Aptitude - Calendar - Discussion
Discussion Forum : Calendar - General Questions (Q.No. 2)
2.
What was the day of the week on 28th May, 2006?
Answer: Option
Explanation:
28 May, 2006 = (2005 years + Period from 1.1.2006 to 28.5.2006)
Odd days in 1600 years = 0
Odd days in 400 years = 0
5 years = (4 ordinary years + 1 leap year) = (4 x 1 + 1 x 2) 
6 odd days
Jan. Feb. March April May (31 + 28 + 31 + 30 + 28 ) = 148 days
148 days = (21 weeks + 1 day) 1 odd day.
Total number of odd days = (0 + 0 + 6 + 1) = 7 0 odd day.
Given day is Sunday.
Discussion:
214 comments Page 13 of 22.
Ram Dafale @PRMIT said:
10 years ago
Use doomsday method to get faster result.
Shubham said:
10 years ago
By, doomsday method:
= Tuesday+(06/12)+rem(06/12)+rem(06/12)/4.
= Tuesday+0+0+0 means on 4th April Tuesday.
From 4th April to 28th may = 55 days = remain 6 odd days.
= Tuesday+6 = Sunday.
= Tuesday+(06/12)+rem(06/12)+rem(06/12)/4.
= Tuesday+0+0+0 means on 4th April Tuesday.
From 4th April to 28th may = 55 days = remain 6 odd days.
= Tuesday+6 = Sunday.
Vivek said:
10 years ago
Lets see that 2000 was a leap year so 1, 2, 3, 5 is non leap year and 2004 is leap year. So counting from 2001, to 5 there will be 6 odd day 1 for each non leap and 2 for 1 leap year next see in 2006 January has 31 day means 3 odd day (31/7), February has 0 (28/7), March has 3, April has 2, and for 28 in May 0 odd days.
So means total 8 days in 2006 means 1 week 1 day hence we total left of 1 odd day. From 2001 to 5 we have 6 odd and 1 in 2006 total 7. So 1 week again so starting day Sunday is answer.
So means total 8 days in 2006 means 1 week 1 day hence we total left of 1 odd day. From 2001 to 5 we have 6 odd and 1 in 2006 total 7. So 1 week again so starting day Sunday is answer.
MANOJ said:
9 years ago
What's that thing that once a year twice a week for four months and a day is 6 times?
Bharathi said:
9 years ago
Please help me guys. First how to find odd & even no in the month & year. Then say how to solve this kind of problems?
Pratik said:
9 years ago
How can be taken as a feb as 28 day or 29 days please explain me?
Moumita said:
9 years ago
Why we taken 0 as Sunday please help me any one?
Sajan said:
9 years ago
Hi, @Moumita.
It is in the series of:
0 => Sunday.
1 => Monday.
2 => Tuesday.
3 => Wednesday.
4 => Thursday.
5 => Friday.
6 => Saturday.
So, we taken 0 as Sunday.
It is in the series of:
0 => Sunday.
1 => Monday.
2 => Tuesday.
3 => Wednesday.
4 => Thursday.
5 => Friday.
6 => Saturday.
So, we taken 0 as Sunday.
Ahmef said:
9 years ago
Hi @Deena.
Your explanation is the best method to solve the calendar problem.
Your explanation is the best method to solve the calendar problem.
Kannaiah said:
9 years ago
MONTH CODE.
J F M A M J J A S O N D
1 4 4 0 2 5 0 3 6 1 4 6
YEAR CODE = 2006 - 6.
Sun = 1. Mon = 2. T = 3. W = 4. Thurs = 5.Fri = 6.Sat = 7 or 0.
28/5/2006.
D + M + Y + Leap year + Cc.
28 + 2 + 6 + 1 + 6 = 43.
43/7 = Q = 6, Re = 1.
SUNDAY = 1.
J F M A M J J A S O N D
1 4 4 0 2 5 0 3 6 1 4 6
YEAR CODE = 2006 - 6.
Sun = 1. Mon = 2. T = 3. W = 4. Thurs = 5.Fri = 6.Sat = 7 or 0.
28/5/2006.
D + M + Y + Leap year + Cc.
28 + 2 + 6 + 1 + 6 = 43.
43/7 = Q = 6, Re = 1.
SUNDAY = 1.
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