### Discussion :: Chain Rule - General Questions (Q.No.10)

Pawan Goyal said: (Oct 27, 2010) | |

hw that problem has been solved i don't understand the way it has been solve out...plz tell me the way it has been solved out |

Chanti said: (Jan 4, 2011) | |

I didn't understood how the ratio will be considered. As follows 1*7*x=7*1*7 So please give the brief description. |

Mehar said: (Feb 2, 2011) | |

When ever you found these kind of problems, come from the back. Means if 7spiders 7weds in 7days so, 1 spider work ==(7*7)/7=7; one person work==days*work done/ number of workers; |

Anjani said: (Sep 11, 2011) | |

I didn't understand the solution please explain once. |

Radhika said: (Sep 17, 2011) | |

7 spiders in 7 days make 7 webs Since 7 webs in 7 days.....1 web in 1 day..dis 1 web is made by 7 spiders. Now, Since 7 spiders have made 1web in a day divide this 1 web into 7 parts 1 each for every spider.. So 1 spider will make 1/7 part of the web in a day. Now, 1/7 th part completes in 1 day so 1/7(1st day) + 1/7(2nd day) + 1/7(3rd day) + 1/7(4th day) + 1/7(5th day) + 1/7(6th day) + 1/7(7th day) = 7/7 = 1 complete web by a spider... Thus it took 7 days which is the answer. |

Prabhu said: (Sep 27, 2011) | |

@RADHIKA What an explanation great thank you. |

Sudheer said: (Oct 5, 2011) | |

Superb radhika. Thank you. |

Deepak Verma said: (Jul 20, 2014) | |

Its simple formula:- (no. of spider*no.of days)/no.of webs So according this: 7*7/7 = 1*x/1. Than x = 7. |

Kasinath @Hyd said: (Sep 4, 2014) | |

7 Spiders ... 7 Days. => 1 spider =7*7= 49 days--- Eq(1). Remaining one is 7 Webs--- Eq(2). But, question is about 1 web. So, when we Divide Eqn(1) by Eqn(2) we get 1 web. =>1 spider =49 days/7 webs = 7 days/1web =>1 spider 1 web = 7 days |

Kilevu said: (Aug 27, 2016) | |

Nice explanations, I get it now. Thanks to all. |

Anomy said: (Oct 26, 2016) | |

To get 7 then I think it needs to be explained better that each spider is working on their own web. Otherwise, it takes 1 team of 7 spiders 7 days to make 7 webs. If you have less on your team you will make fewer webs or it will take longer to make the same number of webs. |

Anoms said: (Dec 23, 2016) | |

3 chickens can make 3 eggs in 3 days, then how many eggs can be made by 300 chickens in 300 days? |

Anonymous said: (Feb 2, 2017) | |

7spiders * 1spider * x days = 7webs * 1web * 7days. Spiders on the Left * days = webs on the right * days. => 7 * 1 * x = 7 * 1 * 7. 7x = 49, 7x/7 = 49/7, x = 7days. |

Mr. Mp said: (Aug 31, 2017) | |

Take this example. 7 girls make 7 cakes in 7 days. so 7 girls complete 1 cake in 1 day. 7 girls complete 2cakes in 2days. 7 girls complete 3 cakes in 3 days. Similarly, 7 girls make 7 cakes in 7 days. Simply can say effort of 7 girls is needed for 1 cake to complete in 1 day as good as saying effort of 1 girl is required for 7 days to make 1 cake. |

Siddu K said: (Sep 14, 2017) | |

@Radhika. Super explanation. |

Mayur said: (Dec 23, 2017) | |

Good explanation @Radhika. |

Bala said: (Apr 19, 2018) | |

Nice explanation @Radhika. |

Vinnu said: (Aug 30, 2018) | |

Nice. Thanks all. |

Mayur said: (Jan 18, 2019) | |

7 Spiders make 7 Webs in 7 Days. -> eq 1 7 Spiders make 1 Web in 1Day -> eq 2 1 Spider make 1 Web in X=? Days) -> eq3 Multiple Value of Number of Spiders with a number of days from eq 2 and eq3 7*1. = 1*X. X. =. 7*1/1, X. = 7 -----> Ans. Less Spiders -> More Days (Indirect Proportion). Less Webs -> fewer Days (Direct Proportion). |

Sushi said: (Mar 10, 2019) | |

@Radhika. Superb explanation, Thank you. |

Pennanson said: (Apr 7, 2019) | |

The correct Answer is 1. |

Anonymous said: (Aug 30, 2020) | |

@Radhika. You explained it very well. Thanks. |

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