Aptitude - Calendar - Discussion
Discussion Forum : Calendar - General Questions (Q.No. 2)
2.
What was the day of the week on 28th May, 2006?
Answer: Option
Explanation:
28 May, 2006 = (2005 years + Period from 1.1.2006 to 28.5.2006)
Odd days in 1600 years = 0
Odd days in 400 years = 0
5 years = (4 ordinary years + 1 leap year) = (4 x 1 + 1 x 2)
6 odd days
Jan. Feb. March April May (31 + 28 + 31 + 30 + 28 ) = 148 days
148 days = (21 weeks + 1 day)
1 odd day.
Total number of odd days = (0 + 0 + 6 + 1) = 7
0 odd day.
Given day is Sunday.
Discussion:
215 comments Page 12 of 22.
Kasinath @Hyd said:
1 decade ago
From 2006,
2000 is a Factor 0f 400 hence it is a leap year and has 0 odd days.
Remaining 6 years has 5 ordinary and 1 leap year i.e.,(4th year).
=> 5*1 + 1*2 + 28(from MAY) = 35 days.
35/7 = 5 weeks + 0 odd days.
0th odd day = Sunday.
2000 is a Factor 0f 400 hence it is a leap year and has 0 odd days.
Remaining 6 years has 5 ordinary and 1 leap year i.e.,(4th year).
=> 5*1 + 1*2 + 28(from MAY) = 35 days.
35/7 = 5 weeks + 0 odd days.
0th odd day = Sunday.
Jannet said:
1 decade ago
Year Odd days.
1600 0
1700 5
1900 3
2000 5
2005 6
2006 3
Total 22 = Sunday
Explanation:
1700-1600=100 in 100 yrs 5 odd days.
1900-1700=200 in 200 yrs 3 odd days.
2000-1900=100 in 100 yrs 5 odd days.
Leap year calculation 2000-2005.
(1+1+1+2+1) 2000 non leap yr so add one 2004 leap yr so I have added 2.
2006 odd day calculation.
Jan 3 odd day(31/7= 28 rem 3,so take that three).
Feb 1 odd day(since leap year)(if non leap yr put 0).
March 3 odd day.
Apr 2 odd day.
May 0(since leap yr).
Tot 10(10/7=1 rem 3).
So 3 odd days in 2006.
1600 0
1700 5
1900 3
2000 5
2005 6
2006 3
Total 22 = Sunday
Explanation:
1700-1600=100 in 100 yrs 5 odd days.
1900-1700=200 in 200 yrs 3 odd days.
2000-1900=100 in 100 yrs 5 odd days.
Leap year calculation 2000-2005.
(1+1+1+2+1) 2000 non leap yr so add one 2004 leap yr so I have added 2.
2006 odd day calculation.
Jan 3 odd day(31/7= 28 rem 3,so take that three).
Feb 1 odd day(since leap year)(if non leap yr put 0).
March 3 odd day.
Apr 2 odd day.
May 0(since leap yr).
Tot 10(10/7=1 rem 3).
So 3 odd days in 2006.
Ragi Akhil said:
1 decade ago
We have to calculate odd days till 2006 may 28. So it will be time taking process. So for simplifying the calculation process first we will find out the odd days till the year 2000. Odd days in 2000 years is 0. And after that we have to find out the odd days from 2001 to 2006 may 28.
Varun said:
1 decade ago
Is it @Rakhi's method is applicable for 17th june 1998
Shiva kumar said:
1 decade ago
Why are you taking nearest leaf year as 2000, 2004 is also leap year right?
Why don't you take 2004 as nearest leap year? Explain please.
Why don't you take 2004 as nearest leap year? Explain please.
Sasank said:
1 decade ago
What does this statement 0+0+6+1 means?
Justin said:
1 decade ago
@Harish:
2000, 2004, 2008 etc are leap year...2000/4 completely divisible...
These are having 366 days = 2 odd day..
Why because 366/7 = 52.1211 so 52 week = 364 days + 2(odd) extra days.
In-case of non leap year 365 days = 1 odd day.
2000, 2004, 2008 etc are leap year...2000/4 completely divisible...
These are having 366 days = 2 odd day..
Why because 366/7 = 52.1211 so 52 week = 364 days + 2(odd) extra days.
In-case of non leap year 365 days = 1 odd day.
Sruti said:
1 decade ago
What does this statement 0+0+6+1 means?
Harish said:
1 decade ago
Which year is exactly divided by 4 called as leap year?
Vishnupriya said:
1 decade ago
@Gopi.
A leap year is always divisible by 4(if it is not a century).
Eg: 2004, 1676.
And every fourth century is a leap year.
Eg: 400, 800, 1200.
But 1800 is not a leap year.
A leap year is always divisible by 4(if it is not a century).
Eg: 2004, 1676.
And every fourth century is a leap year.
Eg: 400, 800, 1200.
But 1800 is not a leap year.
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