Aptitude - Calendar - Discussion
Discussion Forum : Calendar - General Questions (Q.No. 1)
1.
It was Sunday on Jan 1, 2006. What was the day of the week Jan 1, 2010?
Answer: Option
Explanation:
On 31st December, 2005 it was Saturday.
Number of odd days from the year 2006 to the year 2009 = (1 + 1 + 2 + 1) = 5 days.
On 31st December 2009, it was Thursday.
Thus, on 1st Jan, 2010 it is Friday.
Discussion:
258 comments Page 3 of 26.
Kamal said:
1 decade ago
Vijay can we do the same calculations for years like 2000, 1990, 1980 ?
Kamal said:
1 decade ago
Pavithra can you apply you are concept for this date?.
1st Jan 2008.
If please explain it with steps.
1st Jan 2008.
If please explain it with steps.
Sonu navgotri said:
1 decade ago
For non-leap year odd number = 1 .
For leap year odd number = 2.
For leap year odd number = 2.
DG1234 said:
1 decade ago
This formula does not work on leap year. Pavithra..I am so sorry
Akhtar said:
1 decade ago
I think sundar gave perfect ans.
Priya said:
1 decade ago
Multiples of 4 and multiples of 400 are leap years but multiples of 100 not a leap year
Priyanka said:
1 decade ago
Guys give a simple and easy method to find the leap year like pavithra has given to find the week day of a certain date.
Siddharth said:
1 decade ago
Well done sundar.
Let me know that simple method to find leap year.
Let me know that simple method to find leap year.
Rajellam said:
1 decade ago
Thank you sunder. Actually I don't know how to calculate. But now I can do with help of you. Thak you.
Deena said:
1 decade ago
Pavithra your formula is perfect and easy method. Thank you.
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