Aptitude - Chain Rule - Discussion
Discussion Forum : Chain Rule - General Questions (Q.No. 12)
12.
In a camp, there is a meal for 120 men or 200 children. If 150 children have taken the meal, how many men will be catered to with remaining meal?
Answer: Option
Explanation:
There is a meal for 200 children. 150 children have taken the meal.
Remaining meal is to be catered to 50 children.
Now, 200 children 
120 men.
| 50 children |
 |
120 | x 50 |  |
= 30 men. |
| 200 |
Discussion:
20 comments Page 1 of 2.
Harish reddy said:
9 months ago
200 : 120 = 3 : 5.
Then remaining 50 child = 50 * 3/5 = 30.
Then remaining 50 child = 50 * 3/5 = 30.
(2)
Atul said:
6 years ago
120/200 = men : children.
15men = 25 children.
200-150 = 50(consumed).
(25x2)Children = 50(remaning).
:.(15x2)men = 30(remaining).
15men = 25 children.
200-150 = 50(consumed).
(25x2)Children = 50(remaning).
:.(15x2)men = 30(remaining).
(1)
Saiganesh Murarishetty said:
7 years ago
Here; Remaining children are 50 and this is 25% of 200, so 25% of men is 30.
(6)
Zoizo said:
7 years ago
Shouldn't it be 200*120/50?
(1)
Sowmiya said:
8 years ago
How 120/200? Please explain.
Farhaaz said:
9 years ago
The solution to this type of question can be found from observation.
Given that 150 children out of 200 children have taken the meal.i.e, 3/4th of children have been supplied by the meal. So 1/4 the of the children have to be supplied with the remaining meal.
As it is given that 120 men = 200 children.
Therefore the remaining meal must be supplied to 1/4th of 120 men viz.,30 men.
Given that 150 children out of 200 children have taken the meal.i.e, 3/4th of children have been supplied by the meal. So 1/4 the of the children have to be supplied with the remaining meal.
As it is given that 120 men = 200 children.
Therefore the remaining meal must be supplied to 1/4th of 120 men viz.,30 men.
(2)
Aku said:
9 years ago
@Hemanth proportionality is clearly visible, more men catered imply more children catered there is direct proportionality.
i.e
120 : x :: 200 : 150.
200 * x = 150 * 120.
x = 90 so, 150 children are equivalent to 90 men, remaning food is for men = 120 - 90 = 30.
i.e
120 : x :: 200 : 150.
200 * x = 150 * 120.
x = 90 so, 150 children are equivalent to 90 men, remaning food is for men = 120 - 90 = 30.
(2)
Bindubrisk said:
9 years ago
It's so simple here 120:200 is nothing but 3:5 means 3 men =5 children means 1 child=3/5 men and remaining 50 children=50* (3/5) =30 and its the answer it is easy.
Ashok said:
1 decade ago
Ratio for 120 and 200 = 3:5.
Then, 150/5 = 30.
So 1 part = 30,
Then 3 parts for men is 3*30 = 90 and 5 parts for children is 5*30 = 150.
So 90 men = 150 children.
Remaining men = 30.
Then, 150/5 = 30.
So 1 part = 30,
Then 3 parts for men is 3*30 = 90 and 5 parts for children is 5*30 = 150.
So 90 men = 150 children.
Remaining men = 30.
Ram said:
1 decade ago
Let man = m and children = y.
Then meal of 120m = 200c.
Meal of 1m = (200/120)c.
1m = 5/3c.
i.e (5/3)c = 1m.
5c = 3m.
1c = (3/5) m.
50c = (3/5*50) m.
50c = 30m.
Then meal of 120m = 200c.
Meal of 1m = (200/120)c.
1m = 5/3c.
i.e (5/3)c = 1m.
5c = 3m.
1c = (3/5) m.
50c = (3/5*50) m.
50c = 30m.
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