Aptitude - Calendar - Discussion

Discussion Forum : Calendar - General Questions (Q.No. 2)
2.
What was the day of the week on 28th May, 2006?
Thursday
Friday
Saturday
Sunday
Answer: Option
Explanation:

28 May, 2006 = (2005 years + Period from 1.1.2006 to 28.5.2006)

Odd days in 1600 years = 0

Odd days in 400 years = 0

5 years = (4 ordinary years + 1 leap year) = (4 x 1 + 1 x 2) 6 odd days

Jan.  Feb.   March    April    May 
(31 +  28  +  31   +   30   +   28 ) = 148 days

148 days = (21 weeks + 1 day) 1 odd day.

Total number of odd days = (0 + 0 + 6 + 1) = 7 0 odd day.

Given day is Sunday.

Discussion:
214 comments Page 18 of 22.

Effortless said:   7 years ago
If It is like that, Can anybody tell me what was the day on 1 Jan 1601 ?

When I calculate;

The 1600 year will have 0 odd days ( as it says 400 years has 0 odd days )
1 Jan i.e 1 odd day.
Total odd days till 1 Jan 1601 =1 odd day.
I.e. Monday ( As formula says 0 - Sunday, 1 - Monday ).

But the Actual day on 1 Jan 1601 was Thursday.

So, please explain me to get the solution.

Vishnu said:   7 years ago
What was the day of the week on 28th August 2016?

Please explain by this method.

Shashank said:   7 years ago
100 years = 76 ordinary years + 24 leap years (is it not 25 leap years).

Sugu said:   7 years ago
@Deena.

Thank you a lot.

Tony said:   7 years ago
Why not we take no of odd days in 2000 is 0? Anyone explain me.

Jhon said:   7 years ago
Why not adding 800 to 1600 and calculate it up to 2004?

Bikram said:   6 years ago
Is 2000 Leap year or ordinary year?

Bikram said:   6 years ago
The Correct answer is Monday.

Pushpa said:   6 years ago
Thanks for the answer.

Pushpa said:   6 years ago
Thanks @Bikramdevgan.


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