Aptitude - Calendar - Discussion

If in the last step I get "6" which day I consider, because you don't give no week day for "6".

Simple solution here is the trick. Just need to follow this step, guys this type of questions is very easy. But you.

Need to be perfect while solving.

First of all.

Month code.

Jan - 1.
Feb - 4.
Mar - 4.
Apr - 0.
May - 2.
June - 5.
July - 0.
August - 3.
September - 6.
October - 1.
November - 4.
December - 6.

Day code:

Sun - 1.
Mon - 2.
Tues - 4.
Wed - 5.
Thur - 7.
Fri - 8.
Sat - no decimal.

Now lets solve one example.

Example :- My DOB is 15th august 1989.

Step 1 - Take the last two digit of your birth year. Here in my case it is ' 89 '.

Step 2 - Now multiply the last two digit of birth year by "5".

89 x 5 = 445.

Step 3 - Now divide the result by "4".

445/4 = 111.25.

Step 4 - in this step remove the part of the result after decimal (RHS).

111.25 - remove 25.

Now we are having 111.

Step 5 - Now add the month code given above to this.

Month code for august is '3'.

So after adding.

3 + 111 = 114.

Step 6 - Now add the date of your birth. To this.

114 + 15 (15th august) = 129.

Step 7 - Don't worry this is the last step. ;-) ;-) ha ha.

Now finally divide this by '7'.

129/7 = 18.428.

Now we have got the final answer 18.428.

Now very important thing to remember. You have to look.

Upon the next digit after the decimal (right hand side).

In 18.428 the digit after the decimal is '4'.

Now go to the day code given above and see there '4' is for Tuesday. So answer is Tuesday.

15th august 1989 was a Tuesday.

Hope you all have understood this trick.

Note :- 1) I f in the " step 7 " you get no decimal than it is definitely " Saturday ". (see the day code column I have Already mentioned there " Saturday - no decimal ").

2) what to do if the date given is from leap year. Do the all step as it is, just.

Consider the earlier day.

Ex:- If at the last step you get " Friday " then Thursday will be your answer.

That's it. Just practice this steps you'll be perfect. Hope you all like this.

Please explain one example with simple method?

I can't understand this problem. Please explain in simple. What is the odd no?

@Dechen.

Hi.

28th may 2006.

So we need to calculate form.

1 jan 0001st year to 28th may 2006th year.

First 1600th yr dont have odd days rite means 1600/4 = 0 odd day.
400/4 = 0 odd day.

So we reach 1st jan 2000th year ok. Now 2001, 2002,.... 2006 28th may.

@Dechen.

Simply we need to come till 2006 so,

Means 1600+400 = 2000.

Then remaining 2001, 2002, ....2006.

Kindly can anyone of you share me why is odd day 1600 and 400 is taking in this problem please. I would be very grateful for your response :).

What was the day of the week on 28th May, 2006?
Here is d ? right.

Okay,

Need to calculate 28th May, 2006 rite,
(Please refer important formulas first okay :))

Now 1600 years have 0 odd days because 1600/4= No reminder(we can divide 4 completely in 1600).

Now 400 years have 0 odd days because 400/4= No reminder(we can divide 4 completely in 400).

You confused here right.. okay see 1600+400=2000 so we came till 2000th year we need to calculate for 6 more years to reach 2006. Question is 2006 may right, so calculate till 2005 so 5 more years can calculate now okay then will calculate remaining days in 2006 okay.

So,

2001= its ordinary year so have 54 weeks and 1 odd day as per formula right
2002= its ordinary year so have 54 weeks and 1 odd day as per formula right.
2003= its ordinary year so have 54 weeks and 1 odd day as per formula right.
2004= 54 weeks and 2 odd day.
2005= its ordinary year so have 54 weeks and 1 odd day as per formula right.

1+1+1+2+1=6.
So total=6 odd days.

Now one more year which is 2006, here till 28th may needed so,

jan feb mar apr may
31 28 31 30 28th may ok.

31+28+31+30+28= 148 total days.

So calculate how many weeks and odd days in 148.

For this 148/7= 28 and reminder (1).
So 21 week and (1) odd day.

Add this(1) with (6) odd days that we calculate before of

So total 7 odd days now finish see.

1 2 3 4 5 6 7or(0)
Mo Tu We Th Fr Sat Sun

Total 7 odd days so 7th value OK... for example we got 5 odd days means answer will be Fri OK.

Here Sunday Enjoy :).

Can someone please explain 'mathematically' the solution for this problem and not by codes. Thanks in advance.

Total number of odd days = (0 + 0 + 6 + 1) = 7 0 odd day.

I don't get this step could anyone help me?