Aptitude - Calendar - Discussion
Discussion Forum : Calendar - General Questions (Q.No. 2)
2.
What was the day of the week on 28th May, 2006?
Answer: Option
Explanation:
28 May, 2006 = (2005 years + Period from 1.1.2006 to 28.5.2006)
Odd days in 1600 years = 0
Odd days in 400 years = 0
5 years = (4 ordinary years + 1 leap year) = (4 x 1 + 1 x 2) 
6 odd days
Jan. Feb. March April May (31 + 28 + 31 + 30 + 28 ) = 148 days
148 days = (21 weeks + 1 day) 1 odd day.
Total number of odd days = (0 + 0 + 6 + 1) = 7 0 odd day.
Given day is Sunday.
Discussion:
214 comments Page 20 of 22.
Shweta said:
6 years ago
Thank you @Senthil. Very nice explanation. Now I understood properly.
CREDENZA said:
6 years ago
Sorry if anyone has answered already I did not go through the solution.
Here goes the solution,
DAYS:-
0-S, 1-M, 2-T, 3-W, 4-TH, 5-F, 6-SAT
MONTH:-
[J F M][A M Ju][JuL A S][O N D]
[0 3 3] [6 1 4][ 6 2 5][0 3 5] // [ ] Just for simplicity
YEARS;-
1600 to 1699 consider code as 6
1700 to 1799 consider code as 4
1800 to 1899 consider code as 2
1900 to 1999 consider code as 0
2000 to 2099 consider code as 6
FOLLOW THE FOLLOWING STEPS:-
1) Take last two digits of given year: _ _
2) Divide the above taken number by 4 and consider the quotient: _ _
3) Take the date: _ _
4) Take the month: _ _
5) Choose the code of the year as specified above: _
6) Add everything and divide by 7 and consider the remainder the result will be from 0 to 7(any one number).
Match with the day that will be the result.
Here goes the solution,
DAYS:-
0-S, 1-M, 2-T, 3-W, 4-TH, 5-F, 6-SAT
MONTH:-
[J F M][A M Ju][JuL A S][O N D]
[0 3 3] [6 1 4][ 6 2 5][0 3 5] // [ ] Just for simplicity
YEARS;-
1600 to 1699 consider code as 6
1700 to 1799 consider code as 4
1800 to 1899 consider code as 2
1900 to 1999 consider code as 0
2000 to 2099 consider code as 6
FOLLOW THE FOLLOWING STEPS:-
1) Take last two digits of given year: _ _
2) Divide the above taken number by 4 and consider the quotient: _ _
3) Take the date: _ _
4) Take the month: _ _
5) Choose the code of the year as specified above: _
6) Add everything and divide by 7 and consider the remainder the result will be from 0 to 7(any one number).
Match with the day that will be the result.
Ayaan Chaudhary said:
6 years ago
I am unable to understand. This same question is in fitjee entrance exam.
Dabir said:
6 years ago
28 means 28/7... It means 0.
May code is 1.
Year 6.
Leap year 1.
Century code is. 6.
Therefore 0+1+6+1+6= 14/7. The remainder is 0.
0 is the code of Sunday.
May code is 1.
Year 6.
Leap year 1.
Century code is. 6.
Therefore 0+1+6+1+6= 14/7. The remainder is 0.
0 is the code of Sunday.
Raj sharma said:
5 years ago
Learn that every 400 years odd days will be zero.
Akshay Chavda said:
5 years ago
Day --> +28
month code --> +2
year--> + 6
yr/4 --> +1
-----
37/7 = 2 odd days - 1 =1 .
It is Sunday.
month code --> +2
year--> + 6
yr/4 --> +1
-----
37/7 = 2 odd days - 1 =1 .
It is Sunday.
Sanjana said:
5 years ago
Why are 400 and 1600 yrs taken, why not other years? Please anyone explain me.
Narendra said:
5 years ago
How to take 400, 1600? Please anyone explain me.
Divya said:
5 years ago
I can't get this question. Please explain easily.
(1)
Mohanravi Pinaprolu said:
5 years ago
How to find out the odd days? Please explain.
(3)
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