Aptitude - Calendar - Discussion
Discussion Forum : Calendar - General Questions (Q.No. 2)
2.
What was the day of the week on 28th May, 2006?
Answer: Option
Explanation:
28 May, 2006 = (2005 years + Period from 1.1.2006 to 28.5.2006)
Odd days in 1600 years = 0
Odd days in 400 years = 0
5 years = (4 ordinary years + 1 leap year) = (4 x 1 + 1 x 2) 
6 odd days
Jan. Feb. March April May (31 + 28 + 31 + 30 + 28 ) = 148 days
148 days = (21 weeks + 1 day) 1 odd day.
Total number of odd days = (0 + 0 + 6 + 1) = 7 0 odd day.
Given day is Sunday.
Discussion:
214 comments Page 3 of 22.
Hemlatasharma said:
1 decade ago
What is the odd day please explain briefly.
M.Vamshi said:
1 decade ago
Is there any easiest method to calculate day plz i cant understood the odd day or even day
Senthil said:
1 decade ago
The number of days more than the complete weeks are called ODD DAYS....
In 400,1600,2000 odd days are zero...
****************************************************************
Day of the week on 28th may 2006,
In 2006,
Jan 31days+Feb 28days+Mar 31days+Apr 30days+May 28days[bcz 28th may]= 148days [totally]
To find odd day,
148/7=21quotient 1remainder
so 21complete weeks and 1 odd day in 2006
****************************************************************
For 5years [2001-2005],
To find leap year,
5/4=1 [never take the decimal points]
1leap year
So 2odd days in that year[366/7=52weeks+2odd days]
And rest of the 4years have 4odd days[365/7=52weeks+1odd day]
so for 5years,
2+4=6odd days
****************************************************************
Total number of odd days,
0+0+1+6=7
So, 7/7=1complete week
There is zero odd day in it.
0-Sunday
1-Monday
2-Tuesday
3-Wednesday
4-Thursday
5-Friday
6-Saturday
So 28th may 2006 is Sunday....:)
In 400,1600,2000 odd days are zero...
****************************************************************
Day of the week on 28th may 2006,
In 2006,
Jan 31days+Feb 28days+Mar 31days+Apr 30days+May 28days[bcz 28th may]= 148days [totally]
To find odd day,
148/7=21quotient 1remainder
so 21complete weeks and 1 odd day in 2006
****************************************************************
For 5years [2001-2005],
To find leap year,
5/4=1 [never take the decimal points]
1leap year
So 2odd days in that year[366/7=52weeks+2odd days]
And rest of the 4years have 4odd days[365/7=52weeks+1odd day]
so for 5years,
2+4=6odd days
****************************************************************
Total number of odd days,
0+0+1+6=7
So, 7/7=1complete week
There is zero odd day in it.
0-Sunday
1-Monday
2-Tuesday
3-Wednesday
4-Thursday
5-Friday
6-Saturday
So 28th may 2006 is Sunday....:)
Divya said:
1 decade ago
Well explained Senthil
Chandru said:
1 decade ago
Superb senthil. Chanceless.
Deena said:
1 decade ago
Hi there is a formula for this type of problem.
Plz memorize this
jan=1
feb=4
mar=4
apr=0
may=2
jun=5
jul=0
aug=3
sep=6
oct=1
nov=4
dec=6
days:
s=1
m=2
t=3
w=4
th=5
f=6
sat=7 or 0
formula=day+month no.+(x-1900)+(x-1900)/4
x= the year we have to calculate
Eg:
28-may-2006
for=28+2+(2006-1900)+(2006-1900)/4
=28+2+16+16/4
=28+2+16+4 note:
=50 (here we should not take the no
behind decimal i.e 17/4=4.25)
50/7=1(reminder)
sun =1
Plz memorize this
jan=1
feb=4
mar=4
apr=0
may=2
jun=5
jul=0
aug=3
sep=6
oct=1
nov=4
dec=6
days:
s=1
m=2
t=3
w=4
th=5
f=6
sat=7 or 0
formula=day+month no.+(x-1900)+(x-1900)/4
x= the year we have to calculate
Eg:
28-may-2006
for=28+2+(2006-1900)+(2006-1900)/4
=28+2+16+16/4
=28+2+16+4 note:
=50 (here we should not take the no
behind decimal i.e 17/4=4.25)
50/7=1(reminder)
sun =1
Priya said:
1 decade ago
@senthil
Why should we consider 2001-2005? they have specified only 2006.
Why should we consider 2001-2005? they have specified only 2006.
Dev said:
1 decade ago
@Deena
How come 2006-1900=16 can you tell me ?
How come 2006-1900=16 can you tell me ?
John said:
1 decade ago
Its wrong the 2006-1900 is 106.
Praveena said:
1 decade ago
How it possible 2006-1900=16 do you explain.
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