Aptitude - Calendar - Discussion
Discussion Forum : Calendar - General Questions (Q.No. 2)
2.
What was the day of the week on 28th May, 2006?
Answer: Option
Explanation:
28 May, 2006 = (2005 years + Period from 1.1.2006 to 28.5.2006)
Odd days in 1600 years = 0
Odd days in 400 years = 0
5 years = (4 ordinary years + 1 leap year) = (4 x 1 + 1 x 2) 
6 odd days
Jan. Feb. March April May (31 + 28 + 31 + 30 + 28 ) = 148 days
148 days = (21 weeks + 1 day) 1 odd day.
Total number of odd days = (0 + 0 + 6 + 1) = 7 0 odd day.
Given day is Sunday.
Discussion:
214 comments Page 20 of 22.
Divya said:
1 decade ago
Well explained Senthil
Senthil said:
1 decade ago
The number of days more than the complete weeks are called ODD DAYS....
In 400,1600,2000 odd days are zero...
****************************************************************
Day of the week on 28th may 2006,
In 2006,
Jan 31days+Feb 28days+Mar 31days+Apr 30days+May 28days[bcz 28th may]= 148days [totally]
To find odd day,
148/7=21quotient 1remainder
so 21complete weeks and 1 odd day in 2006
****************************************************************
For 5years [2001-2005],
To find leap year,
5/4=1 [never take the decimal points]
1leap year
So 2odd days in that year[366/7=52weeks+2odd days]
And rest of the 4years have 4odd days[365/7=52weeks+1odd day]
so for 5years,
2+4=6odd days
****************************************************************
Total number of odd days,
0+0+1+6=7
So, 7/7=1complete week
There is zero odd day in it.
0-Sunday
1-Monday
2-Tuesday
3-Wednesday
4-Thursday
5-Friday
6-Saturday
So 28th may 2006 is Sunday....:)
In 400,1600,2000 odd days are zero...
****************************************************************
Day of the week on 28th may 2006,
In 2006,
Jan 31days+Feb 28days+Mar 31days+Apr 30days+May 28days[bcz 28th may]= 148days [totally]
To find odd day,
148/7=21quotient 1remainder
so 21complete weeks and 1 odd day in 2006
****************************************************************
For 5years [2001-2005],
To find leap year,
5/4=1 [never take the decimal points]
1leap year
So 2odd days in that year[366/7=52weeks+2odd days]
And rest of the 4years have 4odd days[365/7=52weeks+1odd day]
so for 5years,
2+4=6odd days
****************************************************************
Total number of odd days,
0+0+1+6=7
So, 7/7=1complete week
There is zero odd day in it.
0-Sunday
1-Monday
2-Tuesday
3-Wednesday
4-Thursday
5-Friday
6-Saturday
So 28th may 2006 is Sunday....:)
M.Vamshi said:
1 decade ago
Is there any easiest method to calculate day plz i cant understood the odd day or even day
Hemlatasharma said:
1 decade ago
What is the odd day please explain briefly.
Snehal said:
1 decade ago
What is this odd day?
Can you explain it to me?
Can you explain it to me?
Ansari said:
1 decade ago
@arun i cant get it pls explain it brief...
Geetha said:
1 decade ago
Can you explain it briefly.
Arun Anoop M said:
1 decade ago
What was the day of the week on 28th May, 2006?
Leave 1600,400
it's odd day is zero
----
5=(5/4)leap yr+[5-1]ordinary day
=1 leap year+4 ordinary day
=1*2+4
=6 odd day
---------
Jan Feb Mar Apr May
31 28 31 30 28 ->total->148days->21weeks+1odd day
->1 odd day
Total=0+0+6+1
=7 odd day
Sun Mon Tue Wed Thu Fri Sat
0 1 2 3 4 5 6
7
Day is Sunday.
By Arun Anoop M,MTech IT,Kalasalingam University,TamilNadu.
Leave 1600,400
it's odd day is zero
----
5=(5/4)leap yr+[5-1]ordinary day
=1 leap year+4 ordinary day
=1*2+4
=6 odd day
---------
Jan Feb Mar Apr May
31 28 31 30 28 ->total->148days->21weeks+1odd day
->1 odd day
Total=0+0+6+1
=7 odd day
Sun Mon Tue Wed Thu Fri Sat
0 1 2 3 4 5 6
7
Day is Sunday.
By Arun Anoop M,MTech IT,Kalasalingam University,TamilNadu.
Sachin said:
1 decade ago
Why we write 1600 and 400 odd days here?
Ellappan.v said:
1 decade ago
Why odd days for 1600 and 400 are zero
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