2) *min-30*hour).
If we get angle value as negative take that value as positive. That will be the answer.
Angle= ( (11/2) *min-30*hour).
If we get angle value as negative take that value as positive. That will be the answer.
Prasant said:
1 decade ago
60 parts by min hand = 5 parts by hr hand.
20 parts by min hand = (5/60) *20 = 1 2/3 part by hr hand.
1 part = 6 degree.
1 2/3 part = 10 degree.
20 parts by min hand = (5/60) *20 = 1 2/3 part by hr hand.
1 part = 6 degree.
1 2/3 part = 10 degree.
Raviteja said:
1 decade ago
Here is a simple formula to get an angel between hands..
30*[ Difference b/t hours and ( min /5) ]+ (min/2)
Take an example 4:20
30*[4~20/5]+(20/2)=0+10 = 10
30*[ Difference b/t hours and ( min /5) ]+ (min/2)
Take an example 4:20
30*[4~20/5]+(20/2)=0+10 = 10
Mouparna said:
1 decade ago
Thanks Prasad.........
Hemant said:
1 decade ago
We can also mark the ans by common sense..ie,
1. It is clear that the angle could not be 0.
2. Since the hour hand leads the min hand, and it will be in between 4 to 5, if the time will be 4.30, hour hand exactly in mid of 4 n 5, i.e 5min=30 degree, than half is 15 degree if the time would 4.30, but it is less than the 4.30, so angle will be slightly less than the 15 degree.
1. It is clear that the angle could not be 0.
2. Since the hour hand leads the min hand, and it will be in between 4 to 5, if the time will be 4.30, hour hand exactly in mid of 4 n 5, i.e 5min=30 degree, than half is 15 degree if the time would 4.30, but it is less than the 4.30, so angle will be slightly less than the 15 degree.
Javan said:
1 decade ago
Thanks anil..
Tejkishor said:
1 decade ago
@Saum
We take 12 O'clock point as reference point (r.p).
So we subtract the angle move by hr hand from the r.p. and the angle move by the min hand from the same to get the separating angle between them
and also at 4:20 the hands doesn't coincide in my watch.
We take 12 O'clock point as reference point (r.p).
So we subtract the angle move by hr hand from the r.p. and the angle move by the min hand from the same to get the separating angle between them
and also at 4:20 the hands doesn't coincide in my watch.
Aashish said:
1 decade ago
I agree with Saum. Can someone please clear our doubt?
Saum said:
1 decade ago
Why we are substracting angle traced by hour hand and angle traced by minute hand ?
One another thing is that - if we see the clock at 4.20 hour hand is at 4 and minute hand is also at 4. So angle between them must be 0 degree.
Please clear me.
One another thing is that - if we see the clock at 4.20 hour hand is at 4 and minute hand is also at 4. So angle between them must be 0 degree.
Please clear me.
Anil said:
1 decade ago
Direct formula:
|11M-60H|/2
where M=minute, H=hour hands.
|11M-60H|/2
where M=minute, H=hour hands.
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