Aptitude - Calendar - Discussion

Discussion Forum : Calendar - General Questions (Q.No. 1)
1.
It was Sunday on Jan 1, 2006. What was the day of the week Jan 1, 2010?
Sunday
Saturday
Friday
Wednesday
Answer: Option
Explanation:

On 31st December, 2005 it was Saturday.

Number of odd days from the year 2006 to the year 2009 = (1 + 1 + 2 + 1) = 5 days.

On 31st December 2009, it was Thursday.

Thus, on 1st Jan, 2010 it is Friday.

Discussion:
258 comments Page 16 of 26.

Sohan bansal said:   1 decade ago
What is the even day?

Prabhas said:   1 decade ago
What is the day of 8-oct-1996?

Sumit said:   1 decade ago
Please just tell me how to find out leap year, and odd days?

Sunidhi said:   1 decade ago
Hey friends please help me please give me another formula to solve problems because by above condition all problems are not solved. Please help me.

Mounika said:   1 decade ago
How we can find same day of another year?

Kasinath @Hyd said:   1 decade ago
From 2010..... 2000 is a factor of 400.(A/C to leap year Formula).
Therefore Year 2000 is Leap year hence we get 0 odd days.

From remaining 10 Years we have,
8 Ordinary years and 2 leap years i.e.,(4th & 8th year).

=> 8*1 + 2*2 = 12 days.
12/7 = 1 week + 5 odd days.

A/C to formula 5th day represent Friday.

Darkkites said:   1 decade ago
Divide 4 to any year. If reminder is 0 then it is leap year.

Vasim ghanchi said:   1 decade ago
1-jan-2006 sunday.
1-jan-2007 Monday.
1-jan-2008 Wednesday (if year is leap year then left one day and next day will be used).
1-jan-2009 thursday.
1-jan-2010 Friday.

Susi said:   1 decade ago
How to find the day for any given date?

Himanshu said:   1 decade ago
Method to find the leap year:

If any year divided by 4 without reminder its year known as leap year.
Example-: 2008/4 = 502(no reminder).

And in this year were 29 days in Feb.
And a year consist 366 days.


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