Aptitude - Calendar - Discussion

Discussion Forum : Calendar - General Questions (Q.No. 1)
1.
It was Sunday on Jan 1, 2006. What was the day of the week Jan 1, 2010?
Sunday
Saturday
Friday
Wednesday
Answer: Option
Explanation:

On 31st December, 2005 it was Saturday.

Number of odd days from the year 2006 to the year 2009 = (1 + 1 + 2 + 1) = 5 days.

On 31st December 2009, it was Thursday.

Thus, on 1st Jan, 2010 it is Friday.

Discussion:
258 comments Page 23 of 26.

Amar said:   8 years ago
2006 jan 1 Sunday
2010 jan 1 ?

Here,
Jan 1 ana jan1 cut
then,
(2010-2006)
=4
leap year = 1
=4+1
=1

So, given day is sunday+5
= Friday is the answer.

Prashanth said:   7 years ago
If 1932 December 21st is a Sunday then which day is 2018 December 21st?

Can anyone solve this?

Pujaa said:   7 years ago
How to find leap year? Please explain.

Naren said:   7 years ago
Divide the years last two digits by 4 if the remainder is 0 then it's a leap year.

Ramesh said:   7 years ago
Formula:day + month code + no of years(last 2 digits) + no of leap years + century code.

Month code :1 4 4 0 2 5 0 3 6 1 4 6.

Centuty code: 1900-1999=0.
2000-2099=6.
2100-2199=4.
2200-2299=2.

Day code: Sat-0,Sun-1,Mon-2,Tue-3,wed-4, Thu-5, Fri-6.

Atharva said:   7 years ago
What are the odd days how to find it? Please tell me.

Lokesh said:   7 years ago
Hi guys.

I just want to know how to find a leap year. Is there any tips to remember? Please tell me.

Pavan kalyan said:   7 years ago
Take any particular year and divide that year with 4.

If youu get the exact division, then, such year is a leap year.
Eg:- 2012 divide with 4 = 503.
2016/4 = 504,
2014/4 = 503.5. ( this is not a leap year. you shouldn't get decimals at the end.)

SahithiSundaraRao said:   7 years ago
Can anybody tell me how to calculate; what is the day on June 15, 1998?

Umasankar said:   7 years ago
No of odd days =5 on December 31, 2009, it comes on Friday.
Jan 1, 2010, it comes on Saturday.


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