Aptitude - Calendar - Discussion

Year Odd days.
1600 0
1700 5
1900 3
2000 5
2005 6
2006 3

Total 22 = Sunday

Explanation:

1700-1600=100 in 100 yrs 5 odd days.
1900-1700=200 in 200 yrs 3 odd days.
2000-1900=100 in 100 yrs 5 odd days.

Leap year calculation 2000-2005.
(1+1+1+2+1) 2000 non leap yr so add one 2004 leap yr so I have added 2.

2006 odd day calculation.

Jan 3 odd day(31/7= 28 rem 3,so take that three).
Feb 1 odd day(since leap year)(if non leap yr put 0).
March 3 odd day.
Apr 2 odd day.
May 0(since leap yr).

Tot 10(10/7=1 rem 3).

So 3 odd days in 2006.

We have to calculate odd days till 2006 may 28. So it will be time taking process. So for simplifying the calculation process first we will find out the odd days till the year 2000. Odd days in 2000 years is 0. And after that we have to find out the odd days from 2001 to 2006 may 28.

Is it @Rakhi's method is applicable for 17th june 1998

Why are you taking nearest leaf year as 2000, 2004 is also leap year right?

Why don't you take 2004 as nearest leap year? Explain please.

What does this statement 0+0+6+1 means?

@Harish:

2000, 2004, 2008 etc are leap year...2000/4 completely divisible...

These are having 366 days = 2 odd day..

Why because 366/7 = 52.1211 so 52 week = 364 days + 2(odd) extra days.

In-case of non leap year 365 days = 1 odd day.

What does this statement 0+0+6+1 means?

Which year is exactly divided by 4 called as leap year?

@Gopi.

A leap year is always divisible by 4(if it is not a century).

Eg: 2004, 1676.
And every fourth century is a leap year.

Eg: 400, 800, 1200.

But 1800 is not a leap year.

How to find number of leap years and ordinary years within a given number of years?

For example, in 100 years, 24 leap and 76 ordinary years.

How to find this?