Aptitude - Calendar - Discussion
Discussion Forum : Calendar - General Questions (Q.No. 1)
1.
It was Sunday on Jan 1, 2006. What was the day of the week Jan 1, 2010?
Answer: Option
Explanation:
On 31st December, 2005 it was Saturday.
Number of odd days from the year 2006 to the year 2009 = (1 + 1 + 2 + 1) = 5 days.
On 31st December 2009, it was Thursday.
Thus, on 1st Jan, 2010 it is Friday.
Discussion:
258 comments Page 17 of 26.
Dhara said:
1 decade ago
Easy style to calculate this question.
jan 1, 2006 sunday.
jan 1, 2007 monday (+1 in day because 2007 is not leap year) .
jan 1, 2008 wendsay (+2 in day because 2008 is divisible by 4).
jan 1, 2009 Thursday (+1 in day because it is not leap year).
jan 1, 2010 Friday (+1 because it is not leap year).
If leap year then add 2 days otherwise 1 day will be add if and only if year is only changed and date will be same.
jan 1, 2006 sunday.
jan 1, 2007 monday (+1 in day because 2007 is not leap year) .
jan 1, 2008 wendsay (+2 in day because 2008 is divisible by 4).
jan 1, 2009 Thursday (+1 in day because it is not leap year).
jan 1, 2010 Friday (+1 because it is not leap year).
If leap year then add 2 days otherwise 1 day will be add if and only if year is only changed and date will be same.
Shiva said:
1 decade ago
How do find leap years?
Sameera keerthana best frnds forever said:
1 decade ago
Don't confuse yaar just calculate.
Jan 1 2010 = (jan+2009)odd day calculation.
For 2009 no.of odd days are (2000+1+2+3+4+5+6+7+8+9)
(0+1+1+1+2+1+1+1+2+1) = 11/7 = 4 odd days.
For 1 Jan no.of odd days = 1 odd day.
So totally = (4+1) = 5 odd days.
5->Friday.
Jan 1 2010 = (jan+2009)odd day calculation.
For 2009 no.of odd days are (2000+1+2+3+4+5+6+7+8+9)
(0+1+1+1+2+1+1+1+2+1) = 11/7 = 4 odd days.
For 1 Jan no.of odd days = 1 odd day.
So totally = (4+1) = 5 odd days.
5->Friday.
Prabu said:
1 decade ago
If any shortcut to solve this problem with in 1 min.
Priya Gaikwad said:
1 decade ago
1 jan 2006 = Sunday count 1 .
1 jan 2007 = Monday count 1.
1 jan 2008 = Tuesday count 1.
1 jan 2009 = Thursday count 2 because 2008 is leap year(2008/4=0).
1 jan 2010 = Friday. Req. answer.
1 jan 2007 = Monday count 1.
1 jan 2008 = Tuesday count 1.
1 jan 2009 = Thursday count 2 because 2008 is leap year(2008/4=0).
1 jan 2010 = Friday. Req. answer.
Mustaq said:
1 decade ago
1 year = 365 days and 8 hours.
So after 3 year = 3*8 = 24 hours = 1 days.
So after 3 year = 3*8 = 24 hours = 1 days.
Jenny said:
1 decade ago
2006/4, 2007/4, 2008/4, 2009/4 if remainder will zero that is the leap year.
Sri said:
1 decade ago
If 1st Jan is a Sunday then find the number of Sundays in that year?
Vinodh Guvalla said:
1 decade ago
This is easy explanation by @Narendra.
Neha said:
1 decade ago
How to calculate odd days?
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers