Aptitude - Calendar - Discussion
Discussion Forum : Calendar - General Questions (Q.No. 1)
1.
It was Sunday on Jan 1, 2006. What was the day of the week Jan 1, 2010?
Answer: Option
Explanation:
On 31st December, 2005 it was Saturday.
Number of odd days from the year 2006 to the year 2009 = (1 + 1 + 2 + 1) = 5 days.
On 31st December 2009, it was Thursday.
Thus, on 1st Jan, 2010 it is Friday.
Discussion:
258 comments Page 2 of 26.
Shaunak said:
1 decade ago
@veer singh pal:your answer is partially correct.for years like 1600,1700,1800,1900,2000 etc,we need to divide by 400.for other nos.,it needs to be a multiple of 4.
Arun Anoop M said:
1 decade ago
Thanks vijaya
100=24 leap yr+[100-24]ordinary days
=[24*2]+76
=124
my way is
124=17weeks+5 ordinary days
So answer is 5.
But your way is very easy
124/7=5(remainder).
100=24 leap yr+[100-24]ordinary days
=[24*2]+76
=124
my way is
124=17weeks+5 ordinary days
So answer is 5.
But your way is very easy
124/7=5(remainder).
Priyavel said:
1 decade ago
Hai Nilesh.
We divide year by 400. If remainder comes 0 means that year is leap year.
We divide year by 400. If remainder comes 0 means that year is leap year.
Dhanagopal said:
1 decade ago
I want briefly to find odd days.
(1)
Boomathi said:
1 decade ago
Please tell how do we know the leap year?
Latha said:
1 decade ago
@Boomathi.
We know the given year is leap year or not, that year is divided by 4. That number (year) does not give any remainder that year is called leap year.
We know the given year is leap year or not, that year is divided by 4. That number (year) does not give any remainder that year is called leap year.
Saamy said:
1 decade ago
How there are 24 leaf years there in 100 years.
Anyone please explain.
Anyone please explain.
Pavithra said:
1 decade ago
Hi there is a formula for this type of problem.
Plz memorize this
jan=1
feb=4
mar=4
apr=0
may=2
jun=5
jul=0
aug=3
sep=6
oct=1
nov=4
dec=6
days:
s=1
m=2
t=3
w=4
th=5
f=6
sat=7 or 0
formula=day+mon no.+(x-1900)+(x-1900)/4
x= the year we have to calculate
Eg:
16-may-2011
for=16+2+(2011-1900)+(2011-1900)/4
=16+2+111+111/4
=16+2+111+27
(here we should not take the no behind decimal i.e 111/4=27.75)
=156
156/7=2(reminder)
mon =2
Plz memorize this
jan=1
feb=4
mar=4
apr=0
may=2
jun=5
jul=0
aug=3
sep=6
oct=1
nov=4
dec=6
days:
s=1
m=2
t=3
w=4
th=5
f=6
sat=7 or 0
formula=day+mon no.+(x-1900)+(x-1900)/4
x= the year we have to calculate
Eg:
16-may-2011
for=16+2+(2011-1900)+(2011-1900)/4
=16+2+111+111/4
=16+2+111+27
(here we should not take the no behind decimal i.e 111/4=27.75)
=156
156/7=2(reminder)
mon =2
Seetharaman said:
1 decade ago
Thanks pavithra.
Suman said:
1 decade ago
Many many thanx...Pavithra
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