Aptitude - Calendar - Discussion
Discussion Forum : Calendar - General Questions (Q.No. 1)
1.
It was Sunday on Jan 1, 2006. What was the day of the week Jan 1, 2010?
Answer: Option
Explanation:
On 31st December, 2005 it was Saturday.
Number of odd days from the year 2006 to the year 2009 = (1 + 1 + 2 + 1) = 5 days.
On 31st December 2009, it was Thursday.
Thus, on 1st Jan, 2010 it is Friday.
Discussion:
258 comments Page 15 of 26.
Vinod said:
9 years ago
15 June 1987 how I can found which day of the week? Please let me know the solution.
Mangesh v upare said:
8 years ago
There are 5 no of odd days in between Jan 1 2006 to Jan 2010.
Add 5 days in Sunday.
Add 5 days in Sunday.
Naren said:
7 years ago
Divide the years last two digits by 4 if the remainder is 0 then it's a leap year.
Vallinath said:
1 decade ago
Pavithra you said sat code 7 or 0 when we use 7 and when we use 0 please tell me.
Lakshmi said:
4 years ago
How do we know the leap year of that specific year? How to know? Please explain.
(7)
Monika said:
6 years ago
How many Sundays are there in year if 1st December in that year is on Sunday?
Jenny said:
1 decade ago
2006/4, 2007/4, 2008/4, 2009/4 if remainder will zero that is the leap year.
Vinay said:
10 years ago
How to solve the problem method or what was the day on the 15th August 1947?
Ash said:
6 years ago
If 15 August 1947- Friday.
Then what will be 7 May 2019? Anyone solve this.
Then what will be 7 May 2019? Anyone solve this.
(1)
Sachin said:
8 years ago
In this question, we can apply formula.
f = k + (13 * m-1)/5+D D/4+C/4-2C.
f = k + (13 * m-1)/5+D D/4+C/4-2C.
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers