Aptitude - Calendar - Discussion
Discussion Forum : Calendar - General Questions (Q.No. 1)
1.
It was Sunday on Jan 1, 2006. What was the day of the week Jan 1, 2010?
Answer: Option
Explanation:
On 31st December, 2005 it was Saturday.
Number of odd days from the year 2006 to the year 2009 = (1 + 1 + 2 + 1) = 5 days.
On 31st December 2009, it was Thursday.
Thus, on 1st Jan, 2010 it is Friday.
Discussion:
258 comments Page 14 of 26.
Prashanth said:
8 years ago
If 1932 December 21st is a Sunday then which day is 2018 December 21st?
Can anyone solve this?
Can anyone solve this?
Umasankar said:
7 years ago
No of odd days =5 on December 31, 2009, it comes on Friday.
Jan 1, 2010, it comes on Saturday.
Jan 1, 2010, it comes on Saturday.
Vanisha nagar said:
7 years ago
If it was Tuesday on 24 March 2018 then what was the day on 26 January 1950? Please explain.
Sagar said:
8 years ago
If in a month fourth day after 21st was saturday then what was the day on 3rd of the month?
Shivani said:
6 years ago
2006 - Sunday.
2007 - Monday.
2008(leap year) - wednesday.
2009 - Thursday.
2010 - Friday.
2007 - Monday.
2008(leap year) - wednesday.
2009 - Thursday.
2010 - Friday.
Priya said:
1 decade ago
Multiples of 4 and multiples of 400 are leap years but multiples of 100 not a leap year
Manoj said:
1 decade ago
I am little confused with this particular question. Could you please explain in detail?
Priyavel said:
1 decade ago
Hai Nilesh.
We divide year by 400. If remainder comes 0 means that year is leap year.
We divide year by 400. If remainder comes 0 means that year is leap year.
Deepika said:
6 years ago
If the first day of 1987 is Thursday, then what will be the last day of the year 1987?
Chithra said:
8 years ago
Can anyone tell me the formula to find the day of the week for a year less than 1900?
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers