Aptitude - Calendar - Discussion
Discussion Forum : Calendar - General Questions (Q.No. 2)
2.
What was the day of the week on 28th May, 2006?
Answer: Option
Explanation:
28 May, 2006 = (2005 years + Period from 1.1.2006 to 28.5.2006)
Odd days in 1600 years = 0
Odd days in 400 years = 0
5 years = (4 ordinary years + 1 leap year) = (4 x 1 + 1 x 2) 
6 odd days
Jan. Feb. March April May (31 + 28 + 31 + 30 + 28 ) = 148 days
148 days = (21 weeks + 1 day) 1 odd day.
Total number of odd days = (0 + 0 + 6 + 1) = 7 0 odd day.
Given day is Sunday.
Discussion:
214 comments Page 20 of 22.
Shree said:
1 decade ago
Can doomsday method be applied here?
Bikram said:
6 years ago
Is 2000 Leap year or ordinary year?
Hrithik said:
8 years ago
Thanks for the explanation @Rajat.
Thiru said:
6 years ago
(28+06+1+6+(06/4) )/7 = 43/7 = 1.
John said:
1 decade ago
Its wrong the 2006-1900 is 106.
Sindhu said:
1 decade ago
How we can take jan-1, feb-4...
Rekha said:
1 decade ago
Can you please explain brief?
Bikram said:
6 years ago
The Correct answer is Monday.
Amiya,pradeep said:
1 decade ago
What the meaning of odd day?
Geetha said:
1 decade ago
Can you explain it briefly.
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