Aptitude - Calendar - Discussion
Discussion Forum : Calendar - General Questions (Q.No. 3)
3.
What was the day of the week on 17th June, 1998?
Answer: Option
Explanation:
17th June, 1998 = (1997 years + Period from 1.1.1998 to 17.6.1998)
Odd days in 1600 years = 0
Odd days in 300 years = (5 x 3) 
1
97 years has 24 leap years + 73 ordinary years.
Number of odd days in 97 years ( 24 x 2 + 73) = 121 = 2 odd days.
Jan. Feb. March April May June (31 + 28 + 31 + 30 + 31 + 17) = 168 days
168 days = 24 weeks = 0 odd day.
Total number of odd days = (0 + 1 + 2 + 0) = 3.
Given day is Wednesday.
Discussion:
165 comments Page 7 of 17.
Vicky said:
1 decade ago
Leap year comes for every four years
The basic rule to know about leap year is that the year should be divisible by 4
For Eg: 4, 8, 12, 16, 20................100, 104 etc.,
Then here as per my knowldeged 25 leap years should exists for every 100 years.
why all are considering 24yrs in 100 years?
Need clarity on this.
The basic rule to know about leap year is that the year should be divisible by 4
For Eg: 4, 8, 12, 16, 20................100, 104 etc.,
Then here as per my knowldeged 25 leap years should exists for every 100 years.
why all are considering 24yrs in 100 years?
Need clarity on this.
Juhi said:
1 decade ago
According to my thinking:
97 years has 23 leap years not 24
because if in 100 years 24 leap years.
Then in this case from 1901 to 2000 the last one is leap is 2000, which we are not counting because we want to count from 1901 to 1997.
So please justify your answer.
97 years has 23 leap years not 24
because if in 100 years 24 leap years.
Then in this case from 1901 to 2000 the last one is leap is 2000, which we are not counting because we want to count from 1901 to 1997.
So please justify your answer.
Keya said:
1 decade ago
@Juhi.
The centuries divisible by 400, like 400, 800, 1200, 1600, 2000...etc have 25 leap year and 75 ordinary years.
In given question we have to calculate from 1900 to 1997 therefore.
1998 - ordinary year.
1999 - ordinary year.
2000 - leap year.
So from 1901 to 1997 - ordinary years will be = 75-2 = 73.
And leap year will be = 25-1 = 24.
The centuries divisible by 400, like 400, 800, 1200, 1600, 2000...etc have 25 leap year and 75 ordinary years.
In given question we have to calculate from 1900 to 1997 therefore.
1998 - ordinary year.
1999 - ordinary year.
2000 - leap year.
So from 1901 to 1997 - ordinary years will be = 75-2 = 73.
And leap year will be = 25-1 = 24.
Priya singh said:
1 decade ago
300 years 5*3 = 15 odd days.
What is 5 and 3. Please tell me ?
What is 5 and 3. Please tell me ?
Abhi said:
1 decade ago
Guys, Could help me, what would be the day on 13th-july-1992 ?
Need answer with procedure. Please?
Need answer with procedure. Please?
Goms said:
1 decade ago
The basic rule to know about leap year is that the year should be divisible by 4.
For Eg: 4, 8, 12, 16, 20................100, 104 etc.,
Then here as per my knowledged 25 leap years should exists for every 100 years.
why all are considering 24 yrs in 100 years?
For Eg: 4, 8, 12, 16, 20................100, 104 etc.,
Then here as per my knowledged 25 leap years should exists for every 100 years.
why all are considering 24 yrs in 100 years?
Vikram said:
1 decade ago
Month codes:
Jan- 1, Feb- 4, Mar- 4, Apr- 0, May- 2, June- 5.
July- 0, Aug- 3, Sep- 6, Oct- 1, Nov- 4, Dec- 6.
Year codes:
1500-99: 0
1600-99: 6
1700-99: 4
1800-99: 2
1900-99: 0
:
:
:
So on.......
Day codes:
Sat- 0, Sun- 1, Mon- 2, Tue- 3, Wed- 4, Thu- 5, Fri- 6.
Here,
17+05+98+24+00 = 144.
144/7 = 20+ 4 days.
Which is wednesday
Jan- 1, Feb- 4, Mar- 4, Apr- 0, May- 2, June- 5.
July- 0, Aug- 3, Sep- 6, Oct- 1, Nov- 4, Dec- 6.
Year codes:
1500-99: 0
1600-99: 6
1700-99: 4
1800-99: 2
1900-99: 0
:
:
:
So on.......
Day codes:
Sat- 0, Sun- 1, Mon- 2, Tue- 3, Wed- 4, Thu- 5, Fri- 6.
Here,
17+05+98+24+00 = 144.
144/7 = 20+ 4 days.
Which is wednesday
Ravi said:
1 decade ago
Why you taken 300 years ? why not 400 years please explain in detail.
Naresh said:
1 decade ago
Hello Everyone.
The simple answer is:
1996+2 = 1996(leap year)+1 ordinary year+Jan to june 17th.
= 2 odd days +1 odd day+168 days.
= 2+1+0 odd days.
= 3 odd days.
i.e Wednesday.
The simple answer is:
1996+2 = 1996(leap year)+1 ordinary year+Jan to june 17th.
= 2 odd days +1 odd day+168 days.
= 2+1+0 odd days.
= 3 odd days.
i.e Wednesday.
Vishnu said:
1 decade ago
The question is what is day of 17 june 1998?
If the year is 1998 that is mean in 100 year gets total 25 leap years if getting 25 leap in 100 year then why using 24 leap year in above comments.
Calculating leap year.
On every 4 years gets 1 leap year.
1901 to 1904 = 1 leap year.
1905 to 1908 = 1 leap year ....
Calculating odd days
I am calculating odd days from 1 jan to 17 june 1998
in jan = 31 days
feb = 28 days
march = 31 days
april = 30 days
may = 31 days
june = 17 days
------
168 days
Dividing by 7 to 168 days (7 mean 7 days in week).
168/7= 24 = 24 weeks + 0 odd days (there is any more days).
If eg., 170 /7 = 24 weeks + 2 odd days.
Only this not understood.
In above discuss why used 1900, 300, 400.
If the year is 1998.
We should have take in 1998 years.
1901 to 2000 years = total 100 years.
1901 to 1997 years = 97 years.
24 leap year + 52 weeks + 1 odd days.
If the year is 1998 that is mean in 100 year gets total 25 leap years if getting 25 leap in 100 year then why using 24 leap year in above comments.
Calculating leap year.
On every 4 years gets 1 leap year.
1901 to 1904 = 1 leap year.
1905 to 1908 = 1 leap year ....
Calculating odd days
I am calculating odd days from 1 jan to 17 june 1998
in jan = 31 days
feb = 28 days
march = 31 days
april = 30 days
may = 31 days
june = 17 days
------
168 days
Dividing by 7 to 168 days (7 mean 7 days in week).
168/7= 24 = 24 weeks + 0 odd days (there is any more days).
If eg., 170 /7 = 24 weeks + 2 odd days.
Only this not understood.
In above discuss why used 1900, 300, 400.
If the year is 1998.
We should have take in 1998 years.
1901 to 2000 years = total 100 years.
1901 to 1997 years = 97 years.
24 leap year + 52 weeks + 1 odd days.
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