Aptitude - Calendar - Discussion
Discussion Forum : Calendar - General Questions (Q.No. 3)
3.
What was the day of the week on 17th June, 1998?
Answer: Option
Explanation:
17th June, 1998 = (1997 years + Period from 1.1.1998 to 17.6.1998)
Odd days in 1600 years = 0
Odd days in 300 years = (5 x 3) 
1
97 years has 24 leap years + 73 ordinary years.
Number of odd days in 97 years ( 24 x 2 + 73) = 121 = 2 odd days.
Jan. Feb. March April May June (31 + 28 + 31 + 30 + 31 + 17) = 168 days
168 days = 24 weeks = 0 odd day.
Total number of odd days = (0 + 1 + 2 + 0) = 3.
Given day is Wednesday.
Discussion:
165 comments Page 4 of 17.
Nitin said:
1 decade ago
How can I find no leap year in 97 year.
Aishu said:
1 decade ago
How to find the month code rajesh ?
Inshan said:
1 decade ago
Think it like this!!
Maybe year 0 A.D. is included as an ordinary year rather than as a leap year.
So,
2000 yrs = 499 leap years. (Year: 0 A.D. is be included.)
= 1501 ordinary years
But, 1997 yrs = 498 leap yrs
= 1499 ordinary years
(Year 1998 is not taken because it is of this year's day of 17th of June that we have to figure out.)
1.) Leap years = 366 days (per year)/ 7 = Remainder is 2. Therefore, 2 odd days for every leap year, i.e. to say,
Total odd days = 2 * 498 = 996 odd days
2.) Ordinary years = 365 days (per year)/7 = Remainder is 1. Therefore, 1 odd day for every ordinary year, i.e. to say,
Total odd days = 1 * 1499 = 1499 odd days.
Therefore, total odd days altogether = 2495 days / 7 = 3 odd days.
April and June, & September and November: 30 days each.
Rest of the month: 31 days.
So, for 17th June = 31+28+31+30+31+17 = 168/7 = 0 odd days.
Total odd days = 3 + 0 = 3 odd days.
If 3 odd days:
Start at Sun: Then, 1st is Mon, 2nd is Tues and 3rd is Wednesday.
Maybe year 0 A.D. is included as an ordinary year rather than as a leap year.
So,
2000 yrs = 499 leap years. (Year: 0 A.D. is be included.)
= 1501 ordinary years
But, 1997 yrs = 498 leap yrs
= 1499 ordinary years
(Year 1998 is not taken because it is of this year's day of 17th of June that we have to figure out.)
1.) Leap years = 366 days (per year)/ 7 = Remainder is 2. Therefore, 2 odd days for every leap year, i.e. to say,
Total odd days = 2 * 498 = 996 odd days
2.) Ordinary years = 365 days (per year)/7 = Remainder is 1. Therefore, 1 odd day for every ordinary year, i.e. to say,
Total odd days = 1 * 1499 = 1499 odd days.
Therefore, total odd days altogether = 2495 days / 7 = 3 odd days.
April and June, & September and November: 30 days each.
Rest of the month: 31 days.
So, for 17th June = 31+28+31+30+31+17 = 168/7 = 0 odd days.
Total odd days = 3 + 0 = 3 odd days.
If 3 odd days:
Start at Sun: Then, 1st is Mon, 2nd is Tues and 3rd is Wednesday.
Inshan said:
1 decade ago
Sorry for mistake!
What I said was that 0 A.D. is not included as either years!
But, I surmise that it is better to take into account every 100 yrs to understand such problems better.
For this, we need to figure out how many ordinary years and leap years are there altogether in a century (100 yrs). If we find this, we will go to heaven!!! :)))
What I said was that 0 A.D. is not included as either years!
But, I surmise that it is better to take into account every 100 yrs to understand such problems better.
For this, we need to figure out how many ordinary years and leap years are there altogether in a century (100 yrs). If we find this, we will go to heaven!!! :)))
C.Paththira Selvi said:
1 decade ago
How to calculate this sum?
Ranjith said:
1 decade ago
How could you tell that 1600 has 0 odd days?
Anupama said:
1 decade ago
Wy we are 300 years and why we are calculating odd days for 300 ?
Arya said:
1 decade ago
Counting of Odd Days:
1 ordinary year = 365 days = (52 weeks + 1 day.)
1 ordinary year has 1 odd day.
1 leap year = 366 days = (52 weeks + 2 days)
1 leap year has 2 odd days.
100 years = 76 ordinary years + 24 leap years
= (76 x 1 + 24 x 2) odd days = 124 odd days.
= (17 weeks + days) 5 odd days.
Number of odd days in 100 years = 5.
Number of odd days in 200 years = (5 x 2) 3 odd days.
Number of odd days in 300 years = (5 x 3) 1 odd day.
Number of odd days in 400 years = (5 x 4 + 1) 0 odd day.
1 ordinary year = 365 days = (52 weeks + 1 day.)
1 ordinary year has 1 odd day.
1 leap year = 366 days = (52 weeks + 2 days)
1 leap year has 2 odd days.
100 years = 76 ordinary years + 24 leap years
= (76 x 1 + 24 x 2) odd days = 124 odd days.
= (17 weeks + days) 5 odd days.
Number of odd days in 100 years = 5.
Number of odd days in 200 years = (5 x 2) 3 odd days.
Number of odd days in 300 years = (5 x 3) 1 odd day.
Number of odd days in 400 years = (5 x 4 + 1) 0 odd day.
Rinki said:
1 decade ago
Pls tell me ....why did you add 1 in the calculation of odd days in 400 years???
Vanita said:
1 decade ago
Number of odd days in 200 years = (5 x 2) 3 odd days.
Number of odd days in 300 years = (5 x 3) 1 odd day.
Number of odd days in 400 years = (5 x 4 + 1) 0 odd day.
Why, (Number of odd days in 400 years = (5 x 4 + 1) 0 odd day.) in this 1 is added ,
please clarify
Number of odd days in 300 years = (5 x 3) 1 odd day.
Number of odd days in 400 years = (5 x 4 + 1) 0 odd day.
Why, (Number of odd days in 400 years = (5 x 4 + 1) 0 odd day.) in this 1 is added ,
please clarify
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