Aptitude - Calendar - Discussion

As per the video that I saw on you tube regarding calendar. From freshers world channel. As per the concept/tricks.

1). Take last 2 digits of year
2). Divide this last 2 digits by 4 and consider the quotient.
3). Take the date of the question for which day is to be calculated
4). Month code of may is 1
[ Similarly as per trick code for various months is : J-0,F-3,M-3,A-6,M-1,J-2,J-6,A-1,S-5,O-0,N-3,D-5]
5). Now take year code as 2006 falls between the year 2000-2099 it's code is 6.
[Similarly for various years range code is:
1600-1699 : 6
1700-1799 : 4
1800-1899 : 2
1900-1999 : 0
2000-2099 : 6]

Now add sum of all these values and divide by 7. As we have to calculate day. Consider the reminder. ie, 06 + 0 + 28 + 1 + 6 means add 06 + 00 + 28 + 01 + 06 = 41.

41/7 = 6 (reminder).

Days code is : S-0,M-1,T-2,W-3,T-4,F-5,S-6
The answer is 6 th day of the week is Saturday. On 28 th May 2006 it was Saturday. Not Sunday.

According to me, the simplest way of solution is;

Months - 1440, 2305, 6146

Here, 1 = January, 4 = February, 4 = March, 0= April, May = 2, June = 3, July = 0, August = 5, September = 6, October = 1, November = 4, December = 6.

Learn this table along with the nos of their respective months.

Now come to days, For Days Remember:
1 - Sunday.
2- Monday.
3- Tuesday.
4- Wednesday.
5 - Thursday.
6- Friday .
0 or no remainder = Saturday.

Now come to century part

Remember the small table and understand the concept as to how we can calculate the no that needs to be assigned to a Century.

The No for 2000 Century must be 6, If we go before we need to again Start the chains or simply started from 6 till you reach 6 no.

For Calculating no, after 2000 century like 2100, 2200 just Substract by 2 until you reach 0

Let's see the below example, to go back century just set the 0,2,4, 6 in increasing order and to go after 2000 century just reduce the no by 2.

In below example 2000 is our base.

1600 - 6
1700 - 4
1800- 2
1900 - 0
2000 - 6
2001 - 4
2002 - 2
2003 - 0

And so on

Now come to the question, it Will hardly take 5 to 10 seconds to solve this qsn now, Just learn the above 3 tables

The question is 28 May 2006

Here write in the following manner

28 - Date.
2 - Month(See no assigned in table),
06 - Year(write last 2 digits of year),
6 - Century(2000),
1 - (Divide last 2 digits by 4).

Add on these nos - 43.

Now Divide 43 by 7 and the remainder would be = 1.

Now see the day's table, where 1 = Sunday.
Hence the answer is Sunday.

HERE AS IT IS GIVEN 28 MAY 2006.


28+ 1(CODE OF MAY) +06(LAST TWO DIGITS OF 2006)+06/4=(1),
SO 28+1+6+1 =36 then divide it by 7 for odd days,
36/7 = 1 is reminder.

So according to days
0 - SUNDAY
1 - MONDAY
2 - TUESDAY
3 - WEDNESDAY
4 - THURSDAY
5 - FRIDAY
6 - SATURDAY
7 - SUNDAY.

Here 1 is answer, So MONDAY (But) as 2006 is a leap year - 1 DAY SO (MONDAY - 1 = SUNDAY).

That's it. Thanks.

For all those who have confusion in this:

We calculate the years from 0 till 2005 so we split 2000 into 400 and 1600 and its odd day is 0, now left from 2000 to 2005 (5 yrs) = 4 ordinary years and 1 leap year = 4*1 + 2*1 = 6 the remainings.

I hope you all get it.

How to find out the odd days? Please explain.

I can't get this question. Please explain easily.

How to take 400, 1600? Please anyone explain me.

Why are 400 and 1600 yrs taken, why not other years? Please anyone explain me.

Day --> +28
month code --> +2
year--> + 6
yr/4 --> +1
-----
37/7 = 2 odd days - 1 =1 .

It is Sunday.

Learn that every 400 years odd days will be zero.