Aptitude - Calendar - Discussion

Discussion Forum : Calendar - General Questions (Q.No. 1)
1.
It was Sunday on Jan 1, 2006. What was the day of the week Jan 1, 2010?
Sunday
Saturday
Friday
Wednesday
Answer: Option
Explanation:

On 31st December, 2005 it was Saturday.

Number of odd days from the year 2006 to the year 2009 = (1 + 1 + 2 + 1) = 5 days.

On 31st December 2009, it was Thursday.

Thus, on 1st Jan, 2010 it is Friday.

Discussion:
258 comments Page 20 of 26.

Kundan said:   9 years ago
Hi,
A simple technique is;
2010 - 2006 + no. of leap year between them = 4 + 1 = 5.
[There is only a leap year between 2006 to 2010 is 2008]
Now,
Sunday + 5 = Friday.

Abhishek said:   8 years ago
It is very helpful, Thanks @Mahesh.

Prashant d said:   8 years ago
Really helpful. Thanks to all.

SHUBHAM GUPTA said:   8 years ago
Hi Friends,

Odd days of a year X = Remainder of [No. of days in the year X / 7].

[Where 7 --> For every 7 days, the day will be repeated, thats why we are dividing the total number of days of an year by 7. If it has any remainder then it will be considered as an odd day for that year.]

The required remainders (odd days) for the different years are given below:

For 2006: 365/7 = 1 (Total no. of days in 2006 is 365)
For 2007: 365/7 = 1
For 2008: 366/7 = 2 (Leap year, hence Feb month has 29 days)
For 2009: 365/7 = 1

Therefore, total number of odd days = 5.

Given day is 'Sunday' and total no of odd days is '5'.

The required date = Sunday + 5.

= (The 5th day next to Sunday).
= Sunday + 1-Monday + 2-Tuesday + 3-Wednesday + 4-Thursday + 5-Friday.
= Friday (Required answer).

Jyoti said:   8 years ago
Please, memorise this.

Jan=1
Feb=4
Mar=4
Apr=0
May=2
Jun=5
Jul=0
Aug=3
Sep=6
Oct=1
Nov=4
Dec=6

Days:
S=1
M=2
T=3
W=4
Th=5
F=6
Sat=7 or 0

Formula = day + mon no . + (x-1900) + (x-1900)/4.
x = the year we have to calculate.

Eg:
16-may-2011.

for = 16 + 2 + (2011-1900) + (2011-1900)/4,
= 16+2+111+111/4.
= 16+2+111+27.

(here we should not take the no behind decimal i.e 111/4=27.75)
= 156.

156/7 = 2(reminder).

Mon = 2.

Ajit said:   8 years ago
Thanks @Pavithra.

Ragu said:   8 years ago
Ans :-
Step 1 ; how many years we have between 2006 to 2010 = 2006 - 2010 =4.
Step 2 ; per year 365 so if we divide by weeks = 365/7 = 52.1 that means 52weeks 1ood days.
Step 3 ; So every 4th year we have an extra day that we call leap year means 366 days again if we divide by weeks = 366/7 = 52.2 in this 2 ood days we have.
Step 4; 2006 = 1.
For 2007 = 1.
For 2008 = 1.
For 2009 = 2 (1+1+1+2 = 5days).
Step 5;
1 jan 2006 = Sunday count 1 .
1 jan 2007 = Monday count 1.
1 jan 2008 = Tuesday count 1.
1 jan 2009 = Wednesday & Thursday count 2 because as per our count it is leap year(2days extra).
1 jan 2010 = answer is Friday.

Tarun said:   8 years ago
How to find an leap year by seeing an year. Ex. 2006 is which year?is it leap year or ordinary year. If it is leap year how can we say it is leap year. If not how can we say not?

Sai said:   8 years ago
Good @Sundar.

Minhaz said:   8 years ago
Thanks @Sundar.


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