Aptitude - Calendar - Discussion
Discussion Forum : Calendar - General Questions (Q.No. 3)
3.
What was the day of the week on 17th June, 1998?
Answer: Option
Explanation:
17th June, 1998 = (1997 years + Period from 1.1.1998 to 17.6.1998)
Odd days in 1600 years = 0
Odd days in 300 years = (5 x 3) 
1
97 years has 24 leap years + 73 ordinary years.
Number of odd days in 97 years ( 24 x 2 + 73) = 121 = 2 odd days.
Jan. Feb. March April May June (31 + 28 + 31 + 30 + 31 + 17) = 168 days
168 days = 24 weeks = 0 odd day.
Total number of odd days = (0 + 1 + 2 + 0) = 3.
Given day is Wednesday.
Discussion:
165 comments Page 9 of 17.
Deepak said:
1 decade ago
How to calculate odd day in 1600 years?
MaheshMydo said:
1 decade ago
How did you arrive at MONTH CODES?
Prince said:
1 decade ago
We can solve this problem by going back from 2000 to 17 June 1998.
= 2000-2 odd days (leap year).
= 1999-1 odd day.
= 1988 (197 days i.e 1 odd day) (31 dec+30 nov. 17 june).
Total 4 odd days.
Since we have reversely calculated it.
Sat, Fri, Thurs, Wed.
= 2000-2 odd days (leap year).
= 1999-1 odd day.
= 1988 (197 days i.e 1 odd day) (31 dec+30 nov. 17 june).
Total 4 odd days.
Since we have reversely calculated it.
Sat, Fri, Thurs, Wed.
John said:
1 decade ago
@Mickey.
Now divide 144 by 7.
We'll get quotient = 20 and remainder = 4.
So 4th day is Wednesday.
Here remainder is wrong. We will get it as 5.
How you get remainder as 4?
Now divide 144 by 7.
We'll get quotient = 20 and remainder = 4.
So 4th day is Wednesday.
Here remainder is wrong. We will get it as 5.
How you get remainder as 4?
Monu said:
1 decade ago
If 15 august 1993 is Friday then what would be the day of 6th march of same year? Anybody please answer this.
Kavya said:
1 decade ago
Is there any shortcut? Its very complicated, confusing, odd days, why there is a need to take 1600, 400, it will take more time in competitive exams. Please tell easy way to solve if have.
Mamta said:
1 decade ago
Can anybody explain me? I can't understand.
Prateek said:
1 decade ago
How come 100 years have 76 ordinary and 24 lap years ? And how it is calculated for any number of years?
Saikumar said:
1 decade ago
Formula = (Date+No of normal year+No of leap year+Month code+Century code)/7.
(17+98+24+4+0)/7 = 143/7.
And remainder is 3 code of week is Wednesday.
(17+98+24+4+0)/7 = 143/7.
And remainder is 3 code of week is Wednesday.
Santhosh said:
1 decade ago
How to calculate number of odd days for 2008, 2009, 2010?
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers